The Mole & Molar Mass · Grade 11 Science

Chapter: Reactions, Moles & Composition

The Mole & Molar Mass

Learning goals

Readings for this unit

Before this unit

Atomic masses and unit cancellation.

Use the detailed parent plan: two core 50–60-minute sessions per focused unit, with a third assigned for selected calculation/modeling topics. First study the core explanation and Parts 1–2 with their figures/checks; next study Parts 3–4, the whole-unit application, worked cases, varied practice and exit check. Attempt reasoning before opening guidance. Extend time when actual understanding requires it; investigations and chapter assessments have separate sessions.

Start with something to explain

Does one mole always mean the same mass?

Illustrative evidence case. One mole of helium atoms and one mole of CO₂ molecules have equal entity counts but different mass.

A mole counts specified entities rather than a fixed massA mole counts specified entities rather than a fixed massAmountEntity namedEntity count1 mol HeHe atoms6.02214076×10²³1 mol H₂OH₂O molecules6.02214076×10²³1 mol NaClNaCl formula units6.02214076×10²³The same mole amount need not have the same mass or atom count.
Original entity-count table using the exact SI Avogadro constant; NaCl formula units do not imply discrete NaCl molecules in a crystal.

Notice and wonder

Record two observations using the stated quantities or relationships. Keep observations separate from possible causes. Write one question that a new measurement could help answer.

Does one mole always mean the same mass?

Your first model

Label the counted entity and its composition before comparing samples.

Build the language from the idea

mole (mol)
The chemist's counting unit: one mole is exactly 6.022 × 10²³ particles of a substance.
Avogadro's number
The exact entity count per mole, 6.02214076×10²³; the Avogadro constant carries unit mol⁻¹.
molar mass
The mass of one mole of a substance in grams, numerically equal to the sum of the atomic masses in its formula (g/mol).
atomic mass
The average mass of an atom of an element, in atomic mass units, read from the periodic table.
representative particle
The basic unit being counted — an atom for an element, a molecule for a molecular compound, or a formula unit for an ionic compound.

Atoms are impossibly small and unimaginably numerous — a single sip of water holds trillions of trillions of molecules — yet reactions happen atom by atom, in fixed whole-number ratios. Chemists face a puzzle: how do you count particles you can never see, in a lab where the only tool is a balance that reads grams? The answer is one of the most powerful ideas in all of chemistry: the mole, a bridge between the invisible world of atoms and the visible world of grams you can actually weigh.

The mole is the SI unit of amount of substance: one mole contains exactly 6.02214076×10²³ specified entities. A dozen is a helpful counting analogy, but a mole is a physical amount unit and must name what is counted: atoms, molecules, ions, electrons or formula units. The exact constant does not make a measured sample mass infinitely precise. For one mole of water molecules, the formula also implies two moles of hydrogen atoms and one mole of oxygen atoms.

A mole counts specified entities rather than a fixed massA mole counts specified entities rather than a fixed massAmountEntity namedEntity count1 mol HeHe atoms6.02214076×10²³1 mol H₂OH₂O molecules6.02214076×10²³1 mol NaClNaCl formula units6.02214076×10²³The same mole amount need not have the same mass or atom count.
Original entity-count table using the exact SI Avogadro constant; NaCl formula units do not imply discrete NaCl molecules in a crystal.

That is the quiet genius of the system. The molar mass of a substance — the mass of one mole of it — is numerically equal to the sum of the atomic masses in its formula, just with the unit grams per mole. Carbon's atomic mass is 12.01, so one mole of carbon atoms weighs 12.01 g. To find the molar mass of a compound, you add up the molar masses of every atom in the formula. Water, H₂O, comes to 2(1.01) + 16.00 = 18.02 g/mol, which means a mere 18 grams of water — a little over a tablespoon — already contains a full mole, 6.022 × 10²³ molecules.

Molar mass combines composition with a chosen atomic-mass referenceMolar mass combines composition with a chosen atomic-mass referenceMₘ[Ca(OH)₂] = 40.08 + 2(16.00 + 1.008)= 74.096 g/mol ≈ 74.10 g/molCounts: Ca = 1, O = 2, H = 2Molar mass uses the formula’s full atom inventory.
Original calculation using displayed rounded atomic-weight values; final rounding follows the chosen reference convention.

With molar mass in hand, converting between grams and moles becomes ordinary arithmetic. To go from a measured mass to a number of moles, you divide by the molar mass: moles = mass ÷ molar mass. To go the other way, from moles back to a mass you could weigh out, you multiply: mass = moles × molar mass. Molar mass acts like an exchange rate between two currencies — grams and moles — and every stoichiometry problem you meet later leans on this single conversion.

Moles also link to the actual count of particles. Because one mole is exactly 6.02214076 × 10²³ specified entities by the SI definition, you multiply moles by Avogadro's number to get the number of representative particles — atoms, molecules, or formula units — and you divide by it to go back. So there is a two-step highway running in both directions: mass ⇄ moles ⇄ particles, with molar mass governing the first stretch and Avogadro's number governing the second. Master that map and you can start from any one of the three and reach the other two.

Units connect measured mass to amount and entity countUnits connect measured mass to amount and entity count36.0 g H₂O2.00 mol H₂O÷ 18.0 g/mol2.00 mol × 6.022×10²³ molecules/mol= 1.20×10²⁴ H₂O molecules
Original rounded conversion using a supplied water molar mass; entity count precision reflects the measured mass and chosen school constants.

This is not abstract bookkeeping — it is how real chemistry gets done. A pharmacist scaling a drug, an engineer sizing a fuel tank, and a factory mixing fertilizer all think in moles, because reactions obey mole ratios, not gram ratios. The mole is what lets a chemist weigh out a pinch of powder and know, to the particle, how many molecules are on the balance. It is the counting unit that turns the conservation of atoms into a calculation you can actually run, and it sets up everything in the next two lessons on stoichiometry.

Model check: A mole counts entities; it is not a fixed number of grams. Molar mass 18 g/mol, so 36/18=2 mol; identify molecules as the counted entities.

Build your understanding

Use the detailed parent plan: two core 50–60-minute sessions per focused unit, with a third assigned for selected calculation/modeling topics. First study the core explanation and Parts 1–2 with their figures/checks; next study Parts 3–4, the whole-unit application, worked cases, varied practice and exit check. Attempt reasoning before opening guidance. Extend time when actual understanding requires it; investigations and chapter assessments have separate sessions.

Part 1 · Name the entity counted by a mole

The mole is the SI unit of amount of substance. One mole contains exactly 6.02214076×10²³ specified entities, the Avogadro constant in mol⁻¹. Always name the entity: atoms, molecules, ions, electrons or formula units. One mole of water molecules contains two moles of hydrogen atoms and one mole of oxygen atoms, not one mole of total atoms. A mole of helium and a mole of water have equal specified-entity counts but different masses and compositions.

A mole counts specified entities rather than a fixed massA mole counts specified entities rather than a fixed massAmountEntity namedEntity count1 mol HeHe atoms6.02214076×10²³1 mol H₂OH₂O molecules6.02214076×10²³1 mol NaClNaCl formula units6.02214076×10²³The same mole amount need not have the same mass or atom count.
Original entity-count table using the exact SI Avogadro constant; NaCl formula units do not imply discrete NaCl molecules in a crystal.

Read the visual model

Identify the labeled structures and units, then trace the arrows or compare values under the caption’s stated conditions. Separate the displayed evidence from a further inference. Write your reasoning before opening the guidance.

How many moles of total atoms are represented by one mole of H₂O molecules?

Visual reasoning — after your attempt

Three moles of atoms: two moles of hydrogen atoms plus one mole of oxygen atoms.

One mole contains exactly 6.02214076×10²³ specified entities. State whether those entities are atoms, molecules, ions, or formula units. A mole is a counting unit, not a fixed mass or a type of particle. Different substances have different mass per mole.

One mole of H₂O molecules includes two moles of H atoms and one mole of O atoms. Do not call a mole of water one mole of total atoms.

Pause and explain

Why must the entity be named?

Check your reasoning after answering

The same numerical mole amount can count different entities. Molecules, atoms, ions, and formula units give different composition interpretations.

Part 2 · Find molar mass from the formula

Molar mass is mass per mole of specified substance. Add the contributions of every atom in its formula, including parentheses and hydrates when present. Ca(OH)₂ contains one calcium, two oxygen and two hydrogen atoms per formula unit, so the hydroxide group is counted twice. Atomic-weight values have stated precision and isotope-composition conventions; choose a consistent supplied table. Molar mass is written in g/mol and is different from the molarity of a solution.

Molar mass combines composition with a chosen atomic-mass referenceMolar mass combines composition with a chosen atomic-mass referenceMₘ[Ca(OH)₂] = 40.08 + 2(16.00 + 1.008)= 74.096 g/mol ≈ 74.10 g/molCounts: Ca = 1, O = 2, H = 2Molar mass uses the formula’s full atom inventory.
Original calculation using displayed rounded atomic-weight values; final rounding follows the chosen reference convention.

Read the visual model

Identify the labeled structures and units, then trace the arrows or compare values under the caption’s stated conditions. Separate the displayed evidence from a further inference. Write your reasoning before opening the guidance.

Why must both O and H be multiplied by two in Ca(OH)₂?

Visual reasoning — after your attempt

The subscript outside parentheses multiplies the entire OH group, not only the immediately preceding hydrogen.

Add atomic-mass contributions using every subscript and repeated group. Molar mass in g/mol converts amount to mass. A table atomic mass and a compound molar mass use related numerical contributions but describe different quantities and units.

Using H=1.0 and O=16.0, water has M=18.0 g/mol. Calcium hydroxide needs two O and two H contributions as well as calcium.

Pause and explain

What does 18.0 g/mol mean for this water model?

Check your reasoning after answering

It gives mass per mole of water molecules. It is not the mass of one molecule or the number of atoms in a molecule.

Part 3 · Convert through units rather than memorized arrows

Convert mass to amount using n=m/Mₘ, then multiply amount by the Avogadro constant to obtain specified-entity count. Each conversion factor must cancel the previous unit and retain the entity name. The selected 18.0 g/mol water value is a rounded school input; using it consistently gives 2.00 mol from 36.0 g and approximately 1.20×10²⁴ water molecules. Mole amount is not itself a mass or volume, so do not skip the chemical composition step.

Units connect measured mass to amount and entity countUnits connect measured mass to amount and entity count36.0 g H₂O2.00 mol H₂O÷ 18.0 g/mol2.00 mol × 6.022×10²³ molecules/mol= 1.20×10²⁴ H₂O molecules
Original rounded conversion using a supplied water molar mass; entity count precision reflects the measured mass and chosen school constants.

Read the visual model

Identify the labeled structures and units, then trace the arrows or compare values under the caption’s stated conditions. Separate the displayed evidence from a further inference. Write your reasoning before opening the guidance.

What would be wrong with multiplying 36.0 g directly by a number in molecules/mol?

Visual reasoning — after your attempt

The grams would not cancel the mole denominator. First convert mass to moles with the substance’s molar mass.

Use n=m/M for mass to moles and N=nNₐ for moles to entities. Choose factors to cancel units. If the question asks constituent atoms, add the formula ratio after converting to molecular amount. Keep exact ratios separate from measured precision.

9.0 g water at 18.0 g/mol is 0.50 mol H₂O, containing 1.0 mol H atoms. The hydrogen amount uses a 2: 1 formula ratio, not a separate mass division.

Pause and explain

Why divide mass by molar mass?

Check your reasoning after answering

g divided by g/mol leaves mol. Multiplying mass by molar mass would give inappropriate units for an amount.

Part 4 · Use reasonable scale and composition checks

A formula supplies exact atom-number ratios for the named entity. Half a mole of CO₂ molecules contains half a mole of carbon atoms and one mole of oxygen atoms; their masses are not in a 1:2 ratio because carbon and oxygen atoms have different masses. Use both unit and entity labels to check a conversion. A result can look numerically large and still be reasonable for particle counts, while a mass fraction greater than one signals a likely composition or unit error.

A scale check asks what is being counted at each stepA scale check asks what is being counted at each stepQuantity in 0.50 mol CO₂AmountCO₂ molecules0.50 molC atoms0.50 molO atoms1.0 molTotal atoms1.5 molFormula ratios apply to atom counts, not directly to mass fractions.
Original selected CO₂ amount inventory; the 0.50 mol starting amount is an illustrative input.

Read the visual model

Identify the labeled structures and units, then trace the arrows or compare values under the caption’s stated conditions. Separate the displayed evidence from a further inference. Write your reasoning before opening the guidance.

Why does two oxygen atoms per carbon atom not mean twice as much oxygen mass as carbon mass?

Visual reasoning — after your attempt

Atom counts must be weighted by their different molar masses; count ratios and mass ratios are different quantities.

A mass equal to one molar mass should give one mole. Particle numbers should be enormous for gram-scale samples, while single-particle masses are tiny. Check formula ratios independently so correct arithmetic does not conceal counting the wrong entity.

A calculation reporting 18 g water as 18 molecules fails the scale check. A result of one mole water but one mole hydrogen atoms fails the composition check.

Pause and explain

Which two checks help catch a correct-looking wrong answer?

Check your reasoning after answering

Check magnitude against molar mass and Avogadro’s constant, and check that the named entities match the formula ratios.

Apply the whole unit · Count water molecules and constituent atoms

Illustrative sample mass is 9.0 g pure water. Use M(H₂O)=18.0 g/mol and Nₐ≈6.02×10²³ mol⁻¹.

Your task

Find water amount, molecule number, and the numbers of H and O atoms. Show unit cancellation and explain why the particle totals do not mean free hydrogen and oxygen gases are present.

What your response should show

  • Choose the appropriate chemical model or relationship and state its conditions.
  • Show substitutions, units, particle or charge counts, and intermediate reasoning as relevant.
  • Use supplied evidence to justify the conclusion; distinguish observation from inference.
  • Identify a meaningful limitation, uncertainty, or next measurement.
Response guidance — after your attempt
  1. n=9.0 g/(18.0 g/mol)=0.50 mol H₂O.

  2. N≈0.50×6.02×10²³≈3.0×10²³ water molecules to two significant figures.

  3. Hydrogen atoms≈6.0×10²³; oxygen atoms≈3.0×10²³.

The atom counts describe atoms bound within water molecules. They do not imply free H₂ or O₂ in the sample. The conversion assumes purity and the supplied molar-mass approximation; entity labels, formula ratios, and appropriate precision are part of the answer rather than optional annotations.

Scientific references and source-model foundations

Parent / teacher teaching notes

Require labeled conversion factors. Use mass=moles×molar mass to verify the result, then check constituent-atom ratios. Ask the learner to explain each particle symbol, axis, unit and arrow before calculating. Distinguish hypothetical models and calculated curves from measured records. Public OpenSciEd excerpts here are selected foundation prompts, not complete high-school teacher editions or an endorsement. All required advanced explanations and practice are provided locally.

The conversion map: mass ⇄ moles ⇄ particlesMass(grams)Moles(mol)Particlesatoms / molecules÷ molar mass× molar mass× 6.022×10²³÷ 6.022×10²³Molar mass links mass and moles; Avogadro's number links moles and particles.Moles sit in the middle — every conversion passes through them.
The mole sits at the center of every chemical count: divide or multiply by molar mass to reach mass, and by Avogadro's number to reach particles.

The key idea

One mole contains exactly 6.02214076×10²³ specified entities. Molar mass connects amount with mass, and formula composition connects molecule/formula-unit counts with constituent atom or ion counts.

Molar Mass

M = sum of the atomic masses of every atom in the formula

M is the molar mass in grams per mole (g/mol); read each element's atomic mass from the periodic table and multiply by how many of that atom appear.

Moles from Mass

n = m ÷ M

n = amount in moles (mol), m = mass (g), M = molar mass (g/mol). Rearranged, mass m = n × M.

Particles from Moles

N = n × 6.022 × 10²³

N = number of representative particles (atoms, molecules, or formula units), n = moles, and 6.022 × 10²³ is Avogadro's number.

Worked examples

Example 1

Calculate the molar mass of sulfuric acid, H₂SO₄. (Atomic masses: H = 1.01, S = 32.07, O = 16.00 g/mol.)
  1. Count the atoms in the formula: 2 hydrogen, 1 sulfur, 4 oxygen.
  2. Multiply each count by its atomic mass: H = 2 × 1.01 = 2.02; S = 1 × 32.07 = 32.07; O = 4 × 16.00 = 64.00.
  3. Add the totals: 2.02 + 32.07 + 64.00 = 98.09 g/mol.
Answer: 98.09 g/mol

Example 2 · Worked application

A sample contains 18.0 g of H₂O. Use molar mass 18.0 g/mol and Nₐ=6.02×10²³ mol⁻¹ to find molecules.
  1. Moles=18.0/18.0=1.00 mol.
  2. Multiply by Avogadro's constant to count molecules.
  3. Each molecule has three atoms, so molecules and total atoms are different counts.
Answer: 6.02×10²³ water molecules.
Check the reasoning

Identify the requested entity before applying the mole conversion.

Example 3

How many moles, and how many molecules, are in 54.06 g of water? (Molar mass H₂O = 18.02 g/mol; Avogadro's number = 6.022 × 10²³.)
  1. Convert mass to moles by dividing by molar mass: 54.06 g ÷ 18.02 g/mol = 3.00 mol.
  2. Convert moles to molecules by multiplying by Avogadro's number: 3.00 mol × 6.022 × 10²³ = 1.807 × 10²⁴ molecules.
  3. So 54.06 g of water is 3.00 mol, containing about 1.807 × 10²⁴ molecules.
Answer: 3.00 mol, which is about 1.807 × 10²⁴ molecules

Example 4 · Find and fix the mistake

Context: A sample contains 18.0 g of H₂O. Use molar mass 18.0 g/mol and Nₐ=6.02×10²³ mol⁻¹ to find molecules. A student claims: “One mole of every substance has the same mass.” Evaluate the claim and write a corrected explanation.
  1. Test the claim against the stated conditions: Identify the requested entity before applying the mole conversion.
  2. One mole has the same number of entities; mass depends on the substance's molar mass.
Answer: One mole has the same number of entities; mass depends on the substance's molar mass.
Check the reasoning

Identify the requested entity before applying the mole conversion.

Example 5 · Reason from the visual model

Units connect measured mass to amount and entity countUnits connect measured mass to amount and entity count36.0 g H₂O2.00 mol H₂O÷ 18.0 g/mol2.00 mol × 6.022×10²³ molecules/mol= 1.20×10²⁴ H₂O molecules
Original rounded conversion using a supplied water molar mass; entity count precision reflects the measured mass and chosen school constants.
What would be wrong with multiplying 36.0 g directly by a number in molecules/mol?
  1. Convert mass to amount using n=m/Mₘ, then multiply amount by the Avogadro constant to obtain specified-entity count. Each conversion factor must cancel the previous unit and retain the entity name. The selected 18.0 g/mol water value is a rounded school input; using it consistently gives 2.00 mol from 36.0 g and approximately 1.20×10²⁴ water molecules. Mole amount is not itself a mass or volume, so do not skip the chemical composition step.
  2. The grams would not cancel the mole denominator. First convert mass to moles with the substance’s molar mass.
Answer: The grams would not cancel the mole denominator. First convert mass to moles with the substance’s molar mass.
Check the reasoning

Original rounded conversion using a supplied water molar mass; entity count precision reflects the measured mass and chosen school constants.

Avoid these mistakes

Check your understanding

Using H=1 and O=16, how many moles are in 36 g water?

Discuss the answer

Molar mass 18 g/mol, so 36/18=2 mol; identify molecules as the counted entities.

Return to the phenomenon

Return to the initial case. Does one mole always mean the same mass? Revise your drawing or explanation using two named ideas and one stated limitation.

Compare explanations after your attempt

Mole amount fixes specified-entity number. Mass depends on the entity’s molar mass, and total atom count also depends on composition.

What should we investigate next?

Which comparison would test a remaining uncertainty? State what you would change, keep comparable and measure.

Investigate, calculate and revise

Keep a first model and an evidence-supported revision. Attempt each task before opening guidance; all required explanations and supplied-data routes are available locally.

Activity 1 · Return to the opening case

Assigned reading and preparation

Use the opening phenomenon, unit definitions and explained Parts 1–4.

Your task

Return to the initial case. Does one mole always mean the same mass? Revise your drawing or explanation using two named ideas and one stated limitation.

Success criteria

  • Use the stated observations and appropriate units.
  • Connect a labeled model with the chemical mechanism.
  • State assumptions and an evidence limitation.
  • Explain a substantive revision or next test.
Hint

Keep species identity, material transfer and energy account distinct.

Response guidance — discuss after your attempt

Mole amount fixes specified-entity number. Mass depends on the entity’s molar mass, and total atom count also depends on composition.

Activity 2 · Transfer to a changed case

Assigned reading and preparation

Cover the worked answer and use the explained models, relationships and notebook.

Your task

Using Mₘ(CO₂)=44.0 g/mol and Nₐ≈6.022×10²³ mol⁻¹, find moles, molecules and moles of oxygen atoms in 22.0 g CO₂.

Success criteria

  • Use the stated measurements or conditions, with correct units.
  • Connect the result to the chemical mechanism or evidence relationship.
  • Identify the assumption, model limit or further evidence requested.
Hint

Name known quantities and conditions, show intermediate steps and check conservation.

Response guidance — discuss after your attempt

n=22.0/44.0=0.500 mol CO₂. Molecules≈3.01×10²³. Each has two O atoms, giving 1.00 mol O atoms. Keep the entity labels through every conversion.

Words to know

mole (mol)
The chemist's counting unit: one mole is exactly 6.022 × 10²³ particles of a substance.
Avogadro's number
The exact entity count per mole, 6.02214076×10²³; the Avogadro constant carries unit mol⁻¹.
molar mass
The mass of one mole of a substance in grams, numerically equal to the sum of the atomic masses in its formula (g/mol).
atomic mass
The average mass of an atom of an element, in atomic mass units, read from the periodic table.
representative particle
The basic unit being counted — an atom for an element, a molecule for a molecular compound, or a formula unit for an ionic compound.

Avogadro never knew his own number

The number 6.022 × 10²³ bears Amedeo Avogadro's name, yet Avogadro never calculated it and probably never imagined its size. In 1811 the Italian scientist proposed a modest-sounding idea: that equal volumes of any gases, at the same temperature and pressure, contain equal numbers of particles. That hypothesis was mostly ignored for half a century. Only decades after his death did others measure how many particles a mole actually holds, and in 1909 the French physicist Jean Perrin proposed naming the quantity 'Avogadro's number' in his honor. It is a fitting bit of scientific justice — the man whose insight made the counting unit possible finally got the credit, long after he could have enjoyed it.

Just how big is 6.022 × 10²³?

Avogadro's number is so large it defeats the imagination, so try anchoring it to time. If you had one mole of seconds to spend, you would hold more than a million times the entire age of the universe — the roughly 14 billion years since the Big Bang would not make the smallest dent in the account. One mole of ordinary marbles would bury the Earth's whole surface many kilometers deep. And yet one mole of water molecules fits in a single tablespoon. That contrast is the whole point of the mole: nature packs such staggering numbers of atoms into such tiny masses that we need a counting unit this enormous just to talk about a sip of water.

A mole is a count, not a weight

The most common mole misconception is to treat it as a fixed mass, but a mole is a count — a number of things, exactly like a dozen. A dozen eggs and a dozen watermelons are the same count with wildly different weights, and moles behave the same way. A mole of hydrogen atoms weighs only about 1 gram, while a mole of lead atoms weighs about 207 grams, even though each contains the identical 6.022 × 10²³ atoms. This is precisely why molar mass is so useful: it is the personalized conversion factor that tells you what one mole of a specific substance happens to weigh, translating the universal count into a number of grams you can actually measure on a balance.

In 2019, the mole was pinned down forever

For most of its life the mole was defined by a physical yardstick: it was the number of atoms in exactly 12 grams of carbon-12. That tied chemistry's counting unit to a particular lump of a particular isotope. In May 2019 the international science community modernized the definition, declaring that one mole simply is exactly 6.022 140 76 × 10²³ particles — a fixed, defined number, with no reference sample required. The change is invisible in your homework, where 6.022 × 10²³ still works fine, but it is philosophically clean: Avogadro's number is now a defined constant of nature, as exact and unchanging as the modern definitions of the meter and the second.

One mole of any gas fills the same space

Here is a startling payoff of Avogadro's 1811 insight: at the same temperature and pressure, one mole of any gas occupies the same volume, no matter what the gas is. At standard temperature and pressure — 0°C and 1 atmosphere — that molar volume is about 22.4 liters, roughly the size of a large beach ball. A mole of helium, a mole of carbon dioxide, and a mole of oxygen each fill that same 22.4 L, even though they weigh about 4, 44, and 32 grams respectively. This lets chemists count gas particles just by measuring a volume, and it turns the mole into a bridge that reaches all the way from mass to particles to the space a gas takes up.

In the real world

Every medicine dose is really a mole calculation: a chemist converts the number of active molecules a patient needs into a mass in milligrams that a machine can actually weigh into each tablet.

Exit check

Using H=1 and O=16, how many moles are in 36 g water?

Check your explanation after answering

Molar mass 18 g/mol, so 36/18=2 mol; identify molecules as the counted entities.

Explain your reasoning without notes. If a key idea is missing, revisit the lesson and try again.

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