Kinetic & Potential Energy — Practice · Grade 12 Science
Chapter: Work, Energy & MomentumWhat this practice covers
By the end of Kinetic & Potential Energy you should be able to:
- I can calculate kinetic energy with KE = ½mv² and gravitational potential energy with PE = mgh.
- I can calculate elastic potential energy stored in a spring using PE = ½kx².
9 questions, numeric, multiple choice and written answer, each with a worked explanation.
Vocabulary used: kinetic energy, gravitational potential energy, elastic potential energy, spring constant (k), reference level.
Problem 1
Answer and explanation
100 J
KE = ½mv² = ½ × 2.0 × 10² = ½ × 2.0 × 100 = 100 J.
Problem 2
Answer and explanation
98 J
PE = mgh = 0.50 × 9.8 × 20 = 98 J.
Problem 3
Answer and explanation
10 J
PE = ½kx² = ½ × 500 × 0.20² = ½ × 500 × 0.04 = 10 J.
Problem 4
- The motorcycle (62,500 J)
- They are equal
- It cannot be determined
- The car (50,000 J)
Answer and explanation
The motorcycle (62,500 J)
Car KE = ½ × 1,000 × 10² = 50,000 J. Motorcycle KE = ½ × 200 × 25² = 62,500 J. The motorcycle's higher speed (squared) wins out over its smaller mass.
Problem 5
Answer and explanation
Because PE = mgh measures height h from a chosen zero level, the numerical value of PE changes if you pick a different reference. This is not a problem because only changes in PE (as an object rises or falls) affect motion, and those changes come out the same no matter where you place the reference level.
Problem 6
Hints
Do not add height to speed or confuse their squares.
Answer and explanation
½×4×9=18 J.
Problem 7
Hints
State what the supplied observations or conditions establish, and separate that from any assumption.
Answer and explanation
It increases ninefold because of the square dependence.
Problem 8
Answer and explanation
Us=0.50 J; force magnitude=10 N. Their units and meanings differ.
For an ideal linear spring, elastic potential energy relative to its unstrained state is Us=½kx². This is the area under the balancing force–extension curve, not the endpoint force itself. A spring stretched twice as far stores four times the energy within the same elastic range. Compression can also store energy because x² is positive, while the restoring force reverses direction according to −kx.
Us=0.50 J; force magnitude=10 N. Their units and meanings differ.
Response criteria
- Interpret labels, structures, axes, units and directions correctly.
- Explain the physical or environmental relationship or mechanism.
- Respect stated assumptions and distinguish observation from inference.
Problem 9
Answer and explanation
K=½×1.5×16=12 J. Set 12=½×600x², giving x=0.20 m within the spring’s assumed elastic range.
K=½×1.5×16=12 J.
Set 12=½×600x², giving x=0.20 m within the spring’s assumed elastic range.
Response criteria
- Use the stated measurements or conditions, with correct units.
- Connect the result to the physical or environmental mechanism or evidence relationship.
- Identify the assumption, model limit or further evidence requested.