Nuclear Chemistry — Practice · Grade 11 Science

Chapter: Redox, Cells & Nuclear Chemistry

What this practice covers

By the end of Nuclear Chemistry you should be able to:

9 questions, multiple choice, numeric and written answer, each with a worked explanation.

Vocabulary used: radioactivity, alpha decay, beta decay, gamma decay, half-life, nuclear fission, nuclear fusion.

Problem 1

An alpha particle is identical to…
  1. a high-energy photon
  2. a single proton
  3. a single electron
  4. a helium-4 nucleus (2 protons and 2 neutrons)
Answer and explanation

a helium-4 nucleus (2 protons and 2 neutrons)

An alpha particle is a helium-4 nucleus, ⁴₂He — two protons and two neutrons.

Problem 2

A 160 g sample of a radioisotope has a half-life of 6 years. How many grams remain after 12 years?
Answer and explanation

40 g

12 ÷ 6 = 2 half-lives, so the sample halves twice: 160 → 80 → 40 g (or 160 ÷ 2² = 40 g).

Problem 3

During beta-minus decay, the atomic number of the daughter nucleus…
  1. increases by 1
  2. decreases by 1
  3. decreases by 2
  4. stays the same
Answer and explanation

increases by 1

In beta-minus decay, a neutron becomes a proton while an electron and antineutrino are emitted, so Z rises by 1 and A stays the same. Beta-plus decay follows a different change.

Problem 4

Explain the difference between nuclear fission and nuclear fusion, and give one real-world example of each.
Answer and explanation

Fission splits a heavy nucleus into lighter ones — for example, uranium-235 splitting inside a nuclear power reactor. Fusion joins light nuclei into a heavier one — for example, hydrogen fusing into helium in the core of the Sun. Both release large amounts of energy.

Problem 5

A 12 g sample of a radioisotope has a half-life of 2 hours. How many grams remain after 6 hours?
Answer and explanation

1.5 g

6 ÷ 2 = 3 half-lives, so the sample halves three times: 12 → 6 → 3 → 1.5 g (or 12 ÷ 2³ = 1.5 g).

Problem 6

In beta-minus decay, how do A and Z change in the basic nuclear equation? Show the reasoning, not just the conclusion.
Hints

Balance both mass number and charge number.

Answer and explanation

A stays unchanged; Z increases by 1 as a neutron converts to a proton with emitted particles.

Problem 7

Why can radiation risk not be ranked from radiation type alone?
Hints

State what the supplied observations or conditions establish, and separate that from any assumption.

Answer and explanation

Dose, energy, exposure route, duration and shielding matter as well as radiation type.

Problem 8

Nucleon balance and mass–energy balance answer complementary questionsNucleon balance and mass–energy balance answer complementary questions²³⁵₉₂U + ¹₀n → ¹⁴¹₅₆Ba + ⁹²₃₆Kr + 3¹₀nMass numbers: 236 → 141+92+3 = 236Atomic numbers: 92 → 56+36 = 92Energy comes from the complete consistent mass/binding account.
Original selected balanced U-235 fission channel for bookkeeping. Actual fission has a distribution of product channels and neutron yields, not only this one equation.
Interpret the supplied visual. Does equal total mass number prove the precise rest masses before and after are exactly equal?
Answer and explanation

No. Mass number is nucleon count; different binding energies can produce a rest-mass difference and energy transfer.

Fission splits a heavy nucleus into smaller products and can release neutrons; fusion combines light nuclei. Whether a specified channel releases energy depends on the complete initial/final mass and binding-energy account, not the claim that splitting or joining always releases energy. Mass-number sums count nucleons, while precise mass differences connect with E=Δmc². Use either nuclear or atomic masses consistently so electron masses are not accidentally omitted or double-counted. Reaction accessibility and control require a separate mechanism account.

No. Mass number is nucleon count; different binding energies can produce a rest-mass difference and energy transfer.

Response criteria

  • Interpret labels, structures, axes, units and directions correctly.
  • Explain the chemistry relationship or mechanism.
  • Respect stated assumptions and distinguish observation from inference.

Problem 9

Balance the alpha-decay bookkeeping ²³⁸₉₂U → daughter + ⁴₂He. Give daughter A and Z, then explain why the integers alone do not provide released energy.
Answer and explanation

Daughter A=234 and Z=90, corresponding to thorium. Precise consistent masses or binding energies are needed for an energy calculation; mass-number conservation is not equality of exact rest masses.

Daughter A=234 and Z=90, corresponding to thorium. Precise consistent masses or binding energies are needed for an energy calculation; mass-number conservation is not equality of exact rest masses.

Response criteria

  • Use the stated measurements or conditions, with correct units.
  • Connect the result to the chemical mechanism or evidence relationship.
  • Identify the assumption, model limit or further evidence requested.

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