Matter, Mixtures & Water Properties — Chapter Practice, Grade 6
How can particle models and measurements account for matter across changes? Which parts of a stated sand–salt–water mixture can a filter separate, and where does the matter go?
Problem 1
Answer and explanation
No. Container shape affects height; compare volume with an appropriate method before claiming loss.
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Problem 2
Answer and explanation
Particle spacing decreases; the model does not require individual particles to shrink.
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Problem 3
Answer and explanation
No. Surface evaporation occurs below boiling; its rate depends on conditions such as temperature, airflow, and exposed area.
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Problem 4
Answer and explanation
The same water remains within the boundary; state and arrangement change, not the amount of matter.
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Problem 5
Answer and explanation
Melting in the closed sample changes arrangement while retaining its 50 g of water. The open dish loses 6 g from the measured liquid; evaporation is a possible pathway into the air. The water has not been destroyed. Without further records, the mass loss alone does not exclude a spill or specify the evaporation rate over a particular time.
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Problem 6
Answer and explanation
Visibility is not the definition of matter. Gas particles have mass and occupy space; a suitable comparison or measurement can show these properties.
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Problem 7
- Solid particles are completely motionless.
- particle model: A simplified explanation of matter using tiny moving constituents and their arrangement.
- A gas has no mass because it is invisible.
- One illustrative result establishes every real condition and needs no further evidence.
Answer and explanation
particle model: A simplified explanation of matter using tiny moving constituents and their arrangement.
A simplified explanation of matter using tiny moving constituents and their arrangement. Melting in the closed sample changes arrangement while retaining its 50 g of water. The open dish loses 6 g from the measured liquid; evaporation is a possible pathway into the air. The water has not been destroyed. Without further records, the mass loss alone does not exclude a spill or specify the evaporation rate over a particular time.
Problem 8
- A gas has no mass because it is invisible.
- Solid particles are completely motionless.
- evaporation: A change from liquid to gas at a surface, possible below boiling.
- One illustrative result establishes every real condition and needs no further evidence.
Answer and explanation
evaporation: A change from liquid to gas at a surface, possible below boiling.
A change from liquid to gas at a surface, possible below boiling. Melting in the closed sample changes arrangement while retaining its 50 g of water. The open dish loses 6 g from the measured liquid; evaporation is a possible pathway into the air. The water has not been destroyed. Without further records, the mass loss alone does not exclude a spill or specify the evaporation rate over a particular time.
Problem 9
Answer and explanation
Different substances can share that appearance. Additional appropriate measurements and known source information are needed.
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Problem 10
Answer and explanation
No. A physical change can be difficult to undo; evidence about substance identity is more relevant.
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Problem 11
Answer and explanation
60 ÷ 20 = 3 g/cm³; size changed but the ratio stayed the same.
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Problem 12
Answer and explanation
It distinguishes possibilities that the first property cannot separate; the conclusion should still match the available evidence.
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Problem 13
Answer and explanation
48 ÷ 24 = 2 g/cm³. Reshaping changes outline while the modeled material and measured mass/volume remain. It is described as physical because no new substance is formed in this model, not simply because the shape might be restored.
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Problem 14
Answer and explanation
No. Blue depends on the observation conditions, and heavy depends on sample size and comparison. Measured properties and additional evidence are needed.
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Problem 15
- The largest sample must have the greatest density.
- Every change that is hard to reverse must be chemical.
- physical property: A characteristic measured or observed without changing chemical identity.
- One illustrative result establishes every real condition and needs no further evidence.
Answer and explanation
physical property: A characteristic measured or observed without changing chemical identity.
A characteristic measured or observed without changing chemical identity. 48 ÷ 24 = 2 g/cm³. Reshaping changes outline while the modeled material and measured mass/volume remain. It is described as physical because no new substance is formed in this model, not simply because the shape might be restored.
Problem 16
- One illustrative result establishes every real condition and needs no further evidence.
- Every change that is hard to reverse must be chemical.
- The largest sample must have the greatest density.
- density: Mass per unit volume under stated conditions.
Answer and explanation
density: Mass per unit volume under stated conditions.
Mass per unit volume under stated conditions. 48 ÷ 24 = 2 g/cm³. Reshaping changes outline while the modeled material and measured mass/volume remain. It is described as physical because no new substance is formed in this model, not simply because the shape might be restored.
Problem 17
Answer and explanation
The number of each kind of atom. New combinations form, but the represented atoms remain accounted for.
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Problem 18
Answer and explanation
No. A physical state change can also create bubbles; the gas identity and process need further evidence.
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Problem 19
Answer and explanation
No. It crossed the chosen boundary as gas. The mass inside differs from the mass of the complete accounted system.
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Problem 20
Answer and explanation
The conclusion depends on the record’s stated method and boundaries; illustrative data are not proof that a real procedure was performed.
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Problem 21
Answer and explanation
Two A atoms and two B atoms are represented on each side. Their combinations change from A₂ and B₂ to two AB particles. The closed-system mass remains 60 g. This model directly states a rearrangement; a color change alone would not supply the same evidence of substance identity.
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Problem 22
Answer and explanation
No. Oxygen from the surroundings enters the material. Account for both the metal and the added oxygen rather than treating the exposed object as a closed system.
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Problem 23
- One illustrative result establishes every real condition and needs no further evidence.
- Any bubbles or color change conclusively prove a chemical reaction.
- A mass change inside an open container means matter was destroyed.
- chemical change: A change that forms substances with different chemical identities.
Answer and explanation
chemical change: A change that forms substances with different chemical identities.
A change that forms substances with different chemical identities. Two A atoms and two B atoms are represented on each side. Their combinations change from A₂ and B₂ to two AB particles. The closed-system mass remains 60 g. This model directly states a rearrangement; a color change alone would not supply the same evidence of substance identity.
Problem 24
- conservation of mass: Matter remains accounted for when the complete relevant system and exchanges are included.
- Any bubbles or color change conclusively prove a chemical reaction.
- A mass change inside an open container means matter was destroyed.
- One illustrative result establishes every real condition and needs no further evidence.
Answer and explanation
conservation of mass: Matter remains accounted for when the complete relevant system and exchanges are included.
Matter remains accounted for when the complete relevant system and exchanges are included. Two A atoms and two B atoms are represented on each side. Their combinations change from A₂ and B₂ to two AB particles. The closed-system mass remains 60 g. This model directly states a rearrangement; a color change alone would not supply the same evidence of substance identity.
Problem 25
Answer and explanation
No. Its particles remain in the solution, contributing mass and properties even though they are not individually visible.
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Problem 26
Answer and explanation
No. The solute and volume both double, leaving the same ratio under this definition.
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Problem 27
Answer and explanation
Dissolved salt passes through with the water. Removing visible sand does not establish pure water.
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Problem 28
Answer and explanation
No. Identify retained material, loss pathways, and measurement uncertainty before assigning a cause.
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Problem 29
Answer and explanation
After removing 3 g sand, 105 g of salt solution remains in the idealized model. After water enters the air, 5 g salt remains. The water is transferred, not destroyed. Real recovery may be incomplete; these assumptions do not show that the liquid was safe to drink.
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Problem 30
Answer and explanation
No. Filter pore size and other treatment properties matter. Visible clarity alone cannot establish removal of dissolved substances or drinking safety.
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Problem 31
- solution: A mixture with dissolved particles distributed through a solvent at the particle scale.
- A dissolved substance has ceased to exist.
- Removing visible particles automatically produces safe pure water.
- One illustrative result establishes every real condition and needs no further evidence.
Answer and explanation
solution: A mixture with dissolved particles distributed through a solvent at the particle scale.
A mixture with dissolved particles distributed through a solvent at the particle scale. After removing 3 g sand, 105 g of salt solution remains in the idealized model. After water enters the air, 5 g salt remains. The water is transferred, not destroyed. Real recovery may be incomplete; these assumptions do not show that the liquid was safe to drink.
Problem 32
- A dissolved substance has ceased to exist.
- solute: The substance dissolved in a solution.
- Removing visible particles automatically produces safe pure water.
- One illustrative result establishes every real condition and needs no further evidence.
Answer and explanation
solute: The substance dissolved in a solution.
The substance dissolved in a solution. After removing 3 g sand, 105 g of salt solution remains in the idealized model. After water enters the air, 5 g salt remains. The water is transferred, not destroyed. Real recovery may be incomplete; these assumptions do not show that the liquid was safe to drink.
Problem 33
Answer and explanation
The 20 mL object: 12 ÷ 20 = 0.6 g/mL. The second is 2 g/mL; the equal masses do not imply equal floating behavior.
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Problem 34
Answer and explanation
It changes the object’s geometry and enclosed air, allowing different displacement and average density.
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Problem 35
Answer and explanation
No. Mass stays 90 g while volume and density change with arrangement.
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Problem 36
Answer and explanation
No. A surface force can matter for a small object; density and buoyancy must be considered separately.
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Problem 37
Answer and explanation
Ice density is 0.9 g/mL. The hull displaces 60 g of modeled water, consistent with buoyancy balancing its weight. A hollow hull can float because of its overall geometry and average density; a compact piece of the same material may behave differently. Neither result is a rule for every temperature or liquid.
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Problem 38
Answer and explanation
Ask for mass, volume or displacement, shape, enclosed air, and the liquid’s properties. Size alone does not determine average density or buoyancy.
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Problem 39
- The heaviest or largest object must always sink.
- buoyancy: The upward force a fluid exerts on an immersed or partly immersed object.
- Ice floats because freezing removes its mass.
- One illustrative result establishes every real condition and needs no further evidence.
Answer and explanation
buoyancy: The upward force a fluid exerts on an immersed or partly immersed object.
The upward force a fluid exerts on an immersed or partly immersed object. Ice density is 0.9 g/mL. The hull displaces 60 g of modeled water, consistent with buoyancy balancing its weight. A hollow hull can float because of its overall geometry and average density; a compact piece of the same material may behave differently. Neither result is a rule for every temperature or liquid.
Problem 40
- Ice floats because freezing removes its mass.
- The heaviest or largest object must always sink.
- surface tension: An effect of particle interactions at a liquid surface that can influence small surface objects.
- One illustrative result establishes every real condition and needs no further evidence.
Answer and explanation
surface tension: An effect of particle interactions at a liquid surface that can influence small surface objects.
An effect of particle interactions at a liquid surface that can influence small surface objects. Ice density is 0.9 g/mL. The hull displaces 60 g of modeled water, consistent with buoyancy balancing its weight. A hollow hull can float because of its overall geometry and average density; a compact piece of the same material may behave differently. Neither result is a rule for every temperature or liquid.