Velocity & Acceleration — Drills · Grade 12 Science
Chapter: Motion & KinematicsWhat these drills covers
By the end of Velocity & Acceleration you should be able to:
- I can distinguish average velocity, instantaneous velocity, and average speed, and calculate each.
- I can define acceleration as the rate of change of velocity and calculate it, including its sign.
- I can explain the meaning of g and apply it to objects in free fall.
6 questions, numeric, multiple choice and written answer, each with a worked explanation.
Vocabulary used: average velocity, instantaneous velocity, average speed, acceleration, free fall, g.
Problem 1
Answer and explanation
4 m/s²
a = (v − v₀) ÷ t = (28 − 4) ÷ 6 = 24 ÷ 6 = 4 m/s².
Problem 2
Answer and explanation
19.6 m/s
v = v₀ + gt = 0 + 9.8 × 2.0 = 19.6 m/s.
Problem 3
Answer and explanation
12.5 m/s
Average velocity = displacement ÷ time = 100 ÷ 8.0 = 12.5 m/s.
Problem 4
- acceleration
- displacement
- total distance
- top speed
Answer and explanation
displacement
Average velocity uses displacement ÷ time, which is why a round trip back to the start has an average velocity of zero.
Problem 5
Answer and explanation
-6 m/s²
a = (6 − 30) ÷ 4 = −24 ÷ 4 = −6 m/s². Here the acceleration is opposite the stated positive velocity, so speed decreases during the interval. A negative acceleration does not mean slowing in every motion case.
Problem 6
Answer and explanation
Gravity keeps acting on the ball for the entire flight, so it keeps changing the ball's velocity at 9.8 m/s² downward the whole time. At the top, the velocity is momentarily zero only because the ball has finished slowing down and is about to speed up downward — but the acceleration never pauses. Zero velocity and zero acceleration are completely different conditions.