Newton's Three Laws of Motion — Print · Grade 8 Science

Chapter: Motion

Newton's Three Laws of Motion

Learning goals

Readings for this unit

Before this unit

Calculate net force and distinguish mass from weight.

Use three teaching sessions of about 40–45 minutes: first observe the phenomenon, draft a model and study Parts 1–2; next explain Parts 3–4 with the figures and evidence; then work the application, examples, practice, model revision and exit check. Divide any difficult part into smaller steps and revisit after feedback. Investigations, review and quizzes have separate sessions. Study the four visual parts across the scheduled sessions, then use the illustrated worked case and independent transfer questions. Extend or revisit a session when the learner cannot explain the figure; completion time is a proposed allocation, not a mastery guarantee.

Start with something to explain

What would explain the observations in newton's three laws of motion?

Illustrative evidence case. Illustrative carts of 2 kg and 4 kg each experience a 6 N horizontal net force. Other conditions are comparable.

Equal net force, different accelerationEqual net force, different accelerationQuantity (m/s²)2 kg cart: a34 kg cart: a1.5Each cart has the same horizontal net force: 6 N.a = Fnet / m; compare mass alone.Illustrative model • use the labels and stated assumptions
For the same 6 N net force, doubling mass halves acceleration from 3 to 1.5 m/s². The bars represent rates of velocity change, not current velocity or distance. Equal net force is a condition of this comparison; interaction pairs would require named separate receivers.

Notice and wonder

What happens if mass and force both double? Write two observations from the supplied record without guessing their cause. Include a quantity and its unit when given. An observation is what was recorded; an inference is what you think explains it.

Write one question about why the pattern occurs and one question about a comparison that could distinguish competing explanations. A testable question identifies what could be observed or measured.

Your first model

Before reading the model answer, sketch the named objects or particles and label what you think changes. Calculate acceleration magnitudes, identify an equal-and-opposite interaction pair and explain why zero net force does not require rest. Keep this first version so you can compare it with your later explanation.

Build the language from the idea

inertia
The tendency of an object to resist a change in its motion.
Newton's first law
An object at rest stays at rest, and an object in motion stays in motion at constant velocity, unless acted on by an unbalanced force.
Newton's second law
Force equals mass times acceleration: F = ma.
Newton's third law
For every action force, there is an equal and opposite reaction force.
newton (N)
The unit used to measure force; 1 newton = 1 kg·m/s².
model
A representation that explains selected features and makes predictions; it leaves other details out.
evidence
Relevant observations or records used to support or challenge a claim.
system boundary
The chosen limit separating the objects being studied from their surroundings.
assumption
A condition taken as true for a model or calculation and needing to be checked against the case.

Isaac Newton tied together how forces and motion relate in just three elegant laws, and together they explain almost everything you see moving around you. Newton's first law is the law of inertia: an object at rest stays at rest, and an object already moving keeps moving at the same speed and in the same straight-line direction, unless an unbalanced force acts on it. Inertia is simply an object's built-in resistance to any change in its motion, and the more mass something has, the more inertia it has — that's why it's easy to stop a rolling tennis ball but nearly impossible to stop a rolling truck.

You feel the first law every time you ride in a car. When the car suddenly brakes, your body lurches forward — not because something pushed you, but because your body was already moving and 'wants' to keep moving until a force stops it. That force is your seatbelt, which is exactly why it can save your life. The same law explains why a stack of coins stays put when you flick the bottom one out, and why you slide sideways when a car turns sharply.

This first law also corrects one of the most common misunderstandings in all of physics: the belief that keeping something moving requires a constant push. It seems obvious from daily life — stop pedaling and your bike coasts to a halt. But the truth is the opposite: a moving object only slows down because hidden forces like friction and air resistance are pushing back on it. Remove those forces, as in the near-frictionless emptiness of deep space, and an object will glide onward forever with no engine at all.

Zero net force allows rest OR constant velocityZero net force allows rest OR constant velocityNet force = 0: cart at rest0 s1 s2 sSame position each secondNet force = 0: cart at constant rightward velocity0 s1 s2 s
Equal-time snapshots can show no position change or equal changes in position. Both are consistent with zero net force in an inertial reference frame. The moving cart does not need a forward net force to keep its constant velocity. On a real surface, rolling resistance can slow it unless balanced. The rest snapshots overlap intentionally; no extra force called inertia should be drawn.

Newton's second law puts numbers to all of this with one compact equation: F = ma, meaning force equals mass times acceleration. It says two intuitive things at once. First, the harder you push something, the more it accelerates. Second, the more mass an object has, the harder it resists that acceleration — which is why the same kick sends a soccer ball flying but barely budges a bowling ball. Force is measured in a unit called the newton (N), where 1 newton is the force needed to accelerate 1 kilogram at 1 m/s².

Use the net force, not just the applied pushUse the net force, not just the applied push2 kg cartPush: 10 N →Resistance: 4 N ←Net force: 6 N →Acceleration = net force ÷ mass = 6 N ÷ 2 kg = 3 m/s² right.Acceleration direction is known; current velocity is not supplied.
Both red forces act on the cart and their lengths share one force scale. Subtract the opposing forces: 10−4 = 6 N right. For a 2 kg cart, acceleration is 6/2 = 3 m/s² right. The green arrow summarizes that net force, not a third force to add again. Vertical weight and support balance in the stated level-surface model and are omitted. A rightward acceleration alone does not tell you the cart’s current direction of travel.

Newton's third law delivers the famous line: for every action force, there is an equal and opposite reaction force — and, crucially, those two forces act on different objects. When a swimmer's hands push water backward, the water pushes the swimmer forward with equal strength. When you jump, your legs push down on the Earth and the Earth pushes back up on you. The forces always come in matched pairs, pointing in opposite directions.

This third law is the secret behind how a rocket can fly through the vacuum of space, where there's nothing to push against. The rocket doesn't push on the air — it pushes a huge amount of hot gas downward out of its engines, and by Newton's third law that gas pushes the rocket upward with equal force. From walking (your feet push the ground backward so it pushes you forward) to a squid jetting through the ocean, these three laws together let you predict how any push or pull will change the way things move.

Newton's first law describes motion when net force is zero. The second law connects net force to acceleration: Fnet=ma. The third law identifies paired forces between two interacting objects. Use the law that addresses the question rather than memorizing isolated slogans.

A force diagram belongs to one object. If a hand pushes a cart, include the hand's force on the cart, not the cart's force on the hand. The latter belongs on the hand's diagram. Pair forces have equal magnitude, but different masses can have different accelerations.

For a fixed net force, a larger mass has a smaller acceleration. For a fixed mass, doubling net force doubles acceleration. These are model predictions that can be tested with repeated measurements; friction and measurement uncertainty can alter an ideal classroom result.

Build your understanding

Use three teaching sessions of about 40–45 minutes: first observe the phenomenon, draft a model and study Parts 1–2; next explain Parts 3–4 with the figures and evidence; then work the application, examples, practice, model revision and exit check. Divide any difficult part into smaller steps and revisit after feedback. Investigations, review and quizzes have separate sessions.

Part 1 · Use inertia to explain persistence of motion

Newton’s first law describes constant velocity when the net external force is zero. Inertia is resistance to changes in velocity and increases with mass. A forward force is not required merely to maintain steady motion in the ideal case; everyday objects slow because resistance supplies an unbalanced force.

Zero net force allows rest OR constant velocityZero net force allows rest OR constant velocityNet force = 0: cart at rest0 s · 1 s · 2 sSame position each secondNet force = 0: cart at constant rightward velocity0 s1 s2 s
Equal-time snapshots can show no position change or equal changes in position. Both are consistent with zero net force in an inertial reference frame. The moving cart does not need a forward net force to keep its constant velocity. On a real surface, rolling resistance can slow it unless balanced. The rest snapshots overlap intentionally; no extra force called inertia should be drawn.

Read the visual model

Why is inertia not an extra force on a force diagram?

Visual reasoning — after your attempt

Inertia describes how mass resists acceleration. It is not an interaction from another object and should not be added as a force arrow.

A released toy cart slows due to interactions such as rolling resistance, not because motion uses up a stored force. A passenger’s motion changes when a seat or restraint exerts force; connect the law to interactions rather than calling inertia a pushing force.

Balanced and unbalanced forcesNet force decides the change in motionBalancedno change in velocityUnbalancedaccelerates rightOne forceaccelerates rightBalanced forces keep velocity constant — which includes staying still
Constant velocity and being at rest are the same case as far as the forces are concerned. Something moving steadily needs no net force, which is the part of the first law that contradicts intuition.

Read the equal-time snapshots. The rest case overlaps at one position; the constant-velocity case moves the same distance each second. Neither needs a net forward force. Inertia describes resistance to a velocity change; it is not another force acting forward. Identify real interactions such as rolling resistance before explaining why an ordinary cart slows.

Pause and explain

Why is inertia not an extra force on a force diagram?

Check your reasoning after answering

Inertia describes how mass resists acceleration. It is not an interaction from another object and should not be added as a force arrow.

Part 2 · Use the net force in the second law

For the introductory constant-mass model, net force=mass×acceleration. Acceleration points in the net-force direction. A larger applied push does not automatically give larger acceleration if opposing forces or mass also change. Find the net force on one chosen object before using the equation.

Use the net force, not just the applied pushUse the net force, not just the applied push2 kg cartPush: 10 N →Resistance: 4 N ←Net force: 6 N →Acceleration = net force ÷ mass = 6 N ÷ 2 kg = 3 m/s² right.Acceleration direction is known; current velocity is not supplied.
Both red forces act on the cart and their lengths share one force scale. Subtract the opposing forces: 10−4 = 6 N right. For a 2 kg cart, acceleration is 6/2 = 3 m/s² right. The green arrow summarizes that net force, not a third force to add again. Vertical weight and support balance in the stated level-surface model and are omitted. A rightward acceleration alone does not tell you the cart’s current direction of travel.

Read the visual model

Which force belongs in F=ma for this calculation?

Visual reasoning — after your attempt

Use the net external force on the chosen cart, not a single applied force when other forces also act.

A 2 kg cart pushed right with 10 N against 4 N resistance has net force 6 N right and acceleration 3 m/s² right. Dividing 10 N by mass would ignore resistance and overestimate acceleration.

Read the red arrows on the cart, subtract opposite forces and then use the resulting net force. The green arrow is their summary and must not be counted as an additional interaction. A rightward acceleration could mean a right-moving cart speeds up or a left-moving cart slows; no present velocity was supplied by the force diagram.

Pause and explain

Which force belongs in F=ma for this calculation?

Check your reasoning after answering

Use the net external force on the chosen cart, not a single applied force when other forces also act.

Part 3 · Place third-law pairs on different objects

When object A exerts a force on B, B exerts an equal opposite force on A. These two forces act on different objects, so they do not cancel within one object’s force diagram. Balanced forces on a single object are a different kind of pair.

A third-law pairThird-law pairs act on different objectsskater Askater BA pushes BB pushes AThese two never cancel, because they act on different objects.Only forces on the same object can be added to find a net force.
The commonest error in this topic is adding an action and reaction together and concluding nothing can ever accelerate. The pair acts on two different bodies, so neither appears in the other's net force.

Read the visual model

Why do equal action-reaction forces not prevent the cart accelerating?

Visual reasoning — after your attempt

One force acts on the cart and the other on the hand. They are not both forces on the cart, so they cannot be canceled in its net-force calculation.

A hand pushes a cart and the cart pushes the hand equally in the opposite direction. The cart can accelerate because its own net force need not be zero. The two objects can have different accelerations because their masses and other interactions differ.

OpenSciEd sketch of a wire coil facing a separate magnet across a gap; the diagram is a template for adding the two interaction-force arrows.
The OpenSciEd coil and magnet are two separate objects. Under a specified interaction their force pair is equal and opposite, although their masses and other forces can give different accelerations. Add named source-on-receiver arrows; do not infer motion merely from this uncompleted force template. Coil and magnet before force arrows are added · OpenSciEd · 8.3 Forces at a Distance, Lesson 2, source, CC BY 4.0. Figure excerpt rendered from the PDF and resized for the web.

Pause and explain

Why do equal action-reaction forces not prevent the cart accelerating?

Check your reasoning after answering

One force acts on the cart and the other on the hand. They are not both forces on the cart, so they cannot be canceled in its net-force calculation.

Part 4 · Combine the laws in one explanation

A complete explanation names the object, its interacting partners, the net force, and the change in velocity. Use the first law when net force is zero, the second law for acceleration, and the third law to describe interaction partners. The laws answer related but different questions.

Two second-law graphs answer different questionsTwo second-law graphs answer different questionsAcceleration (m/s²)01.534.50369Net force (N)Mass fixed: 2 kgAcceleration (m/s²)024612345Mass (kg)Net force fixed: 6 NChange one factor at a time. These are model predictions, not collected results.
The left graph holds mass at 2 kg and predicts acceleration = force/2: double net force gives double acceleration. The right graph holds net force at 6 N and predicts acceleration = 6/mass: double mass gives half the acceleration. The curved relationship on the right is not a straight decrease. The mass graph begins at 1 kg, not zero; dividing by zero mass is outside this model. Compare actual repeated cart data with these predictions and account for resistance and uncertainty.

Read the visual model

Do equal interaction forces require equal accelerations?

Visual reasoning — after your attempt

No. Acceleration depends on each object’s mass and all forces acting on it. Equal opposite partner forces act on different objects.

For two carts with equal net force but different masses, the heavier cart has smaller acceleration. Each push still has an equal opposite partner force on the pusher. These facts are consistent because interaction-force equality is not acceleration equality.

Equal net force, different accelerationEqual net force, different accelerationQuantity (m/s²)2 kg cart: a34 kg cart: a1.5Each cart has the same horizontal net force: 6 N.a = Fnet / m; compare mass alone.Illustrative model • use the labels and stated assumptions
For the same 6 N net force, doubling mass halves acceleration from 3 to 1.5 m/s². The bars represent rates of velocity change, not current velocity or distance. Equal net force is a condition of this comparison; interaction pairs would require named separate receivers.

The two graphs hold different quantities fixed. Left: mass is 2 kg, so a = Fnet/2 and acceleration increases in direct proportion to net force. Right: net force is 6 N, so a = 6/m and acceleration decreases with increasing mass along a curve. Do not change mass and force together and attribute the result to one factor. Repeated measurements can be compared with these model predictions without pretending the model curves are collected data.

Pause and explain

Do equal interaction forces require equal accelerations?

Check your reasoning after answering

No. Acceleration depends on each object’s mass and all forces acting on it. Equal opposite partner forces act on different objects.

Investigate force and mass separately

A change in a cart’s motion is not established by a force arrow alone. A planned comparison needs motion records, controls and a receiver.

Acceleration is the rate of velocity change, not the object’s current speed. To investigate its relation to net force, keep mass fixed and compare different controlled net forces. To investigate mass, keep net force fixed and compare masses. A horizontal force estimate must include opposing resistance; an applied pull during acceleration is not automatically the net force. An inertial reference is a frame where the introductory laws apply without additional apparent forces.

Investigate force and mass separatelyInvestigate force and mass separatelyQuantity (acceleration, m/s²)Fixed 1 kg: Fnet 1 N1Fixed 1 kg: Fnet 2 N2Fixed 2 N: mass 4 kg0.5Illustrative model • read the labels and caption
The bars select three supplied cases rather than claim every hand push is a controlled force. At fixed mass, greater net force gives greater acceleration; at fixed net force, greater mass gives less acceleration. Read which condition is held fixed before drawing a causal conclusion.

Define motion measurement before testing: specify the start, positive direction, time interval, and recorded positions or velocities. Equal-interval records can establish average velocities and their changes. Repeating a comparison reveals variation; it does not repair a method that changed both intended factors together. Use safe toy observations to investigate qualitative patterns only, or the supplied quantitative model data; do not invent a constant force from an unmeasured hand push.

Braking illustrates a net force opposite an existing motion direction. A right-moving cart under a leftward net force can slow before reversing. Friction, a brake pad or another interaction transfers energy into deformation and thermal changes. If force becomes balanced while the cart still moves, constant velocity can continue in the ideal model. The three laws connect persistence, net-force/mass response and separate interaction partners rather than provide three unrelated slogans.

Evidence to interpret

Mass (kg)Net force (N)Acceleration (m/s²)
111
122
221
420.5

Investigate or evaluate the supplied records

  1. State one intended variable and choose matching record pairs.
  2. Specify initial state, time measurements and a fixed positive direction.
  3. Use supplied values or an approved safe simulation; ordinary hand-push observations do not provide calibrated net-force values.
  4. Plot acceleration against the changed factor while identifying fixed conditions.
  5. Plan repeated trials and a result that would challenge the explanation.

Explain and apply

Plan two comparisons from the records: one isolating net force, the other mass. Specify motion measurements, repeats, controls and what outcome would challenge the predicted relation. Explain braking separately from velocity direction.

  • Design two separately controlled comparisons.
  • Specify recorded motion, units and repeats.
  • Explain a challenge result and braking mechanism.
Reasoning and marking guidance — after your attempt

Compare the 1 kg cases at 1 and 2 N to isolate net force; compare 1, 2 and 4 kg at 2 N to isolate mass. Match path, resisting conditions, timing, measuring procedure and initial state. Keep all repeated records. The supplied model gives a=Fnet/m; unexpected motion needs a boundary/force/method review rather than automatic rejection of conservation or hidden invented values. A leftward net force can slow rightward motion.

Apply the whole unit · Compare two carts

Illustrative trials: cart A has mass 2 kg and cart B mass 4 kg. Each receives a 10 N push right and 2 N resistance left. Both begin at rest; assume constant forces over the comparison interval.

Your task

Draw a force diagram for each cart, calculate acceleration, and describe how the first, second, and third laws apply. Label the partner force exerted on the pusher without adding it to the cart diagram.

What your response should show

  • Use the supplied observations and measurements accurately; include units where needed.
  • Explain the science behind your answer, rather than giving only a number or label.
  • Show a labeled model, calculation, or evidence comparison as requested.
  • State an assumption or limitation and suggest a useful next measurement.
Response guidance — after your attempt

Each cart has net force 8 N right. A accelerates at 4 m/s²; B at 2 m/s². Their velocities change because net force is nonzero. Each cart exerts a 10 N opposite force on its pusher, acting on the pusher rather than the cart. Equal applied forces and resistance do not imply equal acceleration when masses differ.

Scientific references and adapted teaching resources

Parent / teacher teaching notes

Check each force with the sentence source acts on object. Require net-force subtraction before division by mass. Use a zero-net-force comparison to connect all three laws without suggesting they are separate unrelated rules. Adaptation credit: OpenSciEd middle-school teaching routines and public task structures by OpenSciEd, CC BY 4.0. This independent version adds original explanatory text, data and figures, terminology support and a home-study schedule. It does not reproduce the complete teacher editions or their classroom validation. The illustrated study “Investigate force and mass separately” is required curriculum content. Teach it before the associated application or distribute it over the assigned unit sessions; it is not an optional enrichment. Its practice/review/quiz response provides evidence of understanding. Model/data work must not be recorded as an actual physical experiment.

The key idea

First law: objects resist changes in motion (inertia). Second law: F = ma. Third law: every action has an equal, opposite reaction.

Newton's Second Law

F = ma

F is net force in newtons (N); m is mass in kg; a is acceleration in m/s². Rearranges to a = F ÷ m or m = F ÷ a.

Worked examples

Example 1

A 5 kg cart is pushed with a net force of 20 N. Find its acceleration.
  1. Rearrange F = ma to solve for acceleration: a = F ÷ m.
  2. a = 20 ÷ 5.
  3. = 4.
Answer: 4 m/s²

Example 2 · Worked application

A 2 kg cart has net force 6 N right. Find acceleration and identify the force partner when a hand pushes the cart.
  1. Apply a=Fnet/m: 6/2=3 m/s² right.
  2. The hand's push on the cart has a partner: the cart's push on the hand.
  3. The two partner forces act on different objects, so they do not cancel within the cart's force sum.
Answer: Acceleration is 3 m/s² right; the interaction partner acts on the hand.
Check the reasoning

Use net force on one object in Newton's second law.

Example 3

A soccer ball with a mass of 0.4 kg accelerates at 25 m/s² when kicked. What net force was applied?
  1. Use F = ma.
  2. F = 0.4 × 25.
  3. = 10.
Answer: 10 N

Example 4

A net horizontal force of 12 N acts on a 4 kg cart. Calculate acceleration and identify the reaction to a hand's push.
  1. Acceleration=Fnet/m=12/4=3 m/s².
  2. The reaction to the hand pushing the cart is the cart pushing the hand, on a different object.
Answer: 3 m/s² in the net-force direction; the cart exerts an equal opposite force on the hand.

Example 5 · Find and fix the mistake

Context: A 2 kg cart has net force 6 N right. Find acceleration and identify the force partner when a hand pushes the cart. A student claims: “The action and reaction forces cancel, so no object can accelerate.” Evaluate the claim and write a corrected explanation.
  1. Test the claim against the stated conditions: Use net force on one object in Newton's second law.
  2. They act on different objects. Acceleration depends on the net force on each individual object.
Answer: They act on different objects. Acceleration depends on the net force on each individual object.
Check the reasoning

Use net force on one object in Newton's second law.

Example 6 · Read both second-law graphs

Use the two model graphs. What is acceleration for net force 9 N at mass 2 kg? What is acceleration for mass 4 kg at net force 6 N?
  1. Left graph: a = 9/2 = 4.5 m/s².
  2. Right graph: a = 6/4 = 1.5 m/s².
  3. State what was fixed before comparing results.
Answer: 4.5 m/s² and 1.5 m/s² respectively.
Check the reasoning

The examples change different variables; neither graph predicts current velocity from force alone.

Example 7 · Interpret the visual model

Zero net force allows rest OR constant velocityZero net force allows rest OR constant velocityNet force = 0: cart at rest0 s · 1 s · 2 sSame position each secondNet force = 0: cart at constant rightward velocity0 s1 s2 s
Equal-time snapshots can show no position change or equal changes in position. Both are consistent with zero net force in an inertial reference frame. The moving cart does not need a forward net force to keep its constant velocity. On a real surface, rolling resistance can slow it unless balanced. The rest snapshots overlap intentionally; no extra force called inertia should be drawn.
Why is inertia not an extra force on a force diagram?
  1. Identify the represented objects, axes, labeled quantities and stated conditions before choosing a rule.
  2. A released toy cart slows due to interactions such as rolling resistance, not because motion uses up a stored force. A passenger’s motion changes when a seat or restraint exerts force; connect the law to interactions rather than calling inertia a pushing force.
  3. Inertia describes how mass resists acceleration. It is not an interaction from another object and should not be added as a force arrow.
Answer: Inertia describes how mass resists acceleration. It is not an interaction from another object and should not be added as a force arrow.
Check the reasoning

Keep the model’s stated limits explicit: Equal-time snapshots can show no position change or equal changes in position. Both are consistent with zero net force in an inertial reference frame. The moving cart does not need a forward net force to keep its constant velocity. On a real surface, rolling resistance can slow it unless balanced. The rest snapshots overlap intentionally; no extra force called inertia should be drawn.

Avoid these mistakes

Check your understanding

A net horizontal force of 12 N acts on a 4 kg cart. Calculate acceleration and identify the reaction to a hand's push.

Discuss the answer

3 m/s² in the net-force direction; the cart exerts an equal opposite force on the hand.

Why can a truck and a small car exert equal collision forces but have different accelerations?

Discuss the answer

Newton's first law describes motion when net force is zero. The second law connects net force to acceleration: Fnet=ma. The third law identifies paired forces between two interacting objects. Use the law that addresses the question rather than memorizing isolated slogans. A force diagram belongs to one object. If a hand pushes a cart, include the hand's force on the cart, not the cart's force on the hand. The latter belongs on the hand's diagram. Pair forces have equal magnitude, but different masses can have different accelerations.

Return to the phenomenon

Illustrative carts of 2 kg and 4 kg each experience a 6 N horizontal net force. Other conditions are comparable. Calculate acceleration magnitudes, identify an equal-and-opposite interaction pair and explain why zero net force does not require rest. Revise your first explanation using a named idea from the lesson. Mark the changed part and the evidence that supports it.

Compare explanations after your attempt

Accelerations are 3 and 1.5 m/s² because a=Fnet/m. Equal interaction forces act on different objects, such as hand-on-cart and cart-on-hand. A zero net force means no acceleration in the simple inertial-frame model and permits constant nonzero velocity. Mass affects response, not an extra permanent force needed just to keep moving.

What should we investigate next?

Which condition could be changed to test a remaining uncertainty in this explanation? State the predicted observation and what result would challenge your model.

Investigate, explain and revise

Use these tasks after the three teaching sessions as needed. Discuss an attempted explanation before opening response guidance; a matching sentence is less important than a supported mechanism.

Activity 1 · Explain the new evidence case

Assigned reading and preparation

Use the visible scenario above, Parts 1–4 and your first notebook model. No outside reading or equipment is required.

Your task

Illustrative carts of 2 kg and 4 kg each experience a 6 N horizontal net force. Other conditions are comparable. Calculate acceleration magnitudes, identify an equal-and-opposite interaction pair and explain why zero net force does not require rest. Write 100–150 words or give a labeled drawing with an equivalent oral explanation.

Success criteria

  • Use two relevant stated records or conditions.
  • Explain the mechanism rather than only repeat a definition.
  • Label observation and inference.
  • Name a changed model feature or a remaining uncertainty.
Hint

Read the stated boundary and conditions before selecting a relationship. The unit’s worked examples show intermediate steps.

Response guidance — discuss after your attempt

Accelerations are 3 and 1.5 m/s² because a=Fnet/m. Equal interaction forces act on different objects, such as hand-on-cart and cart-on-hand. A zero net force means no acceleration in the simple inertial-frame model and permits constant nonzero velocity. Mass affects response, not an extra permanent force needed just to keep moving.

Activity 2 · Read and extend the figure

Assigned reading and preparation

Study the new labeled figure and its caption, then compare it with the associated teaching part.

Your task

What happens if mass and force both double? Explain what each important label represents. Add one missing feature that would be needed for a different question, and explain why the original figure leaves it out.

Success criteria

  • Answer the figure question with its stated labels.
  • Connect the visual representation to the scientific idea.
  • Identify a specific limitation from the caption.
  • Propose a useful change without misrepresenting supplied evidence.
Hint

For the same 6 N net force, doubling mass halves acceleration from 3 to 1.5 m/s². The bars represent rates of velocity change, not current velocity or distance. Equal net force is a condition of this comparison; interaction pairs would require named separate receivers.

Response guidance — discuss after your attempt

The ratio Fnet/m, and thus acceleration, remains unchanged in this simple model. For the same 6 N net force, doubling mass halves acceleration from 3 to 1.5 m/s². The bars represent rates of velocity change, not current velocity or distance. Equal net force is a condition of this comparison; interaction pairs would require named separate receivers.

Words to know

inertia
The tendency of an object to resist a change in its motion.
Newton's first law
An object at rest stays at rest, and an object in motion stays in motion at constant velocity, unless acted on by an unbalanced force.
Newton's second law
Force equals mass times acceleration: F = ma.
Newton's third law
For every action force, there is an equal and opposite reaction force.
newton (N)
The unit used to measure force; 1 newton = 1 kg·m/s².
model
A representation that explains selected features and makes predictions; it leaves other details out.
evidence
Relevant observations or records used to support or challenge a claim.
system boundary
The chosen limit separating the objects being studied from their surroundings.
assumption
A condition taken as true for a model or calculation and needing to be checked against the case.

Newton stood on giants' shoulders — and corrected a 2,000-year-old mistake

The ancient Greek philosopher Aristotle taught that a constant force was needed to keep anything moving, and that objects naturally wanted to come to rest — an idea that felt intuitive and went essentially unquestioned for almost 2,000 years. Galileo's experiments with rolling balls suggested otherwise: on a perfectly frictionless surface, a moving object would just keep going forever. In 1687, Isaac Newton formalized this insight as his first law in a book called the Principia Mathematica, one of the most influential science books ever written, building directly on Galileo's and Johannes Kepler's earlier work.

Inertia depends on mass, not speed

It's tempting to think a fast-moving object has 'more inertia' than a slow one, but inertia only depends on mass — how much matter something has — not on how fast it's currently moving. A parked truck and a truck cruising at highway speed have exactly the same inertia (resistance to a change in motion), which is why it takes the same enormous force to start a heavy truck rolling as it does to bring it to a sudden stop. This is exactly why seatbelts and headrests exist: in a sudden stop, your body's inertia makes it want to keep moving forward (or your head want to stay still) even after the car has stopped.

Momentum and impulse: the hidden link between the second and third laws

Multiply an object's mass by its velocity and you get its momentum (p = mv) — a kind of 'quantity of motion.' It turns out force is really just how fast momentum changes: force × time = change in momentum. That's why airbags work: by stretching a car crash's stopping time from a fraction of a second into a slightly longer fraction of a second, the same change in momentum happens with much less force on your body. This connects directly to Newton's third law, too — the passenger pushes back on the airbag exactly as hard as the airbag pushes on the passenger.

Real rockets, real numbers: the third law at full throttle

The Saturn V rocket that carried astronauts to the Moon weighed nearly 3 million kilograms fully fueled, and its engines pushed exhaust gases downward with a combined thrust of over 34 million newtons at liftoff. By Newton's third law, that exhaust pushed back on the rocket with just as much force in the opposite direction — enough to overcome the rocket's enormous weight and accelerate it off the launch pad. No engine 'pushes against the air' the way a swimmer pushes against water; rockets work identically in the vacuum of space, since the action-reaction pair is between the rocket and its own exhaust, not the surrounding air.

In the real world

Newton's third law explains exactly how rockets launch into space — by pushing exhaust gas downward, they get pushed upward in return.

Exit check

What happens if mass and force both double? Explain the relevant mechanism and one model limitation.

Check your explanation after answering

The ratio Fnet/m, and thus acceleration, remains unchanged in this simple model. For the same 6 N net force, doubling mass halves acceleration from 3 to 1.5 m/s². The bars represent rates of velocity change, not current velocity or distance. Equal net force is a condition of this comparison; interaction pairs would require named separate receivers.

Explain your reasoning without notes. If a key idea is missing, revisit the lesson and try again.

Problem 1

A 10 kg object experiences a net force of 50 N. What is its acceleration?
Answer and explanation

5 m/s²

a = F ÷ m = 50 ÷ 10 = 5 m/s².

Problem 2

What net force is needed to accelerate a 2 kg ball at 6 m/s²?
Answer and explanation

12 N

F = ma = 2 × 6 = 12 N.

Problem 3

A 1,500 kg car accelerates at 2 m/s². What net force does the engine provide?
Answer and explanation

3000 N

F = ma = 1,500 × 2 = 3,000 N.

Problem 4

An astronaut floating in deep space, far from any forces, will…
  1. slowly stop on her own
  2. continue moving at constant velocity forever
  3. accelerate away with no cause
  4. spin uncontrollably
Answer and explanation

continue moving at constant velocity forever

With no unbalanced force acting on her, Newton's first law says her velocity won't change.

Problem 5

When a swimmer pushes backward on the water, the water pushes the swimmer forward. This illustrates Newton's…
  1. first law
  2. second law
  3. third law
  4. law of gravity
Answer and explanation

third law

This is an action-reaction pair, which is Newton's third law.

Problem 6

A rocket's engines produce 12,000 N of thrust, accelerating it at 4 m/s². What is the rocket's mass?
Answer and explanation

3000 kg

m = F ÷ a = 12,000 ÷ 4 = 3,000 kg.

Problem 7

A net horizontal force of 12 N acts on a 4 kg cart. Calculate acceleration and identify the reaction to a hand's push. Explain the reasoning in your own words.
Answer and explanation

3 m/s² in the net-force direction; the cart exerts an equal opposite force on the hand.

Acceleration=Fnet/m=12/4=3 m/s².

The reaction to the hand pushing the cart is the cart pushing the hand, on a different object.

Response criteria

  • Use the stated conditions.
  • Show the evidence or calculation.
  • Explain the conclusion and any stated limitation.

Problem 8

Net force 20 N acts on a 5 kg object. Find acceleration. Show the reasoning, not just the conclusion.
Hints

Use net force on one object in Newton's second law.

Answer and explanation

20/5=4 m/s² in the net-force direction.

Problem 9

A passenger lurches forward when a bus brakes. Explain without inventing a new forward force.
Hints

State what the supplied observations or conditions establish, and separate that from any assumption.

Answer and explanation

The passenger's body tends to maintain its forward velocity; a restraint or contact must exert a backward force to slow it.

Problem 10

Plan two comparisons from the records: one isolating net force, the other mass. Specify motion measurements, repeats, controls and what outcome would challenge the predicted relation. Explain braking separately from velocity direction.
Hints

Use the illustrated study titled Investigate force and mass separately. Keep the observations, model and conditions separate.

Answer and explanation

Compare the 1 kg cases at 1 and 2 N to isolate net force; compare 1, 2 and 4 kg at 2 N to isolate mass. Match path, resisting conditions, timing, measuring procedure and initial state. Keep all repeated records. The supplied model gives a=Fnet/m; unexpected motion needs a boundary/force/method review rather than automatic rejection of conservation or hidden invented values. A leftward net force can slow rightward motion.

Compare the 1 kg cases at 1 and 2 N to isolate net force; compare 1, 2 and 4 kg at 2 N to isolate mass. Match path, resisting conditions, timing, measuring procedure and initial state. Keep all repeated records. The supplied model gives a=Fnet/m; unexpected motion needs a boundary/force/method review rather than automatic rejection of conservation or hidden invented values. A leftward net force can slow rightward motion.

Response criteria

  • Design two separately controlled comparisons.
  • Specify recorded motion, units and repeats.
  • Explain a challenge result and braking mechanism.

Problem 11

The cart diagram shows 10 N right and 4 N left on a 2 kg cart. A student calculates 5 m/s² using the push alone. Correct the method and say whether the cart must currently move right.
Answer and explanation

Net force is 6 N right; acceleration is 3 m/s² right. The current velocity is not given: the cart could be moving left and slowing.

Subtract resistance from the applied push.

Divide net force by mass.

Keep acceleration distinct from current motion.

Response criteria

  • Calculate 6 N and 3 m/s².
  • Do not count the green net arrow again.
  • Avoid inferring current velocity.

Problem 12

Zero net force allows rest OR constant velocityZero net force allows rest OR constant velocityNet force = 0: cart at rest0 s · 1 s · 2 sSame position each secondNet force = 0: cart at constant rightward velocity0 s1 s2 s
Equal-time snapshots can show no position change or equal changes in position. Both are consistent with zero net force in an inertial reference frame. The moving cart does not need a forward net force to keep its constant velocity. On a real surface, rolling resistance can slow it unless balanced. The rest snapshots overlap intentionally; no extra force called inertia should be drawn.
For this unit’s illustrated case, why is inertia not an extra force on a force diagram?
Answer and explanation

Inertia describes how mass resists acceleration. It is not an interaction from another object and should not be added as a force arrow.

A released toy cart slows due to interactions such as rolling resistance, not because motion uses up a stored force. A passenger’s motion changes when a seat or restraint exerts force; connect the law to interactions rather than calling inertia a pushing force.

Inertia describes how mass resists acceleration. It is not an interaction from another object and should not be added as a force arrow.

Response criteria

  • Use the named labels, directions or supplied quantities accurately.
  • Connect the visual evidence to the scientific mechanism or calculation.
  • State the relevant model conditions or limitation.

Problem 13

A 2.5 kg cart has a 15 N applied push and 5 N resistance. Find acceleration, and explain why its equal force on the pusher does not cancel that acceleration.
Answer and explanation

Net force is 10 N in the push direction and acceleration 10/2.5 = 4 m/s². The cart-on-pusher partner acts on the pusher, so it is not part of the cart’s net force.

Compute net force before dividing by mass.

Name the receiver of each interaction partner.

Net force is 10 N in the push direction and acceleration 10/2.5 = 4 m/s². The cart-on-pusher partner acts on the pusher, so it is not part of the cart’s net force.

Response criteria

  • Use the named labels, directions or supplied quantities accurately.
  • Connect the visual evidence to the scientific mechanism or calculation.
  • State the relevant model conditions or limitation.

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