Circuits & Ohm's Law — Practice · Grade 12 Science
Chapter: Electricity, Magnetism & CircuitsWhat this practice covers
By the end of Circuits & Ohm's Law you should be able to:
- I can apply Ohm's law (V = IR) to find voltage, current, or resistance in a circuit.
- I can find the total resistance of resistors wired in series and in parallel.
- I can calculate electrical power with P = IV and relate it to energy used.
10 questions, numeric, multiple choice and written answer, each with a worked explanation.
Vocabulary used: Ohm's law, series circuit, parallel circuit, equivalent resistance, electrical power.
Problem 1
Answer and explanation
10 V
V = IR = 2 × 5 = 10 V.
Problem 2
Answer and explanation
8 Ω
R = V ÷ I = 24 ÷ 3 = 8 Ω.
Problem 3
Answer and explanation
20 Ω
In series, resistances add: 4 + 6 + 10 = 20 Ω.
Problem 4
- the same through all of them
- larger in the bigger resistors
- smaller in the bigger resistors
- zero
Answer and explanation
the same through all of them
A series circuit has one single path, so the identical current flows through every component.
Problem 5
Answer and explanation
6 Ω
1/R = 1/12 + 1/12 = 2/12 = 1/6, so R = 6 Ω. (For two equal resistors, the parallel total is always half of one.)
Problem 6
Answer and explanation
0.5 A
Rearranging P = IV gives I = P ÷ V = 60 ÷ 120 = 0.5 A.
Problem 7
Hints
Kirchhoff's loop balance provides a check.
Answer and explanation
R_eq=3 Ω; I_total=12/3=4 A, with 2 A per branch.
Problem 8
Hints
State what the supplied observations or conditions establish, and separate that from any assumption.
Answer and explanation
Each branch spans the same two electrical nodes, so it has the same potential difference.
Problem 9
Answer and explanation
Smaller for more than one finite positive branch in this ideal model.
An equivalent resistance gives the same voltage–total-current relation at a chosen pair of terminals as the ideal resistor network. Series resistances add; parallel conductances 1/R add. A 2 Ω equivalent for 6 Ω parallel with 3 Ω is smaller than either branch resistance because it offers more conducting paths. This does not mean either actual resistor changed its own resistance or that branch currents equal the total current.
Smaller for more than one finite positive branch in this ideal model.
Response criteria
- Interpret labels, structures, axes, units and directions correctly.
- Explain the physical or environmental relationship or mechanism.
- Respect stated assumptions and distinguish observation from inference.
Problem 10
Answer and explanation
Currents are 3 A and 1 A; total 4 A. Req=12/4=3 Ω and P=12×4=48 W. Branch powers 36 W and 12 W sum consistently.
Currents are 3 A and 1 A; total 4 A.
Req=12/4=3 Ω and P=12×4=48 W.
Branch powers 36 W and 12 W sum consistently.
Response criteria
- Use the stated measurements or conditions, with correct units.
- Connect the result to the physical or environmental mechanism or evidence relationship.
- Identify the assumption, model limit or further evidence requested.