Cells, Membranes & Exchange — Chapter Practice, Grade 10
Connect cell structures, membrane transport, and exchange with the needs of cells.
Problem 1
- All living things are made of one or more cells
- The cell is the basic unit of structure and function
- All cells arise from pre-existing cells
- All cells contain a nucleus
Answer and explanation
All cells contain a nucleus
Prokaryotic cells (like bacteria) have no nucleus, so 'all cells contain a nucleus' is false and is not part of cell theory.
Problem 2
- Its resolution limit (~200 nm) is far larger than a ribosome, so it cannot separate that fine detail no matter how much it magnifies
- Light microscopes cannot magnify past 100×
- Ribosomes are too large to fit in the field of view
- Light microscopes only work on living cells
Answer and explanation
Its resolution limit (~200 nm) is far larger than a ribosome, so it cannot separate that fine detail no matter how much it magnifies
Magnification and resolution are different. A light microscope's resolution stalls near 200 nm, so a 20 nm ribosome stays a blur; an electron microscope is needed.
Problem 3
Answer and explanation
400 ×
Total magnification = eyepiece × objective = 10 × 40 = 400×.
Problem 4
Answer and explanation
Cell theory's third tenet says cells only come from pre-existing cells. If life could arise spontaneously from non-living matter, that tenet would be false. Pasteur's swan-neck experiment showed sterile broth stayed lifeless until microbes reached it, confirming that cells come only from other cells.
Problem 5
- Robert Hooke
- Antonie van Leeuwenhoek
- Matthias Schleiden
- Louis Pasteur
Answer and explanation
Antonie van Leeuwenhoek
Leeuwenhoek's unusually powerful lenses let him observe living 'animalcules' in pond water in the 1670s.
Problem 6
Answer and explanation
About 50 μm if the printed image retains its stated scale.
Actual size=image size/magnification=25/500=0.05 mm.
Convert 0.05 mm to 50 μm.
Response criteria
- Use the stated conditions.
- Show the evidence or calculation.
- Explain the conclusion and any stated limitation.
Problem 7
Hints
An instrument extends observation but conclusions still require evidence.
Answer and explanation
It allowed structures and cell division to be observed and compared across organisms.
Problem 8
Hints
State what the supplied observations or conditions establish, and separate that from any assumption.
Answer and explanation
No. Sampling, preparation, focus and resolution can limit detection; inspect appropriate fields and controls.
Problem 9
Answer and explanation
The original image may lack sufficient resolution; resizing cannot recover detail that was never resolved. Use an appropriate method or independent evidence.
Magnification is enlargement of an image. Resolution is the ability to distinguish nearby features as separate under the imaging conditions. A larger blurry spot can still hide two structures. Contrast, preparation, staining and artifacts also influence what can be seen. Light and electron imaging have different capacities and preparation requirements; neither one automatically shows every structure alive and unchanged. Before identifying an organelle, ask whether the feature is resolved, labeled with scale and supported by appropriate observations rather than a familiar-looking blob.
The original image may lack sufficient resolution; resizing cannot recover detail that was never resolved. Use an appropriate method or independent evidence.
Response criteria
- Read the structures, axes, directions and units correctly.
- Connect the evidence with the biological mechanism.
- Respect stated model assumptions and distinguish an observation from a further inference.
Problem 10
Answer and explanation
The estimate is 2.4×25 = 60 μm. A magnification label describes a particular display enlargement; resizing changes it, while an image and scale bar resized together preserve the specimen-length ratio.
The estimate is 2.4×25 = 60 μm. A magnification label describes a particular display enlargement; resizing changes it, while an image and scale bar resized together preserve the specimen-length ratio.
Response criteria
- Use the stated measurements or conditions, with correct units.
- Connect the result to the biological mechanism or evidence relationship.
- Identify the assumption, model limit or further evidence requested.
Problem 11
- A cell membrane
- Ribosomes
- A membrane-bound nucleus
- DNA
Answer and explanation
A membrane-bound nucleus
Prokaryotes have DNA, ribosomes, and a cell membrane, but they lack a true membrane-bound nucleus — that is the defining eukaryotic feature.
Problem 12
- Mitochondrion
- Ribosome
- Nucleus
- Golgi apparatus
Answer and explanation
Golgi apparatus
The Golgi apparatus is the cell's shipping department, tagging and packaging proteins into vesicles addressed to their destinations.
Problem 13
- It is studded with ribosomes that build and process proteins
- It has a jagged outer wall
- It stores rough, undigested food
- It contains chloroplasts
Answer and explanation
It is studded with ribosomes that build and process proteins
Ribosomes attached to its surface give the rough ER its bumpy look and its role in processing newly made proteins.
Problem 14
Answer and explanation
Mitochondria have their own circular DNA separate from the nucleus, they are wrapped in a double membrane, and they divide on their own schedule — all clues that they descend from free-living bacteria engulfed by an ancestral cell.
Problem 15
Answer and explanation
20 ×
40 ÷ 2 = 20 times wider, reflecting the much larger size of eukaryotic cells.
Problem 16
- bacteria have no ribosomes to jam
- bacterial (prokaryotic) ribosomes differ enough from human (eukaryotic) ribosomes for the drug to target one and not the other
- human cells have no ribosomes
- antibiotics cannot enter human cells at all
Answer and explanation
bacterial (prokaryotic) ribosomes differ enough from human (eukaryotic) ribosomes for the drug to target one and not the other
Prokaryotic ribosomes are structurally different from eukaryotic ones, so a drug can disable bacterial ribosomes while sparing our own — a key principle of selective antibiotics.
Problem 17
Answer and explanation
Ribosome→rough ER→Golgi→secretory vesicle→cell exterior, in a simplified pathway.
Ribosomes associated with rough ER synthesize the protein into the secretory pathway.
It passes through ER and Golgi processing and vesicles to the cell surface.
Response criteria
- Use the stated conditions.
- Show the evidence or calculation.
- Explain the conclusion and any stated limitation.
Problem 18
Hints
Ribosomes alone do not distinguish these types.
Answer and explanation
Eukaryotic; these membrane-bound structures support that classification.
Problem 19
Hints
State what the supplied observations or conditions establish, and separate that from any assumption.
Answer and explanation
No. Chloroplast abundance depends on tissue and function; many root cells do not photosynthesize.
Problem 20
Answer and explanation
No. It handles selected cargo; many proteins remain in other compartments and use different targeting routes.
The endoplasmic reticulum, ER, is a membrane network; ribosomes attached to rough ER can make proteins entering the secretory pathway. The Golgi apparatus modifies and sorts selected products. A vesicle is a membrane-bounded transport compartment, and exocytosis releases contents when its membrane fuses with the plasma membrane. The nucleus supplies transcribed information rather than shipping a finished protein through the whole route. Not all proteins follow this pathway; cytosolic proteins and organelle-targeted proteins have other destinations and targeting mechanisms.
No. It handles selected cargo; many proteins remain in other compartments and use different targeting routes.
Response criteria
- Read the structures, axes, directions and units correctly.
- Connect the evidence with the biological mechanism.
- Respect stated model assumptions and distinguish an observation from a further inference.
Problem 21
Answer and explanation
Gene information is transcribed and used by ribosomes; selected secretory proteins enter the ER, undergo processing/sorting through Golgi and travel in vesicles to membrane fusion. A cytosolic enzyme generally follows a different localization pathway rather than compulsory secretion.
Gene information is transcribed and used by ribosomes; selected secretory proteins enter the ER, undergo processing/sorting through Golgi and travel in vesicles to membrane fusion. A cytosolic enzyme generally follows a different localization pathway rather than compulsory secretion.
Response criteria
- Use the stated measurements or conditions, with correct units.
- Connect the result to the biological mechanism or evidence relationship.
- Identify the assumption, model limit or further evidence requested.
Problem 22
- hydrophilic; hydrophobic
- hydrophobic; hydrophilic
- both hydrophilic
- both hydrophobic
Answer and explanation
hydrophilic; hydrophobic
The phosphate head is water-loving (hydrophilic) and the fatty-acid tails are water-fearing (hydrophobic) — the split personality that lets a bilayer form.
Problem 23
- The rigid, crystal-like arrangement of phospholipids
- The colorful appearance of cells under a microscope
- The variety of proteins embedded throughout the membrane like tiles
- The way water freezes on the membrane
Answer and explanation
The variety of proteins embedded throughout the membrane like tiles
'Mosaic' refers to the patchwork of many different proteins set into the fluid phospholipid sheet.
Problem 24
- A sodium ion (charged)
- Glucose (large, polar)
- A protein
- Oxygen (small, nonpolar)
Answer and explanation
Oxygen (small, nonpolar)
Small nonpolar molecules like oxygen dissolve straight through the hydrophobic core; charged or large molecules need transport proteins.
Problem 25
Answer and explanation
Selective permeability means the membrane lets some substances cross while blocking or controlling others. It is essential because it lets the cell keep its internal chemistry different from the outside — taking in what it needs, removing wastes, and keeping harmful things out — which is the basis of homeostasis.
Problem 26
- A receptor protein that detects the signal and relays it inward
- The hydrophobic tails
- Cholesterol
- The nucleus
Answer and explanation
A receptor protein that detects the signal and relays it inward
Receptor proteins act as antennae: they bind the signal on the outside and trigger a response inside without the signal itself entering the cell.
Problem 27
Answer and explanation
Different chemical properties cause different permeabilities.
Oxygen is small and nonpolar.
A charged ion interacts poorly with the hydrophobic interior and generally needs a protein pathway.
Response criteria
- Use the stated conditions.
- Show the evidence or calculation.
- Explain the conclusion and any stated limitation.
Problem 28
Hints
A membrane is neither an open sieve nor an absolute wall.
Answer and explanation
Its structure permits certain particles and not others; movement can still occur down an electrochemical gradient.
Problem 29
Hints
State what the supplied observations or conditions establish, and separate that from any assumption.
Answer and explanation
No. Channels and carriers can mediate passive transport; active transport requires an energy-coupled mechanism.
Problem 30
Answer and explanation
Size alone is insufficient; its charge makes passage through the lipid interior unfavorable, and suitable transport proteins may be required.
Selective permeability means passage depends on a substance and the membrane’s pathways. Small nonpolar molecules can often enter the lipid interior more readily than ions, whose charge and surrounding interactions create a barrier. Some water crosses lipid membranes, and aquaporin proteins greatly increase water permeability in many cells. A molecule being small does not automatically guarantee rapid passage. Channels and carriers have selectivity and regulation, so identify the relevant substance, concentration/electrical conditions and available protein before predicting transport.
Size alone is insufficient; its charge makes passage through the lipid interior unfavorable, and suitable transport proteins may be required.
Response criteria
- Read the structures, axes, directions and units correctly.
- Connect the evidence with the biological mechanism.
- Respect stated model assumptions and distinguish an observation from a further inference.
Problem 31
Answer and explanation
Charge and lipid-interior interactions limit the direct route; the selective channel changes the available pathway. Fluidity concerns component motion, not unrestricted permeability to every substance.
Charge and lipid-interior interactions limit the direct route; the selective channel changes the available pathway. Fluidity concerns component motion, not unrestricted permeability to every substance.
Response criteria
- Use the stated measurements or conditions, with correct units.
- Connect the result to the biological mechanism or evidence relationship.
- Identify the assumption, model limit or further evidence requested.
Problem 32
- protein
- water
- oxygen
- glucose
Answer and explanation
water
Osmosis specifically refers to the movement of water across a selectively permeable membrane toward the side with more solute.
Problem 33
- It never uses proteins
- It only moves water
- It requires energy (ATP) and can move substances against their concentration gradient
- It moves substances down their concentration gradient
Answer and explanation
It requires energy (ATP) and can move substances against their concentration gradient
Active transport spends energy to move substances against the gradient; passive transport moves them down the gradient for free.
Problem 34
- Water leaves and the cell shrivels
- Nothing changes
- The cell builds a cell wall
- Water enters by osmosis and the cell swells and may burst
Answer and explanation
Water enters by osmosis and the cell swells and may burst
Pure water is hypotonic, so water rushes in by osmosis; with no wall to resist, the animal cell swells and can burst (lysis).
Problem 35
Answer and explanation
In endocytosis, the membrane wraps around material and pulls it into the cell inside a vesicle (bringing things in). In exocytosis, a vesicle fuses with the membrane and releases its contents outside the cell (sending things out). Both move large amounts of material and require energy.
Problem 36
Answer and explanation
1 charges
3 positive charges leave and 2 positive charges enter, so the net is 3 − 2 = 1 positive charge moved out.
Problem 37
- So there is no net osmosis — the blood cells neither swell and burst nor shrivel
- So the cells absorb as much water as possible
- So the cells lose water quickly
- Because isotonic fluids contain no water
Answer and explanation
So there is no net osmosis — the blood cells neither swell and burst nor shrivel
An isotonic fluid matches the solute concentration of blood, so water moves in and out equally and red blood cells keep their normal shape.
Problem 38
Answer and explanation
The cell initially loses water; the final behavior also depends on cell structure and pressure.
The external solution has the higher effective solute concentration.
Water moves out in the simple osmosis model.
Response criteria
- Use the stated conditions.
- Show the evidence or calculation.
- Explain the conclusion and any stated limitation.
Problem 39
Hints
State permeability and effective solute conditions; not every solute is trapped.
Answer and explanation
The pump uses coupled energy; facilitated diffusion moves particles down their electrochemical gradient.
Problem 40
Hints
State what the supplied observations or conditions establish, and separate that from any assumption.
Answer and explanation
Its cell wall resists expansion, allowing turgor pressure to balance water entry.
Problem 41
Answer and explanation
No. Both can have limited protein capacity; gradient direction and energy coupling provide additional tests.
Facilitated diffusion uses a channel or carrier for down-gradient transport. Active transport couples energy transfer to movement against the relevant driving gradient, directly through ATP or indirectly through another gradient. Primary active transport uses a direct energy source; secondary transport can use a gradient maintained by other processes. A pump and a passive carrier can both become saturated as capacity is limited. Therefore, protein involvement or a plateau alone does not establish whether the step is active; use direction, gradients, coupling and controlled energy perturbations.
No. Both can have limited protein capacity; gradient direction and energy coupling provide additional tests.
Response criteria
- Read the structures, axes, directions and units correctly.
- Connect the evidence with the biological mechanism.
- Respect stated model assumptions and distinguish an observation from a further inference.
Problem 42
Answer and explanation
The change is −3/12×100 = −25%. Net water loss is consistent with a hypertonic external solution under the model. Comparable blotting, membrane integrity and limits on solute loss are needed before assigning all mass change to water.
The change is −3/12×100 = −25%. Net water loss is consistent with a hypertonic external solution under the model. Comparable blotting, membrane integrity and limits on solute loss are needed before assigning all mass change to water.
Response criteria
- Use the stated measurements or conditions, with correct units.
- Connect the result to the biological mechanism or evidence relationship.
- Identify the assumption, model limit or further evidence requested.
Problem 43
Answer and explanation
2 mm⁻¹
6/3 = 2.
Problem 44
- 2 times larger
- 4 times larger
- 8 times larger
- unchanged
Answer and explanation
8 times larger
Volume depends on the cube of length.
Problem 45
Answer and explanation
Thinness shortens diffusion distance; folding increases exchange area.
Problem 46
Answer and explanation
The larger cube has half the area per unit volume.
At 1 mm, area=6 and volume=1, ratio=6 mm⁻¹.
At 2 mm, area=24 and volume=8, ratio=3 mm⁻¹.
Response criteria
- Use the stated conditions.
- Show the evidence or calculation.
- Explain the conclusion and any stated limitation.
Problem 47
Hints
Both lengths use the same units.
Answer and explanation
54/27=2 inverse length units.
Problem 48
Hints
State what the supplied observations or conditions establish, and separate that from any assumption.
Answer and explanation
They increase membrane area available for transport relative to the volume served.
Problem 49
Answer and explanation
No. Area supports capacity, but driving conditions, permeability and supply/removal also determine rate.
A fold can increase exchange area within a compact region. A thin barrier reduces the distance across which a substance must move. Circulation maintains delivery and removal by bulk transport, affecting gradients at exchange surfaces. These mechanisms should not be collapsed into one vague explanation that every surface is “large.” Intestinal villi, respiratory surfaces and internal membranes use different combinations under their conditions. A structural observation supports a plausible function, but actual rates also need permeability, driving conditions and activity measurements.
No. Area supports capacity, but driving conditions, permeability and supply/removal also determine rate.
Response criteria
- Read the structures, axes, directions and units correctly.
- Connect the evidence with the biological mechanism.
- Respect stated model assumptions and distinguish an observation from a further inference.
Problem 50
Answer and explanation
At 2 mm: area 24 mm², volume 8 mm³, ratio 3 mm⁻¹. At 4 mm: area 96 mm², volume 64 mm³, ratio 1.5 mm⁻¹. Total surface increases while area per volume falls; actual exchange also depends on pathways and demand.
At 2 mm: area 24 mm², volume 8 mm³, ratio 3 mm⁻¹. At 4 mm: area 96 mm², volume 64 mm³, ratio 1.5 mm⁻¹. Total surface increases while area per volume falls; actual exchange also depends on pathways and demand.
Response criteria
- Use the stated measurements or conditions, with correct units.
- Connect the result to the biological mechanism or evidence relationship.
- Identify the assumption, model limit or further evidence requested.