Investigating the Chemistry of Life — Chapter Practice, Grade 10

Use fair comparisons and molecular models to explain reactions in living systems.

Problem 1

Three independent rates are 4, 6, and 8 units/min. Find the mean.
Answer and explanation

6 units/min

18 ÷ 3 = 6.

Problem 2

To test temperature alone, which factor should also be kept comparable?
  1. Enzyme amount
  2. The measured reaction rate
  3. The graph height
  4. The conclusion
Answer and explanation

Enzyme amount

Changing enzyme amount would introduce another potential cause.

Problem 3

Why does measuring one sample three times differ from preparing three samples?
Answer and explanation

Repeated readings emphasize measurement variability; independent samples also reflect preparation and biological variation.

Problem 4

One plant is measured ten times after treatment. Does this establish the treatment's effect on plants generally? Explain the reasoning in your own words.
Answer and explanation

No; use independent plants, appropriate comparisons and controlled conditions to test a broader claim.

The ten readings describe repeatability for one plant.

They do not capture variation among plants or provide an untreated comparison.

Response criteria

  • Use the stated conditions.
  • Show the evidence or calculation.
  • Explain the conclusion and any stated limitation.

Problem 5

A test compares fertilizer treatments on one plant each. What improvement helps distinguish treatment effects from individual variation? Show the reasoning, not just the conclusion.
Hints

Replication helps assess variation but does not by itself remove confounding.

Answer and explanation

Use several comparable plants per treatment, assigned fairly, with other conditions held constant.

Problem 6

Why specify growth as a measured change rather than looks healthier?
Hints

State what the supplied observations or conditions establish, and separate that from any assumption.

Answer and explanation

An operational measure such as height change or dry mass allows repeatable comparisons; appearance alone is subjective.

Problem 7

A mean summarizes a distribution without replacing itA mean summarizes a distribution without replacing itIllustrative height change (mm)Plant 110Plant 220Plant 330Plant 440Mean = 25 mm; range = 10–40 mm. Keep every result.
Original illustrative replicate outcomes. They are not evidence of a universal biological growth rate or a significance test.
Interpret the supplied visual. Would replacing these four records with “25 mm for every plant” be accurate?
Answer and explanation

No. Twenty-five is the mean, while the individual plants range from 10 to 40 mm. Retain variation and the sampling conditions.

A mean is the sum of measured values divided by their number. The range describes the spread from minimum to maximum; it is not an uncertainty interval for a population mean. These four plants have mean 25 mm and range 10–40 mm. A bar showing only the mean would hide the variation. Report sample size, units and individual results or a useful distribution plot. Do not discard a low result solely because it weakens the preferred hypothesis; exclusions require a stated reason such as a documented measurement failure.

No. Twenty-five is the mean, while the individual plants range from 10 to 40 mm. Retain variation and the sampling conditions.

Response criteria

  • Read the structures, axes, directions and units correctly.
  • Connect the evidence with the biological mechanism.
  • Respect stated model assumptions and distinguish an observation from a further inference.

Problem 8

Two trays receive different nutrient treatments. Each tray contains one plant measured six times. Explain the true replication and redesign the comparison.
Answer and explanation

There is only one treated biological/treatment unit per condition; six readings are repeated observations. Use several independently assigned plants or trays per condition, keep light/water/species comparable and preserve all time records.

There is only one treated biological/treatment unit per condition; six readings are repeated observations. Use several independently assigned plants or trays per condition, keep light/water/species comparable and preserve all time records.

Response criteria

  • Use the stated measurements or conditions, with correct units.
  • Connect the result to the biological mechanism or evidence relationship.
  • Identify the assumption, model limit or further evidence requested.

Problem 9

Which type of bond forms when two atoms share a pair of electrons?
  1. Metallic bond
  2. Ionic bond
  3. Covalent bond
  4. Hydrogen bond
Answer and explanation

Covalent bond

In a covalent bond, two atoms share a pair of electrons — as oxygen does with two hydrogens in water.

Problem 10

Water is described as a 'polar molecule' because
  1. it is made of only one element
  2. it carries a full electrical charge overall
  3. it cannot dissolve any other substances
  4. it shares its electrons unequally, giving it a slightly positive end and a slightly negative end
Answer and explanation

it shares its electrons unequally, giving it a slightly positive end and a slightly negative end

Oxygen pulls the shared electrons closer, leaving the oxygen end slightly negative and the hydrogen ends slightly positive — that charge separation makes water polar.

Problem 11

How many times more acidic is a solution of pH 2 than a solution of pH 5?
Answer and explanation

1000 times

Each pH unit is a factor of 10. The difference is 5 − 2 = 3 units, so 10³ = 1000 times more acidic.

Problem 12

Explain how hydrogen bonds give water its cohesion, and give one example of cohesion in nature.
Answer and explanation

Hydrogen bonds attract water molecules to one another, so they stick together — this is cohesion. It creates surface tension that lets a water strider walk on a pond and helps tall trees pull an unbroken column of water up from their roots to their leaves.

Problem 13

A student claims, 'Salt dissolves in water because water breaks the covalent bonds inside salt.' What is the main error?
  1. Salt is held together by ionic bonds, not covalent bonds; water surrounds and separates its ions without breaking any covalent bonds
  2. Water cannot dissolve salt at all
  3. Salt has no chemical bonds to break
  4. Water is nonpolar, so it can never dissolve salt
Answer and explanation

Salt is held together by ionic bonds, not covalent bonds; water surrounds and separates its ions without breaking any covalent bonds

Salt (NaCl) is held together by ionic bonds. Polar water molecules surround the Na⁺ and Cl⁻ ions and pull them apart — it separates ions rather than breaking covalent bonds.

Problem 14

Why do oil and water tend to separate while salt can dissolve in water? Explain the reasoning in your own words.
Answer and explanation

Different molecular interactions explain the contrasting behavior; water does not dissolve everything.

Water interacts strongly with ions and many polar groups.

Nonpolar oil does not make similarly favorable interactions with water and separates in bulk.

Response criteria

  • Use the stated conditions.
  • Show the evidence or calculation.
  • Explain the conclusion and any stated limitation.

Problem 15

Why is water's oxygen region partially negative while hydrogen regions are partially positive? Show the reasoning, not just the conclusion.
Hints

Do not treat hydrogen bonds between molecules as the covalent bonds inside water.

Answer and explanation

Oxygen attracts shared electrons more strongly, creating an uneven charge distribution rather than full ionic charges.

Problem 16

Does melting ice break all O–H covalent bonds in water molecules?
Hints

State what the supplied observations or conditions establish, and separate that from any assumption.

Answer and explanation

No. It mainly alters intermolecular organization; water molecules remain intact.

Problem 17

Equal energy additions need not give equal temperature changesEqual energy additions need not give equal temperature changesTemperature (°C)20253035400123Equal successive energy additionsSample A: water modelSample B: comparison
Original matched-mass heating example with invented records; the horizontal axis is an input count, not real calorimeter time or a measured water constant.
Interpret the supplied visual. What controlled conditions are needed to infer different heat capacities from these slopes?
Answer and explanation

Use matched masses, equal energy inputs, stated phases and comparable heat losses. The supplied water-model sample rises 6 °C, the comparison 18 °C.

Temperature describes a thermal state, while thermal energy also depends on amount and material. Specific heat capacity is energy per unit mass per degree of temperature change under stated conditions. Matched masses receiving equal energy can warm at different rates. Water’s interactions and degrees of freedom contribute to its relatively high heat capacity, moderating temperature changes in organisms and environments. This is different from evaporation, which transfers energy through a phase change. Heat-loss conditions, mass and phase must be comparable before assigning the observed slope only to a material property.

Use matched masses, equal energy inputs, stated phases and comparable heat losses. The supplied water-model sample rises 6 °C, the comparison 18 °C.

Response criteria

  • Read the structures, axes, directions and units correctly.
  • Connect the evidence with the biological mechanism.
  • Respect stated model assumptions and distinguish an observation from a further inference.

Problem 18

Compare hydrogen-ion concentrations at pH 5 and pH 8 using a tenfold change per unit. Explain why a buffer cannot be described as preventing every pH change.
Answer and explanation

The pH 5 sample has 10³ = 1,000 times the hydrogen-ion concentration of the pH 8 sample in the dilute-solution comparison. A buffer has a finite working range and capacity; sufficiently large additions can exceed it.

The pH 5 sample has 10³ = 1,000 times the hydrogen-ion concentration of the pH 8 sample in the dilute-solution comparison. A buffer has a finite working range and capacity; sufficiently large additions can exceed it.

Response criteria

  • Use the stated measurements or conditions, with correct units.
  • Connect the result to the biological mechanism or evidence relationship.
  • Identify the assumption, model limit or further evidence requested.

Problem 19

Why is carbon so well suited to building the molecules of life?
  1. It cannot bond with any other element
  2. It can form four covalent bonds, letting it build long chains, branches, and rings
  3. It is the most abundant element on Earth
  4. It always forms ionic bonds
Answer and explanation

It can form four covalent bonds, letting it build long chains, branches, and rings

Each carbon atom can form four covalent bonds, so carbon can link into the large, varied skeletons that macromolecules need.

Problem 20

The monomer (building block) of a protein is a(n)
  1. monosaccharide
  2. fatty acid
  3. amino acid
  4. nucleotide
Answer and explanation

amino acid

Proteins are polymers of amino acids; there are 20 kinds that cells string together in different orders.

Problem 21

Which macromolecule family stores genetic information?
  1. Protein
  2. Lipid
  3. Carbohydrate
  4. Nucleic acid
Answer and explanation

Nucleic acid

Nucleic acids — DNA and RNA — store and carry the genetic instructions for building proteins.

Problem 22

A polymer is built by linking 12 monomers into a single chain. How many bonds connect them?
Answer and explanation

11 bonds

In a single chain, the number of bonds is one less than the number of monomers: 12 − 1 = 11 bonds.

Problem 23

Explain the phrase 'a protein's shape determines its function,' and connect it to why proteins can act as enzymes.
Answer and explanation

A protein's chain of amino acids folds into a specific 3-D shape, and that shape decides which molecules it can fit and interact with. Enzymes depend on this because their folded shape forms an active site that fits one specific substrate — change the shape and the enzyme can no longer do its job.

Problem 24

A growing plant gains dry mass while soil mass changes little. Explain a major source of its carbon. Explain the reasoning in your own words.
Answer and explanation

Atmospheric carbon dioxide is a major carbon source; water and mineral nutrients are also required.

Photosynthesis incorporates carbon from atmospheric CO₂.

That carbon can be rearranged into carbohydrates and other organic molecules.

Response criteria

  • Use the stated conditions.
  • Show the evidence or calculation.
  • Explain the conclusion and any stated limitation.

Problem 25

Identify the building units of DNA and explain why their order matters. Show the reasoning, not just the conclusion.
Hints

Do not infer that every carbon-containing molecule has the same biological role.

Answer and explanation

DNA contains nucleotides; base sequence carries information affecting RNA and proteins.

Problem 26

Why cannot equal food mass establish equal available energy or nutrient function?
Hints

State what the supplied observations or conditions establish, and separate that from any assumption.

Answer and explanation

Composition, digestibility and molecule types differ; mass alone does not identify chemical stores or biological roles.

Problem 27

Protein function depends on sequence, folding and contextProtein function depends on sequence, folding and contextSequenceFolded structureInteractions depend on conditionsSequence → interactions / folding → possible function
Original symbolic amino-acid sequence and folded-chain model. It illustrates an explanatory relationship, not a solved structure of a named protein.
Interpret the supplied visual. Does an unfolded protein necessarily have a newly rewritten amino-acid sequence?
Answer and explanation

No. Its interactions and folding may change while much of the covalent chain sequence remains; hydrolysis and denaturation are different processes.

A protein consists of one or more folded polypeptides, chains of amino acids joined by peptide bonds. Each amino acid has a side group whose interactions influence folding. A different sequence can change a binding site, stability or location, but some sequence changes have little detectable effect. Denaturation disrupts an important folded arrangement; it is not the same as cutting every peptide bond. Enzymes, structural components, receptors and transporters are protein roles. A correct explanation connects a particular structural change to a tested function rather than saying all proteins behave alike.

No. Its interactions and folding may change while much of the covalent chain sequence remains; hydrolysis and denaturation are different processes.

Response criteria

  • Read the structures, axes, directions and units correctly.
  • Connect the evidence with the biological mechanism.
  • Respect stated model assumptions and distinguish an observation from a further inference.

Problem 28

A treatment unfolds an enzyme but leaves its amino-acid chain largely intact. Explain what may change, what need not change, and what evidence would test retained function.
Answer and explanation

Folding and active-site arrangement may change while amino-acid sequence remains largely intact. Compare catalytic rates under matched conditions and examine whether the fold/function can recover; unfolding is not automatically complete peptide hydrolysis.

Folding and active-site arrangement may change while amino-acid sequence remains largely intact. Compare catalytic rates under matched conditions and examine whether the fold/function can recover; unfolding is not automatically complete peptide hydrolysis.

Response criteria

  • Use the stated measurements or conditions, with correct units.
  • Connect the result to the biological mechanism or evidence relationship.
  • Identify the assumption, model limit or further evidence requested.

Problem 29

An enzyme is best described as a
  1. protein that speeds up a chemical reaction without being used up
  2. sugar that stores energy for the cell
  3. type of lipid that builds the cell membrane
  4. molecule that stores genetic information
Answer and explanation

protein that speeds up a chemical reaction without being used up

Enzymes are protein catalysts — they speed up specific reactions and are not consumed, so they can be reused.

Problem 30

The specific molecule that an enzyme acts on is called its
  1. active site
  2. substrate
  3. product
  4. catalyst
Answer and explanation

substrate

The substrate is the molecule that binds the active site and gets changed into product.

Problem 31

Why does an enzyme stop working at very high temperatures?
  1. The substrate becomes too cold to move
  2. High heat gives the enzyme an extra active site
  3. The heat denatures the enzyme, changing the shape of its active site so the substrate no longer fits
  4. The enzyme is used up in the reaction
Answer and explanation

The heat denatures the enzyme, changing the shape of its active site so the substrate no longer fits

Too much heat unravels the protein's folding (denaturing), distorting the active site so the substrate can't bind.

Problem 32

Without an enzyme, a reaction makes 5 molecules of product per second. With its enzyme, the reaction runs 200 times faster. How many molecules of product form per second with the enzyme?
Answer and explanation

1000 molecules per second

5 products/second × 200 = 1000 products per second.

Problem 33

Pepsin, a stomach enzyme, works best at about pH 2, while most enzymes in your cells work best near pH 7. Use what you know about enzyme shape to explain why an enzyme has an optimum pH.
Answer and explanation

An enzyme's function depends on its precise folded shape, which is held by chemical attractions sensitive to the surrounding H⁺ concentration (pH). At its optimum pH the active site keeps the right shape to fit the substrate; at the wrong pH those attractions are disrupted, the active site distorts, and the enzyme works poorly or denatures. Pepsin evolved to fold correctly in stomach acid, so its optimum is pH 2.

Problem 34

Rate increases with substrate concentration then levels off while enzyme amount is fixed. Give a plausible explanation. Explain the reasoning in your own words.
Answer and explanation

Enzyme saturation can explain the plateau; the design must rule out other limiting conditions.

At low substrate, more substrate increases encounters with active sites.

At high substrate, available sites can become occupied much of the time.

Response criteria

  • Use the stated conditions.
  • Show the evidence or calculation.
  • Explain the conclusion and any stated limitation.

Problem 35

An inhibitor resembles the substrate and occupies the active site. What mechanism fits? Show the reasoning, not just the conclusion.
Hints

A falling rate does not establish the exact molecular mechanism without additional tests.

Answer and explanation

Competitive inhibition is consistent with competing for the substrate-binding site.

Problem 36

Does an enzyme supply all the energy required by an unfavorable reaction?
Hints

State what the supplied observations or conditions establish, and separate that from any assumption.

Answer and explanation

No. It lowers activation barriers; it does not change the overall free-energy requirement or create an energy source.

Problem 37

An optimum is a result under specified conditionsAn optimum is a result under specified conditionsInitial reaction rate (model units/min)04812102030405060Temperature (°C)The supplied optimum is near 40 °C under these test conditions.
Original invented initial-rate versus temperature example, not a measured universal enzyme optimum or storage recommendation.
Interpret the supplied visual. Would this curve justify storing all enzymes at 40 °C indefinitely?
Answer and explanation

No. It describes an initial-rate example under selected conditions; long-term stability and other enzyme identities require different evidence.

A reaction rate measures change per time; an initial rate uses a defined early interval before large substrate depletion or product buildup. Warming can increase productive collisions, but higher temperature can disrupt an enzyme’s fold and stability. The balance creates a condition-dependent optimum. pH, enzyme identity, exposure duration and substrate conditions matter too. Low rate in the cold is not automatically denaturation; activity may return on warming. A steep loss after heating needs suitable recovery and structural evidence before its cause is assigned.

No. It describes an initial-rate example under selected conditions; long-term stability and other enzyme identities require different evidence.

Response criteria

  • Read the structures, axes, directions and units correctly.
  • Connect the evidence with the biological mechanism.
  • Respect stated model assumptions and distinguish an observation from a further inference.

Problem 38

An enzyme has the same reactant and product energy levels with and without a catalyst, but a lower pathway peak with it. Explain rate, equilibrium and energy implications.
Answer and explanation

The lower barrier can increase the approach rate in both directions. It does not by itself change the equilibrium or net free-energy change, and an unfavorable isolated process still needs suitable coupling or conditions.

The lower barrier can increase the approach rate in both directions. It does not by itself change the equilibrium or net free-energy change, and an unfavorable isolated process still needs suitable coupling or conditions.

Response criteria

  • Use the stated measurements or conditions, with correct units.
  • Connect the result to the biological mechanism or evidence relationship.
  • Identify the assumption, model limit or further evidence requested.

Problem 39

A reaction that combines small molecules into a larger one is a
  1. freezing
  2. melting
  3. decomposition reaction
  4. synthesis reaction
Answer and explanation

synthesis reaction

Synthesis joins smaller molecules; its energy balance depends on the full reaction and may require coupling.

Problem 40

What molecule do cells use as their main energy 'currency'?
  1. ATP
  2. Water
  3. DNA
  4. Glucose
Answer and explanation

ATP

ATP is the cell's energy currency. Glucose is an energy source, but its energy is banked into ATP before the cell spends it.

Problem 41

When ATP releases energy for the cell to use, it becomes
  1. DNA
  2. ADP + a phosphate group
  3. glucose
  4. a protein
Answer and explanation

ADP + a phosphate group

ATP hydrolysis forms ADP and phosphate; the overall reaction can release free energy under cellular conditions.

Problem 42

An active-transport pump uses 1 ATP to move 3 sodium ions out of a cell. How many ATP molecules are needed to pump 3,600 sodium ions?
Answer and explanation

1200 ATP

3,600 ions ÷ 3 ions per ATP = 1,200 ATP.

Problem 43

Explain how a decomposition reaction and a synthesis reaction can be linked together by ATP inside a cell.
Answer and explanation

Energy-releasing metabolism supports ATP production. ATP hydrolysis coupled to synthesis or transport can make the combined process favorable. No energy is created, and the full reactions, not bond breaking alone, determine the balance.

Problem 44

Explain why saying ATP provides energy because its bond is broken is incomplete. Explain the reasoning in your own words.
Answer and explanation

Energy availability comes from the whole reaction and coupling mechanism, not bond breaking by itself.

Bond breaking requires an input of energy.

The full reaction forms new interactions and products; its overall free-energy change can be favorable and coupled to work.

Response criteria

  • Use the stated conditions.
  • Show the evidence or calculation.
  • Explain the conclusion and any stated limitation.

Problem 45

Why do living cells need ongoing inputs even though energy is conserved? Show the reasoning, not just the conclusion.
Hints

Energy is transferred through a mechanism, not created by the enzyme.

Answer and explanation

Energy disperses to surroundings; cells need usable energy to maintain organization and drive processes.

Problem 46

A pathway occurs faster with an enzyme. Does this prove its equilibrium shifted?
Hints

State what the supplied observations or conditions establish, and separate that from any assumption.

Answer and explanation

No. Catalysis speeds approach to equilibrium without changing the equilibrium determined by the reaction and conditions.

Problem 47

A favorable total is useful only when the processes are connectedA favorable total is useful only when the processes are connectedSupplied magnitudes of free-energy changeSynthesis alone: needs12Hydrolysis: can supply20Coupled net: +12 + (−20) = −8 model units.A reaction mechanism must connect the processes.
Original signed free-energy teaching cases with invented units, not a physiological ATP constant.
Interpret the supplied visual. If synthesis needs +25 and the coupled hydrolysis provides −20, is the supplied net favorable?
Answer and explanation

The total is +5 model units, so this stated pair alone is not favorable; additional coupling or changed conditions would be needed.

An endergonic process requires a positive free-energy change under the stated conditions; an exergonic process has a negative change. Coupling links processes through a mechanism so their combined outcome can proceed. Here a +12 synthesis step and −20 hydrolysis contribution sum to −8 model units. This accounting does not say that two unconnected reactions in neighboring beakers drive each other. Enzymes or molecular machines must link the relevant changes, and actual concentrations and pathways determine feasibility and rate.

The total is +5 model units, so this stated pair alone is not favorable; additional coupling or changed conditions would be needed.

Response criteria

  • Read the structures, axes, directions and units correctly.
  • Connect the evidence with the biological mechanism.
  • Respect stated model assumptions and distinguish an observation from a further inference.

Problem 48

A coupled synthesis needs +18 free-energy units and its linked hydrolysis contributes −26. Calculate the net, then explain why a catalyst alone cannot replace the coupling.
Answer and explanation

The net is −8 units under the supplied conditions. A catalyst can lower the activation barrier but does not make the isolated +18 process favorable by changing its endpoint free-energy balance.

The net is −8 units under the supplied conditions. A catalyst can lower the activation barrier but does not make the isolated +18 process favorable by changing its endpoint free-energy balance.

Response criteria

  • Use the stated measurements or conditions, with correct units.
  • Connect the result to the biological mechanism or evidence relationship.
  • Identify the assumption, model limit or further evidence requested.

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