Heating Curves & Phase-Change Energy — Practice · Grade 11 Science
Chapter: States of Matter & GasesWhat this practice covers
By the end of Heating Curves & Phase-Change Energy you should be able to:
- I can identify phase-change and temperature-change stages on a heating curve.
- I can add sensible and latent energy contributions with appropriate constants.
8 questions, numeric and written answer, each with a worked explanation.
Vocabulary used: latent heat, plateau.
Problem 1
Hints
Write the relationship first; substitute with consistent units.
Answer and explanation
1670 J
mL=5×334.
Problem 2
Answer and explanation
It includes sensible heating but omits latent heat needed to change phase.
Response criteria
- State a scientifically accurate conclusion.
- Show the calculation or mechanism that supports it.
- Include units, conditions, or limits where relevant.
Problem 3
Hints
List the given quantities, select a relationship, and check units before substituting.
Answer and explanation
1002 J
3×334=1002; sample heat would be negative.
Problem 4
Answer and explanation
No. Ordinary boiling primarily overcomes intermolecular attractions; the molecules remain H₂O.
Response criteria
- State a scientifically accurate conclusion.
- Show the calculation or mechanism that supports it.
- Include units, conditions, or limits where relevant.
Problem 5
Hints
Do not apply mcΔT alone to a phase-change plateau.
Answer and explanation
Q=20×2×15=600 J.
Problem 6
Hints
State what the supplied observations or conditions establish, and separate that from any assumption.
Answer and explanation
Phase-change energy mL plus any separate warming before or after, with each segment counted once.
Problem 7
Answer and explanation
Approximately −3340 J for the reverse transition under the corresponding conditions.
A specific latent energy L gives energy per mass for a particular phase change under specified conditions. Near ordinary-pressure melting, water’s fusion value is about 334 J/g. Melting ten grams of ice at its transition therefore needs about 3,340 J even while temperature is nearly constant. Vaporization has a different value, and reverse transitions have the opposite system heat sign. The energy concerns the full phase arrangement, not ordinary cleavage of every O–H covalent bond in the molecules.
Approximately −3340 J for the reverse transition under the corresponding conditions.
Response criteria
- Interpret labels, structures, axes, units and directions correctly.
- Explain the chemistry relationship or mechanism.
- Respect stated assumptions and distinguish observation from inference.
Problem 8
Answer and explanation
Melting: 20.0×334=6680 J. Warming: 20.0×4.18×10.0=836 J. Total=7516 J≈7.52 kJ. The sample receives positive heat under the stated boundary.
Melting: 20.0×334=6680 J. Warming: 20.0×4.18×10.0=836 J. Total=7516 J≈7.52 kJ. The sample receives positive heat under the stated boundary.
Response criteria
- Use the stated measurements or conditions, with correct units.
- Connect the result to the chemical mechanism or evidence relationship.
- Identify the assumption, model limit or further evidence requested.