Oxidation Numbers & Redox Equations — Practice · Grade 11 Science
Chapter: Redox, Cells & Nuclear ChemistryWhat this practice covers
By the end of Oxidation Numbers & Redox Equations you should be able to:
- I can assign oxidation numbers and identify oxidizing and reducing agents.
- I can combine half-reactions while conserving atoms, charge, and electrons.
8 questions, numeric and written answer, each with a worked explanation.
Vocabulary used: oxidation, reduction, oxidizing agent.
Problem 1
Hints
Write the relationship first; substitute with consistent units.
Answer and explanation
5
x−6=−1, x=+5.
Problem 2
Answer and explanation
Zn donates electrons and is oxidized, so it is the reducing agent.
Response criteria
- State a scientifically accurate conclusion.
- Show the calculation or mechanism that supports it.
- Include units, conditions, or limits where relevant.
Problem 3
Hints
List the given quantities, select a relationship, and check units before substituting.
Answer and explanation
4
x−4=0, x=+4.
Problem 4
Hints
Write the relationship first; substitute with consistent units.
Answer and explanation
4 electrons
Each loses 2, total 4.
Problem 5
Hints
Oxidation and reduction occur together in the complete reaction.
Answer and explanation
Oxygen, changing from 0 to −2 oxidation state; magnesium is oxidized.
Problem 6
Hints
State what the supplied observations or conditions establish, and separate that from any assumption.
Answer and explanation
Total charge must match on both sides, along with atom counts and balanced electron loss/gain.
Problem 7
Answer and explanation
The left side without electrons has charge +7, while Mn²⁺ on the right has +2. Five negative electron charges make both +2.
A half-reaction method first balances non-H/O atoms, then uses water and the medium’s proton/hydroxide account to balance O and H, and electrons to balance charge. In the selected acidic permanganate reduction, five electrons are required. A basic-medium answer should not leave an inappropriate net inventory of free H⁺; converting an acidic balance uses matched OH⁻ additions and water cancellation. The method is formal conservation, not proof that the equation is an elementary microscopic step.
The left side without electrons has charge +7, while Mn²⁺ on the right has +2. Five negative electron charges make both +2.
Response criteria
- Interpret labels, structures, axes, units and directions correctly.
- Explain the chemistry relationship or mechanism.
- Respect stated assumptions and distinguish observation from inference.
Problem 8
Answer and explanation
Mg goes 0→+2 and is oxidized/reducing agent. Ag⁺ goes +1→0 and is reduced/oxidizing agent. One mole Mg transfers two moles electrons, consumed by two moles Ag⁺ in the selected complete account.
Mg goes 0→+2 and is oxidized/reducing agent. Ag⁺ goes +1→0 and is reduced/oxidizing agent. One mole Mg transfers two moles electrons, consumed by two moles Ag⁺ in the selected complete account.
Response criteria
- Use the stated measurements or conditions, with correct units.
- Connect the result to the chemical mechanism or evidence relationship.
- Identify the assumption, model limit or further evidence requested.