Photons, Photoelectric Effect & Wave–Particle Models — Practice · Grade 12 Science
Chapter: Modern PhysicsWhat this practice covers
By the end of Photons, Photoelectric Effect & Wave–Particle Models you should be able to:
- I can explain threshold and intensity evidence for photoelectric emission.
- I can calculate photon energy, maximum electron energy, and stopping potential.
8 questions, numeric and written answer, each with a worked explanation.
Vocabulary used: work function, threshold frequency, electronvolt.
Problem 1
Hints
Write the relationship first; substitute with consistent units.
Answer and explanation
3 eV
5−2=3.
Problem 2
Answer and explanation
Each photon lacks the required energy; adding more such photons does not change the single-photon energy.
Response criteria
- State a scientifically accurate conclusion.
- Show the calculation or mechanism that supports it.
- Include units, conditions, or limits where relevant.
Problem 3
Hints
List the given quantities, select a relationship, and check units before substituting.
Answer and explanation
2 eV
1240/620=2.
Problem 4
Answer and explanation
Interference supports wave superposition; threshold-dependent photoemission supports quantized energy exchange.
Response criteria
- State a scientifically accurate conclusion.
- Show the calculation or mechanism that supports it.
- Include units, conditions, or limits where relevant.
Problem 5
Hints
Below threshold, increased intensity alone does not supply more energy to each photon.
Answer and explanation
No. Each photon is below threshold; do not report negative kinetic energy as an emitted-electron result.
Problem 6
Hints
State what the supplied observations or conditions establish, and separate that from any assumption.
Answer and explanation
It can increase emission rate/current, while maximum electron kinetic energy is set by photon energy minus work function.
Problem 7
Answer and explanation
3.204×10⁻¹⁹ J per electron, rounded appropriately for the supplied data.
Photoelectrons can emerge with a range of kinetic energies; the ideal relation specifies the maximum. A retarding stopping potential magnitude Vs is sufficient to stop even those fastest electrons when eVs=Kmax in the stated setup. Converting eV to joules uses 1 eV=1.602×10⁻¹⁹ J. Keep electron charge magnitude separate from the signed field/voltage convention when describing the apparatus, and do not confuse a 2 eV energy with a 2 V potential.
3.204×10⁻¹⁹ J per electron, rounded appropriately for the supplied data.
Response criteria
- Interpret labels, structures, axes, units and directions correctly.
- Explain the physical or environmental relationship or mechanism.
- Respect stated assumptions and distinguish observation from inference.
Problem 8
Answer and explanation
Kmax=1.5 eV=2.403×10⁻¹⁹ J; stopping-potential magnitude=1.5 V. At fixed photon energy, increasing intensity changes available electron number rather than this maximum.
Kmax=1.5 eV=2.403×10⁻¹⁹ J; stopping-potential magnitude=1.5 V.
At fixed photon energy, increasing intensity changes available electron number rather than this maximum.
Response criteria
- Use the stated measurements or conditions, with correct units.
- Connect the result to the physical or environmental mechanism or evidence relationship.
- Identify the assumption, model limit or further evidence requested.