Half-Life Models & Nuclear Equations — Practice · Grade 11 Science
Chapter: Redox, Cells & Nuclear ChemistryWhat this practice covers
By the end of Half-Life Models & Nuclear Equations you should be able to:
- I can calculate remaining parent amount from a statistical half-life model.
- I can identify daughter counts and state isotope-dating assumptions.
8 questions, numeric and written answer, each with a worked explanation.
Vocabulary used: activity, daughter nucleus, decay constant.
Problem 1
Hints
Write the relationship first; substitute with consistent units.
Answer and explanation
20 g
80/4=20.
Problem 2
Answer and explanation
No. One-quarter remains on average in a large population.
Response criteria
- State a scientifically accurate conclusion.
- Show the calculation or mechanism that supports it.
- Include units, conditions, or limits where relevant.
Problem 3
Hints
List the given quantities, select a relationship, and check units before substituting.
Answer and explanation
15 g
120/8=15.
Problem 4
Answer and explanation
A neutron becomes a proton, an electron and an antineutrino are emitted; Z increases 1 and A stays the same.
Response criteria
- State a scientifically accurate conclusion.
- Show the calculation or mechanism that supports it.
- Include units, conditions, or limits where relevant.
Problem 5
Hints
A half-life is repeated fractional decrease, not fixed mass loss.
Answer and explanation
Four half-lives, so 8 days.
Problem 6
Hints
State what the supplied observations or conditions establish, and separate that from any assumption.
Answer and explanation
1000e⁻²ln2=250, equivalent to two half-lives.
Problem 7
Answer and explanation
Their ratio is positive; the parent fraction has fallen below one over a positive time interval.
A measured parent fraction need not be a simple power of one half. Rearrange the exponential using logarithms to solve t=t½ ln(N/N₀)/ln(1/2). Both the fraction and logarithm arguments are dimensionless. A fraction between zero and one gives positive time because numerator and denominator are both negative. Dating requires an appropriate initial inventory or calibrated initial ratio and a sufficiently closed accounting system; contamination or material exchange can invalidate a simple age inference.
Their ratio is positive; the parent fraction has fallen below one over a positive time interval.
Response criteria
- Interpret labels, structures, axes, units and directions correctly.
- Explain the chemistry relationship or mechanism.
- Respect stated assumptions and distinguish observation from inference.
Problem 8
Answer and explanation
Later net signal=200, so fraction=200/800=0.250. That is two half-lives, giving 16.0 days. Assume stable geometry/efficiency and a net signal proportional to the same parent population with an appropriate closed account.
Later net signal=200, so fraction=200/800=0.250. That is two half-lives, giving 16.0 days. Assume stable geometry/efficiency and a net signal proportional to the same parent population with an appropriate closed account.
Response criteria
- Use the stated measurements or conditions, with correct units.
- Connect the result to the chemical mechanism or evidence relationship.
- Identify the assumption, model limit or further evidence requested.