Solution Stoichiometry — Practice · Grade 11 Science
Chapter: Stoichiometry & YieldWhat this practice covers
By the end of Solution Stoichiometry you should be able to:
- I can convert solution volume to moles and apply a reaction ratio.
- I can distinguish dilution from reaction and identify excess reactant.
8 questions, numeric and written answer, each with a worked explanation.
Vocabulary used: equivalence, aliquot.
Problem 1
Hints
Write the relationship first; substitute with consistent units.
Answer and explanation
0.1 mol
.400×.250=.100.
Problem 2
Answer and explanation
Their molarities and reaction coefficients can differ.
Response criteria
- State a scientifically accurate conclusion.
- Show the calculation or mechanism that supports it.
- Include units, conditions, or limits where relevant.
Problem 3
Hints
List the given quantities, select a relationship, and check units before substituting.
Answer and explanation
20 mL
.0040/.20=.020L=20 mL.
Problem 4
Answer and explanation
Dilution preserves solute moles; neutralization transforms species according to a balanced equation.
Response criteria
- State a scientifically accurate conclusion.
- Show the calculation or mechanism that supports it.
- Include units, conditions, or limits where relevant.
Problem 5
Hints
Use liters in n=MV.
Answer and explanation
n=0.40×0.025=0.010 mol.
Problem 6
Hints
State what the supplied observations or conditions establish, and separate that from any assumption.
Answer and explanation
Ag⁺, because equal volumes give half as many moles of Ag⁺ as Cl⁻.
Problem 7
Answer and explanation
Some acid is consumed. Reaction bookkeeping must determine the remaining amount before the final-volume division.
When solutions mix, a reacting ion can be consumed while spectator ions remain. Calculate each initial amount, apply stoichiometry, then divide remaining amount by the final solution volume. Adding volumes is a common dilute-solution school approximation, not an exact law for every mixture. The concentration of a spectator can decrease by dilution without the spectator being consumed. A final mixture can contain several species with different concentrations, so keep a separate inventory for each named species.
Some acid is consumed. Reaction bookkeeping must determine the remaining amount before the final-volume division.
Response criteria
- Interpret labels, structures, axes, units and directions correctly.
- Explain the chemistry relationship or mechanism.
- Respect stated assumptions and distinguish observation from inference.
Problem 8
Answer and explanation
Ag⁺ starts at 0.00200 mol and Cl⁻ at 0.00150 mol, so chloride limits. AgCl forms 0.00150 mol; remaining Ag⁺ is 0.00050 mol in 0.0250 L, or 0.0200 M under the stated model.
Ag⁺ starts at 0.00200 mol and Cl⁻ at 0.00150 mol, so chloride limits. AgCl forms 0.00150 mol; remaining Ag⁺ is 0.00050 mol in 0.0250 L, or 0.0200 M under the stated model.
Response criteria
- Use the stated measurements or conditions, with correct units.
- Connect the result to the chemical mechanism or evidence relationship.
- Identify the assumption, model limit or further evidence requested.