Cells, Membranes & Exchange — Chapter Practice, Grade 10

Connect cell structures, membrane transport, and exchange with the needs of cells.

Problem 1

Which statement is NOT one of the three tenets of cell theory?
  1. All living things are made of one or more cells
  2. The cell is the basic unit of structure and function
  3. All cells arise from pre-existing cells
  4. All cells contain a nucleus
Answer and explanation

All cells contain a nucleus

Prokaryotic cells (like bacteria) have no nucleus, so 'all cells contain a nucleus' is false and is not part of cell theory.

Problem 2

A researcher wants to see individual ribosomes, which are about 20 nanometers across. Why won't the best light microscope work?
  1. Its resolution limit (~200 nm) is far larger than a ribosome, so it cannot separate that fine detail no matter how much it magnifies
  2. Light microscopes cannot magnify past 100×
  3. Ribosomes are too large to fit in the field of view
  4. Light microscopes only work on living cells
Answer and explanation

Its resolution limit (~200 nm) is far larger than a ribosome, so it cannot separate that fine detail no matter how much it magnifies

Magnification and resolution are different. A light microscope's resolution stalls near 200 nm, so a 20 nm ribosome stays a blur; an electron microscope is needed.

Problem 3

A microscope has a 10× eyepiece and a 40× objective lens. What is the total magnification?
Answer and explanation

400 ×

Total magnification = eyepiece × objective = 10 × 40 = 400×.

Problem 4

Explain why disproving spontaneous generation was essential to completing cell theory.
Answer and explanation

Cell theory's third tenet says cells only come from pre-existing cells. If life could arise spontaneously from non-living matter, that tenet would be false. Pasteur's swan-neck experiment showed sterile broth stayed lifeless until microbes reached it, confirming that cells come only from other cells.

Problem 5

Who is credited as among the first to observe living, single-celled organisms?
  1. Robert Hooke
  2. Antonie van Leeuwenhoek
  3. Matthias Schleiden
  4. Louis Pasteur
Answer and explanation

Antonie van Leeuwenhoek

Leeuwenhoek's unusually powerful lenses let him observe living 'animalcules' in pond water in the 1670s.

Problem 6

A cell image spans 25 mm on paper and is labeled 500×. Estimate actual length. Explain the reasoning in your own words.
Answer and explanation

About 50 μm if the printed image retains its stated scale.

Actual size=image size/magnification=25/500=0.05 mm.

Convert 0.05 mm to 50 μm.

Response criteria

  • Use the stated conditions.
  • Show the evidence or calculation.
  • Explain the conclusion and any stated limitation.

Problem 7

Why did improved microscopy matter to cell theory? Show the reasoning, not just the conclusion.
Hints

An instrument extends observation but conclusions still require evidence.

Answer and explanation

It allowed structures and cell division to be observed and compared across organisms.

Problem 8

Does one empty microscope field prove a sample contains no cells?
Hints

State what the supplied observations or conditions establish, and separate that from any assumption.

Answer and explanation

No. Sampling, preparation, focus and resolution can limit detection; inspect appropriate fields and controls.

Problem 9

Enlarging an unresolved feature does not create new detailEnlarging an unresolved feature does not create new detailMagnification aloneBetter resolutionResolution: distinguish nearby features, not simply make a blur bigger.
Original resolution comparison, not a calibrated microscope test; the two-panel scale isolates the conceptual distinction.
Interpret the supplied visual. Why would enlarging a blurry photograph not establish that two nearby structures are one?
Answer and explanation

The original image may lack sufficient resolution; resizing cannot recover detail that was never resolved. Use an appropriate method or independent evidence.

Magnification is enlargement of an image. Resolution is the ability to distinguish nearby features as separate under the imaging conditions. A larger blurry spot can still hide two structures. Contrast, preparation, staining and artifacts also influence what can be seen. Light and electron imaging have different capacities and preparation requirements; neither one automatically shows every structure alive and unchanged. Before identifying an organelle, ask whether the feature is resolved, labeled with scale and supported by appropriate observations rather than a familiar-looking blob.

The original image may lack sufficient resolution; resizing cannot recover detail that was never resolved. Use an appropriate method or independent evidence.

Response criteria

  • Read the structures, axes, directions and units correctly.
  • Connect the evidence with the biological mechanism.
  • Respect stated model assumptions and distinguish an observation from a further inference.

Problem 10

A cell spans 2.4 lengths of a 25 μm scale bar. Find its estimated length and explain why a resized “400×” label is less useful than the correctly resized bar.
Answer and explanation

The estimate is 2.4×25 = 60 μm. A magnification label describes a particular display enlargement; resizing changes it, while an image and scale bar resized together preserve the specimen-length ratio.

The estimate is 2.4×25 = 60 μm. A magnification label describes a particular display enlargement; resizing changes it, while an image and scale bar resized together preserve the specimen-length ratio.

Response criteria

  • Use the stated measurements or conditions, with correct units.
  • Connect the result to the biological mechanism or evidence relationship.
  • Identify the assumption, model limit or further evidence requested.

Problem 11

Which feature is found in eukaryotic cells but NEVER in prokaryotic cells?
  1. A cell membrane
  2. Ribosomes
  3. A membrane-bound nucleus
  4. DNA
Answer and explanation

A membrane-bound nucleus

Prokaryotes have DNA, ribosomes, and a cell membrane, but they lack a true membrane-bound nucleus — that is the defining eukaryotic feature.

Problem 12

Which organelle modifies, sorts, and packages proteins into vesicles for shipping?
  1. Mitochondrion
  2. Ribosome
  3. Nucleus
  4. Golgi apparatus
Answer and explanation

Golgi apparatus

The Golgi apparatus is the cell's shipping department, tagging and packaging proteins into vesicles addressed to their destinations.

Problem 13

Why is the rough endoplasmic reticulum described as 'rough'?
  1. It is studded with ribosomes that build and process proteins
  2. It has a jagged outer wall
  3. It stores rough, undigested food
  4. It contains chloroplasts
Answer and explanation

It is studded with ribosomes that build and process proteins

Ribosomes attached to its surface give the rough ER its bumpy look and its role in processing newly made proteins.

Problem 14

State two pieces of evidence that support the endosymbiotic origin of mitochondria.
Answer and explanation

Mitochondria have their own circular DNA separate from the nucleus, they are wrapped in a double membrane, and they divide on their own schedule — all clues that they descend from free-living bacteria engulfed by an ancestral cell.

Problem 15

A typical eukaryotic cell is about 40 micrometers across, while a typical bacterium is about 2 micrometers across. How many times wider is the eukaryotic cell?
Answer and explanation

20 ×

40 ÷ 2 = 20 times wider, reflecting the much larger size of eukaryotic cells.

Problem 16

Some antibiotics kill bacteria by jamming their ribosomes yet leave human cells unharmed. The best explanation is that
  1. bacteria have no ribosomes to jam
  2. bacterial (prokaryotic) ribosomes differ enough from human (eukaryotic) ribosomes for the drug to target one and not the other
  3. human cells have no ribosomes
  4. antibiotics cannot enter human cells at all
Answer and explanation

bacterial (prokaryotic) ribosomes differ enough from human (eukaryotic) ribosomes for the drug to target one and not the other

Prokaryotic ribosomes are structurally different from eukaryotic ones, so a drug can disable bacterial ribosomes while sparing our own — a key principle of selective antibiotics.

Problem 17

Trace a protein secreted by a typical eukaryotic cell through major compartments. Explain the reasoning in your own words.
Answer and explanation

Ribosome→rough ER→Golgi→secretory vesicle→cell exterior, in a simplified pathway.

Ribosomes associated with rough ER synthesize the protein into the secretory pathway.

It passes through ER and Golgi processing and vesicles to the cell surface.

Response criteria

  • Use the stated conditions.
  • Show the evidence or calculation.
  • Explain the conclusion and any stated limitation.

Problem 18

A cell contains a nucleus and mitochondria. Which broad category fits? Show the reasoning, not just the conclusion.
Hints

Ribosomes alone do not distinguish these types.

Answer and explanation

Eukaryotic; these membrane-bound structures support that classification.

Problem 19

Would every cell in a plant contain chloroplasts? Explain.
Hints

State what the supplied observations or conditions establish, and separate that from any assumption.

Answer and explanation

No. Chloroplast abundance depends on tissue and function; many root cells do not photosynthesize.

Problem 20

A secretion pathway connects information, synthesis and membranesA secretion pathway connects information, synthesis and membranesGeneRough ERGolgiVesicle → membraneA secreted protein is made, processed and carried through a pathway.
Original secretion-route model. Arrows summarize several distinct steps, and the small vesicle is not a literal protein molecule.
Interpret the supplied visual. Does the presence of Golgi prove that every protein in the cell is secreted?
Answer and explanation

No. It handles selected cargo; many proteins remain in other compartments and use different targeting routes.

The endoplasmic reticulum, ER, is a membrane network; ribosomes attached to rough ER can make proteins entering the secretory pathway. The Golgi apparatus modifies and sorts selected products. A vesicle is a membrane-bounded transport compartment, and exocytosis releases contents when its membrane fuses with the plasma membrane. The nucleus supplies transcribed information rather than shipping a finished protein through the whole route. Not all proteins follow this pathway; cytosolic proteins and organelle-targeted proteins have other destinations and targeting mechanisms.

No. It handles selected cargo; many proteins remain in other compartments and use different targeting routes.

Response criteria

  • Read the structures, axes, directions and units correctly.
  • Connect the evidence with the biological mechanism.
  • Respect stated model assumptions and distinguish an observation from a further inference.

Problem 21

A cell makes a protein that will be exported. Explain the roles of DNA/RNA information, rough ER, Golgi and vesicles, and why this route need not describe a cytosolic enzyme.
Answer and explanation

Gene information is transcribed and used by ribosomes; selected secretory proteins enter the ER, undergo processing/sorting through Golgi and travel in vesicles to membrane fusion. A cytosolic enzyme generally follows a different localization pathway rather than compulsory secretion.

Gene information is transcribed and used by ribosomes; selected secretory proteins enter the ER, undergo processing/sorting through Golgi and travel in vesicles to membrane fusion. A cytosolic enzyme generally follows a different localization pathway rather than compulsory secretion.

Response criteria

  • Use the stated measurements or conditions, with correct units.
  • Connect the result to the biological mechanism or evidence relationship.
  • Identify the assumption, model limit or further evidence requested.

Problem 22

In a phospholipid, the phosphate head is ___ and the fatty-acid tails are ___.
  1. hydrophilic; hydrophobic
  2. hydrophobic; hydrophilic
  3. both hydrophilic
  4. both hydrophobic
Answer and explanation

hydrophilic; hydrophobic

The phosphate head is water-loving (hydrophilic) and the fatty-acid tails are water-fearing (hydrophobic) — the split personality that lets a bilayer form.

Problem 23

In the fluid mosaic model, what does the word 'mosaic' describe?
  1. The rigid, crystal-like arrangement of phospholipids
  2. The colorful appearance of cells under a microscope
  3. The variety of proteins embedded throughout the membrane like tiles
  4. The way water freezes on the membrane
Answer and explanation

The variety of proteins embedded throughout the membrane like tiles

'Mosaic' refers to the patchwork of many different proteins set into the fluid phospholipid sheet.

Problem 24

Which molecule can pass most easily through the phospholipid bilayer WITHOUT a protein?
  1. A sodium ion (charged)
  2. Glucose (large, polar)
  3. A protein
  4. Oxygen (small, nonpolar)
Answer and explanation

Oxygen (small, nonpolar)

Small nonpolar molecules like oxygen dissolve straight through the hydrophobic core; charged or large molecules need transport proteins.

Problem 25

Explain what 'selective permeability' means and why it is essential for a cell.
Answer and explanation

Selective permeability means the membrane lets some substances cross while blocking or controlling others. It is essential because it lets the cell keep its internal chemistry different from the outside — taking in what it needs, removing wastes, and keeping harmful things out — which is the basis of homeostasis.

Problem 26

A hormone that cannot cross the membrane still changes a cell's behavior. Which membrane component makes this possible?
  1. A receptor protein that detects the signal and relays it inward
  2. The hydrophobic tails
  3. Cholesterol
  4. The nucleus
Answer and explanation

A receptor protein that detects the signal and relays it inward

Receptor proteins act as antennae: they bind the signal on the outside and trigger a response inside without the signal itself entering the cell.

Problem 27

Why does oxygen often cross a lipid bilayer more readily than a sodium ion? Explain the reasoning in your own words.
Answer and explanation

Different chemical properties cause different permeabilities.

Oxygen is small and nonpolar.

A charged ion interacts poorly with the hydrophobic interior and generally needs a protein pathway.

Response criteria

  • Use the stated conditions.
  • Show the evidence or calculation.
  • Explain the conclusion and any stated limitation.

Problem 28

Why can a channel make diffusion selective? Show the reasoning, not just the conclusion.
Hints

A membrane is neither an open sieve nor an absolute wall.

Answer and explanation

Its structure permits certain particles and not others; movement can still occur down an electrochemical gradient.

Problem 29

Does adding a membrane transport protein necessarily make transport active?
Hints

State what the supplied observations or conditions establish, and separate that from any assumption.

Answer and explanation

No. Channels and carriers can mediate passive transport; active transport requires an energy-coupled mechanism.

Problem 30

A membrane can allow one substance while limiting anotherA membrane can allow one substance while limiting another+Small nonpolar soluteIon: chargedPermeability depends on the substance and the available pathways.
Original qualitative permeability comparison. Arrow length is not a numerical permeability coefficient, and omitted channels could change actual ion transport.
Interpret the supplied visual. Can an ion cross simply because it is smaller than a protein?
Answer and explanation

Size alone is insufficient; its charge makes passage through the lipid interior unfavorable, and suitable transport proteins may be required.

Selective permeability means passage depends on a substance and the membrane’s pathways. Small nonpolar molecules can often enter the lipid interior more readily than ions, whose charge and surrounding interactions create a barrier. Some water crosses lipid membranes, and aquaporin proteins greatly increase water permeability in many cells. A molecule being small does not automatically guarantee rapid passage. Channels and carriers have selectivity and regulation, so identify the relevant substance, concentration/electrical conditions and available protein before predicting transport.

Size alone is insufficient; its charge makes passage through the lipid interior unfavorable, and suitable transport proteins may be required.

Response criteria

  • Read the structures, axes, directions and units correctly.
  • Connect the evidence with the biological mechanism.
  • Respect stated model assumptions and distinguish an observation from a further inference.

Problem 31

A small charged solute crosses a cell membrane only after a matching channel opens. Explain why size alone and the phrase “fluid membrane” do not predict its passage.
Answer and explanation

Charge and lipid-interior interactions limit the direct route; the selective channel changes the available pathway. Fluidity concerns component motion, not unrestricted permeability to every substance.

Charge and lipid-interior interactions limit the direct route; the selective channel changes the available pathway. Fluidity concerns component motion, not unrestricted permeability to every substance.

Response criteria

  • Use the stated measurements or conditions, with correct units.
  • Connect the result to the biological mechanism or evidence relationship.
  • Identify the assumption, model limit or further evidence requested.

Problem 32

Osmosis is best defined as the diffusion of ___ across a selectively permeable membrane.
  1. protein
  2. water
  3. oxygen
  4. glucose
Answer and explanation

water

Osmosis specifically refers to the movement of water across a selectively permeable membrane toward the side with more solute.

Problem 33

Which is TRUE of active transport but NOT of passive transport?
  1. It never uses proteins
  2. It only moves water
  3. It requires energy (ATP) and can move substances against their concentration gradient
  4. It moves substances down their concentration gradient
Answer and explanation

It requires energy (ATP) and can move substances against their concentration gradient

Active transport spends energy to move substances against the gradient; passive transport moves them down the gradient for free.

Problem 34

A red blood cell is placed in pure (hypotonic) water. What happens?
  1. Water leaves and the cell shrivels
  2. Nothing changes
  3. The cell builds a cell wall
  4. Water enters by osmosis and the cell swells and may burst
Answer and explanation

Water enters by osmosis and the cell swells and may burst

Pure water is hypotonic, so water rushes in by osmosis; with no wall to resist, the animal cell swells and can burst (lysis).

Problem 35

Explain the difference between endocytosis and exocytosis.
Answer and explanation

In endocytosis, the membrane wraps around material and pulls it into the cell inside a vesicle (bringing things in). In exocytosis, a vesicle fuses with the membrane and releases its contents outside the cell (sending things out). Both move large amounts of material and require energy.

Problem 36

The sodium-potassium pump ejects 3 sodium ions and imports 2 potassium ions each cycle. What is the net number of positive charges moved OUT of the cell per cycle?
Answer and explanation

1 charges

3 positive charges leave and 2 positive charges enter, so the net is 3 − 2 = 1 positive charge moved out.

Problem 37

Why must fluids given through an IV drip be isotonic to a patient's blood?
  1. So there is no net osmosis — the blood cells neither swell and burst nor shrivel
  2. So the cells absorb as much water as possible
  3. So the cells lose water quickly
  4. Because isotonic fluids contain no water
Answer and explanation

So there is no net osmosis — the blood cells neither swell and burst nor shrivel

An isotonic fluid matches the solute concentration of blood, so water moves in and out equally and red blood cells keep their normal shape.

Problem 38

A cell is placed in an equal-pressure solution containing more impermeant solute than its interior. Predict initial water movement. Explain the reasoning in your own words.
Answer and explanation

The cell initially loses water; the final behavior also depends on cell structure and pressure.

The external solution has the higher effective solute concentration.

Water moves out in the simple osmosis model.

Response criteria

  • Use the stated conditions.
  • Show the evidence or calculation.
  • Explain the conclusion and any stated limitation.

Problem 39

A cell pumps ions against their gradient. What distinguishes this from facilitated diffusion? Show the reasoning, not just the conclusion.
Hints

State permeability and effective solute conditions; not every solute is trapped.

Answer and explanation

The pump uses coupled energy; facilitated diffusion moves particles down their electrochemical gradient.

Problem 40

Why can a plant cell resist bursting in dilute surroundings better than many animal cells?
Hints

State what the supplied observations or conditions establish, and separate that from any assumption.

Answer and explanation

Its cell wall resists expansion, allowing turgor pressure to balance water entry.

Problem 41

Transport proteins can support passive or energy-driven movementTransport proteins can support passive or energy-driven movementFacilitated diffusion: down-gradientAn active pump can use energy to move against its driving gradient.Using a protein does not by itself make transport active.
Original facilitated transport schematic. The protein symbolizes a route, not a measured ion pump, ATP stoichiometry or complete electrical gradient.
Interpret the supplied visual. Would a saturating uptake curve alone distinguish facilitated diffusion from active transport?
Answer and explanation

No. Both can have limited protein capacity; gradient direction and energy coupling provide additional tests.

Facilitated diffusion uses a channel or carrier for down-gradient transport. Active transport couples energy transfer to movement against the relevant driving gradient, directly through ATP or indirectly through another gradient. Primary active transport uses a direct energy source; secondary transport can use a gradient maintained by other processes. A pump and a passive carrier can both become saturated as capacity is limited. Therefore, protein involvement or a plateau alone does not establish whether the step is active; use direction, gradients, coupling and controlled energy perturbations.

No. Both can have limited protein capacity; gradient direction and energy coupling provide additional tests.

Response criteria

  • Read the structures, axes, directions and units correctly.
  • Connect the evidence with the biological mechanism.
  • Respect stated model assumptions and distinguish an observation from a further inference.

Problem 42

A tissue sample changes from 12 g to 9 g in a stated nonpenetrating-solute model. Find percentage change and explain a suitable osmotic account plus one measurement control.
Answer and explanation

The change is −3/12×100 = −25%. Net water loss is consistent with a hypertonic external solution under the model. Comparable blotting, membrane integrity and limits on solute loss are needed before assigning all mass change to water.

The change is −3/12×100 = −25%. Net water loss is consistent with a hypertonic external solution under the model. Comparable blotting, membrane integrity and limits on solute loss are needed before assigning all mass change to water.

Response criteria

  • Use the stated measurements or conditions, with correct units.
  • Connect the result to the biological mechanism or evidence relationship.
  • Identify the assumption, model limit or further evidence requested.

Problem 43

Find area/volume for a cube with side length 3 mm.
Answer and explanation

2 mm⁻¹

6/3 = 2.

Problem 44

Doubling a cube’s side makes its volume…
  1. 2 times larger
  2. 4 times larger
  3. 8 times larger
  4. unchanged
Answer and explanation

8 times larger

Volume depends on the cube of length.

Problem 45

How do a thin surface and folding help exchange?
Answer and explanation

Thinness shortens diffusion distance; folding increases exchange area.

Problem 46

Compare area/volume ratios for cubes of side 1 mm and 2 mm. Explain the reasoning in your own words.
Answer and explanation

The larger cube has half the area per unit volume.

At 1 mm, area=6 and volume=1, ratio=6 mm⁻¹.

At 2 mm, area=24 and volume=8, ratio=3 mm⁻¹.

Response criteria

  • Use the stated conditions.
  • Show the evidence or calculation.
  • Explain the conclusion and any stated limitation.

Problem 47

For L=3, find SA/V using 6L²/L³. Show the reasoning, not just the conclusion.
Hints

Both lengths use the same units.

Answer and explanation

54/27=2 inverse length units.

Problem 48

How can folds help a cell exchange materials without greatly increasing volume?
Hints

State what the supplied observations or conditions establish, and separate that from any assumption.

Answer and explanation

They increase membrane area available for transport relative to the volume served.

Problem 49

Surface shape, thickness and delivery solve different exchange problemsSurface shape, thickness and delivery solve different exchange problemsSmooth exchange boundaryFolded exchange boundaryFolds add area within a similar footprint.Thin barriers shorten a diffusion path; circulation changes delivery.
Original smooth/folded boundary sections; the curves illustrate added area qualitatively and are not a measured organ surface or a fold-area calculation.
Interpret the supplied visual. Would more folds alone guarantee faster exchange if no useful gradient or pathway exists?
Answer and explanation

No. Area supports capacity, but driving conditions, permeability and supply/removal also determine rate.

A fold can increase exchange area within a compact region. A thin barrier reduces the distance across which a substance must move. Circulation maintains delivery and removal by bulk transport, affecting gradients at exchange surfaces. These mechanisms should not be collapsed into one vague explanation that every surface is “large.” Intestinal villi, respiratory surfaces and internal membranes use different combinations under their conditions. A structural observation supports a plausible function, but actual rates also need permeability, driving conditions and activity measurements.

No. Area supports capacity, but driving conditions, permeability and supply/removal also determine rate.

Response criteria

  • Read the structures, axes, directions and units correctly.
  • Connect the evidence with the biological mechanism.
  • Respect stated model assumptions and distinguish an observation from a further inference.

Problem 50

A cube’s side length rises from 2 to 4 mm. Calculate area, volume and area/volume for both, then explain why “the larger one has less surface” is misleading.
Answer and explanation

At 2 mm: area 24 mm², volume 8 mm³, ratio 3 mm⁻¹. At 4 mm: area 96 mm², volume 64 mm³, ratio 1.5 mm⁻¹. Total surface increases while area per volume falls; actual exchange also depends on pathways and demand.

At 2 mm: area 24 mm², volume 8 mm³, ratio 3 mm⁻¹. At 4 mm: area 96 mm², volume 64 mm³, ratio 1.5 mm⁻¹. Total surface increases while area per volume falls; actual exchange also depends on pathways and demand.

Response criteria

  • Use the stated measurements or conditions, with correct units.
  • Connect the result to the biological mechanism or evidence relationship.
  • Identify the assumption, model limit or further evidence requested.

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