Solving Quadratic Equations — Challenge

Four methods, one goal. Factoring is fastest when it works; the quadratic formula always works.

What these problems cover

These questions use 10 ideas from the course. Follow any of them for a definition, where it is taught, and what it leads to.

Problem 1

What is the positive solution of x2=49?

  1. 14
  2. 7
  3. 24.5
  4. 49
  5. 2401
Worked answer

7

Taking square roots of both sides gives x = 7 or x = -7.

The positive one is 7.

Halving 49 would give 24.5, which confuses squaring with doubling.

Problem 2

What is the larger solution of x2-5x+6=0?

  1. 1
  2. 2
  3. 3
  4. 5
  5. 6
Worked answer

3

Factorise: two numbers multiplying to 6 and adding to -5 are -2 and -3, so (x-2)(x-3) = 0.

A product is zero only when a factor is zero, so x = 2 or x = 3.

The larger solution is 3.

Problem 3

What is the positive solution of x2+2x-8=0?

  1. -4
  2. 1
  3. 2
  4. 4
  5. 8
Worked answer

2

Two numbers multiplying to -8 and adding to 2 are 4 and -2, so (x+4)(x-2) = 0.

The solutions are x = -4 and x = 2.

The positive one is 2.

Problem 4

What is the positive solution of x2-9=0?

  1. 4.5
  2. 3
  3. 9
  4. 81
  5. -3
Worked answer

3

Rearranging gives x2 = 9.

So x = 3 or x = -3, and the positive solution is 3.

Equivalently, factorising as (x-3)(x+3) = 0 gives the same two roots.

Problem 5

What is the positive solution of 2x2=18?

  1. 6
  2. 9
  3. 3
  4. 36
  5. 4.5
Worked answer

3

Divide both sides by 2 first: x2 = 9.

Then x = 3 or x = -3, so the positive solution is 3.

Taking the square root of 18 before dividing is the common error.

Problem 6

What is the solution of x2+6x+9=0?

  1. 3
  2. -3
  3. -9
  4. 9
  5. No real solution
Worked answer

-3

The left side is a perfect square: x2+6x+9 = (x+3)2.

So (x+3)2 = 0, which gives x+3 = 0 and x = -3.

There is only one solution here, because the two roots coincide.

Problem 7

What is the sum of the solutions of x2-4x+3=0?

  1. 2
  2. 3
  3. 4
  4. -4
  5. 7
Worked answer

4

Factorising gives (x-1)(x-3) = 0, so the solutions are 1 and 3.

Their sum is 1+3 = 4.

This matches the general rule that the roots of x2+bx+c sum to -b, here -(-4) = 4.

Problem 8

What is the product of the solutions of x2+x-12=0?

  1. 12
  2. -12
  3. -1
  4. 1
  5. 7
Worked answer

-12

Two numbers multiplying to -12 and adding to 1 are 4 and -3, so (x+4)(x-3) = 0.

The solutions are -4 and 3, and their product is -12.

This matches the rule that the roots of x2+bx+c multiply to c.

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