Levers, Ramps & Pulleys — Print · Grade 8 Science

Chapter: Work & Machines

Levers, Ramps & Pulleys

Learning goals

Readings for this unit

Before this unit

Understand that useful work requires both force and distance.

Use three teaching sessions of about 40–45 minutes: first observe the phenomenon, draft a model and study Parts 1–2; next explain Parts 3–4 with the figures and evidence; then work the application, examples, practice, model revision and exit check. Divide any difficult part into smaller steps and revisit after feedback. Investigations, review and quizzes have separate sessions. Study the four visual parts across the scheduled sessions, then use the illustrated worked case and independent transfer questions. Extend or revisit a session when the learner cannot explain the figure; completion time is a proposed allocation, not a mastery guarantee.

Start with something to explain

What would explain the observations in levers, ramps & pulleys?

Illustrative evidence case. Illustrative ideal ramps raise the same load by 0.5 m. Ramp A is 1 m long and B 2 m long; measured input forces are 20 and 10 N under the simplified no-loss model.

A longer ramp trades distance for forceA longer ramp trades distance for forceRamp A: 1 m; 20 NRamp B: 2 m; 10 NSame load rises 0.5 m • ideal input work: 20 J each.Illustrative model • use the labels and stated assumptions
The labeled lengths and forces, rather than the schematic slopes, define the ideal comparison. Both raise the same load by 0.5 m, with 20 J input work in this no-loss model. A longer path reduces required force but does not make energy; real friction changes the input.

Notice and wonder

Why are these ramps not a scale drawing? Write two observations from the supplied record without guessing their cause. Include a quantity and its unit when given. An observation is what was recorded; an inference is what you think explains it.

Write one question about why the pattern occurs and one question about a comparison that could distinguish competing explanations. A testable question identifies what could be observed or measured.

Your first model

Before reading the model answer, sketch the named objects or particles and label what you think changes. Compare input work and explain the force–distance trade-off. State why actual friction would change the required input. Keep this first version so you can compare it with your later explanation.

Build the language from the idea

simple machine
A device that changes the size or direction of an applied force.
fulcrum
The pivot about which a lever turns.
ideal machine
A model with no dissipative energy losses.
model
A representation that explains selected features and makes predictions; it leaves other details out.
evidence
Relevant observations or records used to support or challenge a claim.
system boundary
The chosen limit separating the objects being studied from their surroundings.
assumption
A condition taken as true for a model or calculation and needing to be checked against the case.

A simple machine changes how a force is applied. A lever turns around a pivot, called a fulcrum. A ramp lets a load rise along a sloping path. A pulley redirects a rope; some pulley arrangements also reduce the input force. Machines help us complete tasks, but they do not make energy from nothing.

Three simple machinesThree ways to trade force against distanceLevereffortloadRamppush alongheightPulley4 supporting segmentsEach reduces the force needed and increases the distance moved — energy in is never less than out
All three make a job feel easier by the same bargain: less force over a greater distance. None of them reduces the energy required, which is the point the efficiency unit then quantifies.

An ideal machine can reduce the force needed by increasing the distance through which you apply it. A long, gently sloping ramp requires less force than a steep one to raise the same load slowly to the same height, ignoring friction. The gentler ramp requires a longer trip.

A fixed pulley can change the direction of a force without reducing its size. A movable pulley supported by more rope segments can reduce the pulling force, but more rope must be pulled. Real machines also transfer some energy to thermal energy and sound, so their input work exceeds their useful output work.

Count strands supporting the moving loadCount strands supporting the moving loadFixed pulley: one supporting strandMovable pulley: two supporting strands100 NPull 100 N; direction changes100 NPull 50 NEach supporting strand: 50 N
The fixed ideal pulley changes pulling direction but leaves a 100 N effort for a 100 N load. The movable ideal pulley is lifted by two rope strands with equal tension; 50 N in each supports the 100 N load. The model assumes negligible pulley/rope mass and friction, and the sketches are reasoning tools rather than construction instructions.

A machine can reduce the input force by increasing the input distance. An ideal ramp spreads the work of raising a load over a longer path. It does not reduce the required gain in gravitational potential energy.

For a lever, turning effect depends on force and its perpendicular distance from the pivot. A long effort arm can balance a larger load on a short arm. For a pulley system, count the rope segments actually supporting the moving load; a fixed pulley may change direction without reducing effort.

Real machines have friction and can bend or slip, so input work usually exceeds useful output work. Compare designs for the same load and height, measure both effort and travel, and keep fingers clear of pinch points. A smaller force does not by itself show a smaller energy requirement.

Build your understanding

Use three teaching sessions of about 40–45 minutes: first observe the phenomenon, draft a model and study Parts 1–2; next explain Parts 3–4 with the figures and evidence; then work the application, examples, practice, model revision and exit check. Divide any difficult part into smaller steps and revisit after feedback. Investigations, review and quizzes have separate sessions.

Part 1 · Use a machine to change a task

Simple machines can change force magnitude, force direction, or where a force is applied. They do not create energy. An ideal machine trades force against movement distance; real machines also transfer some input energy to less useful stores. Identify the input action and useful output before comparing designs.

Three simple machinesThree ways to trade force against distanceLevereffortloadRamppush alongheightPulley4 supporting segmentsEach reduces the force needed and increases the distance moved — energy in is never less than out
All three make a job feel easier by the same bargain: less force over a greater distance. None of them reduces the energy required, which is the point the efficiency unit then quantifies.

Read the visual model

Must every simple machine reduce force?

Visual reasoning — after your attempt

No. Some primarily change direction or trade increased force for a movement or speed advantage. Describe the actual input and output rather than assuming a force reduction.

An ideal ramp raises a load with a smaller force acting over a longer distance than a vertical lift. A fixed pulley may mainly change pulling direction. Being called a machine does not automatically mean the input force is reduced.

Pause and explain

Must every simple machine reduce force?

Check your reasoning after answering

No. Some primarily change direction or trade increased force for a movement or speed advantage. Describe the actual input and output rather than assuming a force reduction.

Part 2 · Explain a lever with turning effects

A lever turns about a pivot or fulcrum. The turning effect depends on the force and its perpendicular distance from the pivot. A longer input arm can balance a larger output force in a simple ideal static lever. Distances measured along an angled lever are not always the perpendicular moment arms.

A lever trades force against its distance from the pivotA lever trades force against its distance from the pivotEffort: 75 N downLoad on lever: 300 N downPivot support upArm: 4 m1 mTurning effects: 75×4 = 300×1. Forces shown act on the lever.
The ideal lever is balanced when the 75 N effort acts 4 m from the pivot and the 300 N load force acts 1 m from it. The turning effects match even though the forces differ. Both downward red arrows are forces on the lever; its upward force on the load is a different receiver’s force. Arrow lengths are qualitative here, while the arm distances and force labels supply the calculation.

Read the visual model

The pivot is the turning point. A force’s perpendicular distance from it affects turning. The lever does not create energy; during a small movement the long effort end travels farther than the short load end.

Why can the smaller effort balance the larger load force? Would moving the effort closer to the pivot keep the same balance?

Visual reasoning — after your attempt

Its arm is four times as long: 75×4 = 300×1. Moving the effort closer reduces its turning effect, so a larger effort would be needed under the same ideal conditions.

With a 0.4 m input arm and 0.1 m output arm, a 10 N perpendicular input can balance a 40 N output load. Both turning effects are 4 N·m. This is a balance model; acceleration and friction require more information.

Lever model compares a 10 newton input over a 0.4 meter arm with a 40 newton output over a 0.1 meter arm.Input 10 NLoad 40 NInput arm 0.4 m0.1 mPivotEqual turning effects: 10 × 0.4 = 40 × 0.1 = 4 N·m
Ideal static lever model. The input and load both act downward on the lever, on opposite sides of the pivot. Their perpendicular moment arms are 0.4 m and 0.1 m. The lever in turn pushes upward on the load with 40 N. Read the labels rather than measuring the sketch.

Pause and explain

Why can pushing farther from the pivot reduce the needed force?

Check your reasoning after answering

A larger perpendicular distance gives a larger turning effect for the same force. A smaller force can then balance the same load turning effect.

Part 3 · Compare ramps by height and path

An ideal frictionless ramp of length L and height h requires a parallel input force equal to load weight×h/L for steady motion. Increasing length while keeping height fixed reduces the ideal input force. The required gravitational energy change still depends on the same height gain.

A longer ramp trades distance for forceA longer ramp trades distance for forceRamp A: 1 m; 20 NRamp B: 2 m; 10 NSame load rises 0.5 m • ideal input work: 20 J each.Illustrative model • use the labels and stated assumptions
The labeled lengths and forces, rather than the schematic slopes, define the ideal comparison. Both raise the same load by 0.5 m, with 20 J input work in this no-loss model. A longer path reduces required force but does not make energy; real friction changes the input.

Read the visual model

What changes when the ramp gets longer but the rise stays the same?

Visual reasoning — after your attempt

The ideal input force becomes smaller and input distance larger. The gravitational energy increase remains the same for the same load and height.

For a 60 N load and 1 m rise, a 3 m ideal ramp requires 20 N parallel pull. Input work=20×3=60 J, equal to 60×1 J for the vertical lift. A rough ramp needs extra input for resistance.

Pause and explain

What changes when the ramp gets longer but the rise stays the same?

Check your reasoning after answering

The ideal input force becomes smaller and input distance larger. The gravitational energy increase remains the same for the same load and height.

Part 4 · Count supporting rope segments in a pulley model

An ideal movable pulley can distribute a load across supporting rope segments with equal tension. A fixed pulley changes direction without the same force advantage. Rope movement increases as more supporting segments lift the load. Friction, rope mass, and changing geometry can reduce the real advantage.

Count strands supporting the moving loadCount strands supporting the moving loadFixed pulley: one supporting strandMovable pulley: two supporting strands100 NPull 100 N; direction changes100 NPull 50 NEach supporting strand: 50 N
The fixed ideal pulley changes pulling direction but leaves a 100 N effort for a 100 N load. The movable ideal pulley is lifted by two rope strands with equal tension; 50 N in each supports the 100 N load. The model assumes negligible pulley/rope mass and friction, and the sketches are reasoning tools rather than construction instructions.

Read the visual model

Tension is the pull transmitted along a rope. Count strands that act on the moving load/pulley assembly, not every segment visible in the picture. A fixed pulley alone does not automatically double force advantage.

For the movable case, how much rope must be pulled to raise the load 0.5 m ideally?

Visual reasoning — after your attempt

1 m: both supporting strands shorten by 0.5 m as the load rises. The force reduction trades for greater effort travel, leaving ideal work unchanged.

Two vertical rope segments supporting a 40 N load each carry 20 N in the ideal balanced model. Lifting the load 0.5 m requires taking in 1 m of rope. Count segments actually supporting the moving load, not every visible rope piece.

Pause and explain

Why does a two-supporting-segment pulley require more rope movement?

Check your reasoning after answering

Both supporting segments shorten when the load rises. The input rope must supply twice the load’s upward distance in the ideal arrangement.

Apply the whole unit · Choose a lifting method

Illustrative ideal choices for raising a 60 N load through 0.5 m: vertical lift; a frictionless 2 m ramp; a pulley with two vertical supporting rope segments. Ignore machine weight and friction.

Your task

Calculate input force and input distance for each method, compare input work, and explain a practical constraint that could favor one method. Sketch the ramp or pulley with labels.

What your response should show

  • Use the supplied observations and measurements accurately; include units where needed.
  • Explain the science behind your answer, rather than giving only a number or label.
  • Show a labeled model, calculation, or evidence comparison as requested.
  • State an assumption or limitation and suggest a useful next measurement.
Response guidance — after your attempt

Vertical:60 N over 0.5 m. Ramp:60×0.5/2=15 N over 2 m. Pulley:30 N over 1 m of input rope. Each ideal input is 30 J. Space, secure attachment, or friction may change the practical choice and real input. The smaller force does not reduce the ideal energy needed for the same height.

Scientific references and adapted teaching resources

Parent / teacher teaching notes

Use sketches and energy accounts before remembering machine formulas. Specify perpendicular lever arms and supporting pulley segments. The application is a design calculation, not a request to rig lifting equipment. Adaptation credit: OpenSciEd middle-school teaching routines and public task structures by OpenSciEd, CC BY 4.0. This independent version adds original explanatory text, data and figures, terminology support and a home-study schedule. It does not reproduce the complete teacher editions or their classroom validation.

The key idea

Simple machines trade force for distance or change force direction; they do not create energy.

Worked examples

Example 1

Two frictionless ramps reach the same 0.5 m platform. One is 1 m long and one is 2 m long. Which needs less force to raise the same load slowly?
  1. Both increase the load’s gravitational potential energy by the same amount.
  2. The 2 m ramp allows the force to act over twice the distance.
Answer: The 2 m ramp requires half the force; the ideal input work is the same.

Example 2 · Worked application

An ideal ramp raises a 100 N load by 1 m over a 5 m ramp. Compare the aligned pulling force with lifting directly.
  1. The needed gravitational-energy increase is 100×1=100 J.
  2. For a frictionless aligned pull over 5 m, F×5=100.
  3. F=20 N, but the pull acts over five times the distance.
Answer: 20 N on the ideal ramp versus 100 N for a direct slow lift.
Check the reasoning

Both ideal methods transfer 100 J; the ramp does not create energy.

Example 3

An ideal ramp raises a 60 N load by 0.5 m over a 3 m path. Find output work and ideal input force.
  1. Output work=60×0.5=30 J.
  2. Ideal input work is also 30 J; force=30/3=10 N.
Answer: 30 J of output work and 10 N ideal effort, ignoring friction.

Example 4 · Find and fix the mistake

Context: An ideal ramp raises a 100 N load by 1 m over a 5 m ramp. Compare the aligned pulling force with lifting directly. A student claims: “A machine reduces force, so it must also reduce ideal input work.” Evaluate the claim and write a corrected explanation.
  1. Test the claim against the stated conditions: Both ideal methods transfer 100 J; the ramp does not create energy.
  2. Ideal force reduction trades for increased distance. Real friction usually increases required input work.
Answer: Ideal force reduction trades for increased distance. Real friction usually increases required input work.
Check the reasoning

Both ideal methods transfer 100 J; the ramp does not create energy.

Example 5 · Interpret the visual model

A lever trades force against its distance from the pivotA lever trades force against its distance from the pivotEffort: 75 N downLoad on lever: 300 N downPivot support upArm: 4 m1 mTurning effects: 75×4 = 300×1. Forces shown act on the lever.
The ideal lever is balanced when the 75 N effort acts 4 m from the pivot and the 300 N load force acts 1 m from it. The turning effects match even though the forces differ. Both downward red arrows are forces on the lever; its upward force on the load is a different receiver’s force. Arrow lengths are qualitative here, while the arm distances and force labels supply the calculation.
Why can the smaller effort balance the larger load force? Would moving the effort closer to the pivot keep the same balance?
  1. Identify the represented objects, axes, labeled quantities and stated conditions before choosing a rule.
  2. The pivot is the turning point. A force’s perpendicular distance from it affects turning. The lever does not create energy; during a small movement the long effort end travels farther than the short load end.
  3. Its arm is four times as long: 75×4 = 300×1. Moving the effort closer reduces its turning effect, so a larger effort would be needed under the same ideal conditions.
Answer: Its arm is four times as long: 75×4 = 300×1. Moving the effort closer reduces its turning effect, so a larger effort would be needed under the same ideal conditions.
Check the reasoning

Keep the model’s stated limits explicit: The ideal lever is balanced when the 75 N effort acts 4 m from the pivot and the 300 N load force acts 1 m from it. The turning effects match even though the forces differ. Both downward red arrows are forces on the lever; its upward force on the load is a different receiver’s force. Arrow lengths are qualitative here, while the arm distances and force labels supply the calculation.

Avoid these mistakes

Check your understanding

An ideal ramp raises a 60 N load by 0.5 m over a 3 m path. Find output work and ideal input force.

Discuss the answer

30 J of output work and 10 N ideal effort, ignoring friction.

Why does a longer ramp reduce force without creating energy?

Discuss the answer

A machine can reduce the input force by increasing the input distance. An ideal ramp spreads the work of raising a load over a longer path. It does not reduce the required gain in gravitational potential energy. For a lever, turning effect depends on force and its perpendicular distance from the pivot. A long effort arm can balance a larger load on a short arm. For a pulley system, count the rope segments actually supporting the moving load; a fixed pulley may change direction without reducing effort.

Return to the phenomenon

Illustrative ideal ramps raise the same load by 0.5 m. Ramp A is 1 m long and B 2 m long; measured input forces are 20 and 10 N under the simplified no-loss model. Compare input work and explain the force–distance trade-off. State why actual friction would change the required input. Revise your first explanation using a named idea from the lesson. Mark the changed part and the evidence that supports it.

Compare explanations after your attempt

Both have modeled input work 20 J: 20×1 and 10×2. The longer ramp reduces force while increasing travel distance for the same lift; it does not make energy. Actual friction can require greater input work and introduce thermal transfers. The simple along-ramp calculation uses the stated force direction and ideal model.

What should we investigate next?

Which condition could be changed to test a remaining uncertainty in this explanation? State the predicted observation and what result would challenge your model.

Investigate, explain and revise

Use these tasks after the three teaching sessions as needed. Discuss an attempted explanation before opening response guidance; a matching sentence is less important than a supported mechanism.

Activity 1 · Explain the new evidence case

Assigned reading and preparation

Use the visible scenario above, Parts 1–4 and your first notebook model. No outside reading or equipment is required.

Your task

Illustrative ideal ramps raise the same load by 0.5 m. Ramp A is 1 m long and B 2 m long; measured input forces are 20 and 10 N under the simplified no-loss model. Compare input work and explain the force–distance trade-off. State why actual friction would change the required input. Write 100–150 words or give a labeled drawing with an equivalent oral explanation.

Success criteria

  • Use two relevant stated records or conditions.
  • Explain the mechanism rather than only repeat a definition.
  • Label observation and inference.
  • Name a changed model feature or a remaining uncertainty.
Hint

Read the stated boundary and conditions before selecting a relationship. The unit’s worked examples show intermediate steps.

Response guidance — discuss after your attempt

Both have modeled input work 20 J: 20×1 and 10×2. The longer ramp reduces force while increasing travel distance for the same lift; it does not make energy. Actual friction can require greater input work and introduce thermal transfers. The simple along-ramp calculation uses the stated force direction and ideal model.

Activity 2 · Read and extend the figure

Assigned reading and preparation

Study the new labeled figure and its caption, then compare it with the associated teaching part.

Your task

Why are these ramps not a scale drawing? Explain what each important label represents. Add one missing feature that would be needed for a different question, and explain why the original figure leaves it out.

Success criteria

  • Answer the figure question with its stated labels.
  • Connect the visual representation to the scientific idea.
  • Identify a specific limitation from the caption.
  • Propose a useful change without misrepresenting supplied evidence.
Hint

The labeled lengths and forces, rather than the schematic slopes, define the ideal comparison. Both raise the same load by 0.5 m, with 20 J input work in this no-loss model. A longer path reduces required force but does not make energy; real friction changes the input.

Response guidance — discuss after your attempt

The drawn slopes and heights are arranged for readability. Use the stated 1 m, 2 m and 0.5 m dimensions for quantitative reasoning. The labeled lengths and forces, rather than the schematic slopes, define the ideal comparison. Both raise the same load by 0.5 m, with 20 J input work in this no-loss model. A longer path reduces required force but does not make energy; real friction changes the input.

Words to know

simple machine
A device that changes the size or direction of an applied force.
fulcrum
The pivot about which a lever turns.
ideal machine
A model with no dissipative energy losses.
model
A representation that explains selected features and makes predictions; it leaves other details out.
evidence
Relevant observations or records used to support or challenge a claim.
system boundary
The chosen limit separating the objects being studied from their surroundings.
assumption
A condition taken as true for a model or calculation and needing to be checked against the case.

In the real world

Exit check

Why are these ramps not a scale drawing? Explain the relevant mechanism and one model limitation.

Check your explanation after answering

The drawn slopes and heights are arranged for readability. Use the stated 1 m, 2 m and 0.5 m dimensions for quantitative reasoning. The labeled lengths and forces, rather than the schematic slopes, define the ideal comparison. Both raise the same load by 0.5 m, with 20 J input work in this no-loss model. A longer path reduces required force but does not make energy; real friction changes the input.

Explain your reasoning without notes. If a key idea is missing, revisit the lesson and try again.

Problem 1

A longer ramp to the same height usually trades…
  1. more force for less distance
  2. less force for more distance
  3. zero work for motion
  4. mass for energy
Answer and explanation

less force for more distance

The force acts over a longer distance.

Problem 2

A lever pivots around a…
  1. battery
  2. fulcrum
  3. magnetic pole
  4. wavelength
Answer and explanation

fulcrum

The fulcrum is its pivot.

Problem 3

Does a fixed pulley necessarily reduce the size of the force needed?
Answer and explanation

No. An ideal fixed pulley can redirect the force while leaving its size unchanged.

Problem 4

An ideal ramp raises a 60 N load by 0.5 m over a 3 m path. Find output work and ideal input force. Explain the reasoning in your own words.
Answer and explanation

30 J of output work and 10 N ideal effort, ignoring friction.

Output work=60×0.5=30 J.

Ideal input work is also 30 J; force=30/3=10 N.

Response criteria

  • Use the stated conditions.
  • Show the evidence or calculation.
  • Explain the conclusion and any stated limitation.

Problem 5

An ideal pulley uses two supporting rope segments for a 60 N load. Find pulling force during a slow lift. Show the reasoning, not just the conclusion.
Hints

Both ideal methods transfer 100 J; the ramp does not create energy.

Answer and explanation

60/2=30 N, with the free end moving twice the load's distance.

Problem 6

Why does a real rough ramp require more than the ideal predicted force?
Hints

State what the supplied observations or conditions establish, and separate that from any assumption.

Answer and explanation

Friction transfers some input energy to thermal energy, so input work must exceed the load's gravitational-energy increase.

Problem 7

Why are these ramps not a scale drawing?
Answer and explanation

The drawn slopes and heights are arranged for readability. Use the stated 1 m, 2 m and 0.5 m dimensions for quantitative reasoning.

The drawn slopes and heights are arranged for readability. Use the stated 1 m, 2 m and 0.5 m dimensions for quantitative reasoning.

Response criteria

  • Use the supplied conditions and relevant evidence.
  • Explain the scientific mechanism or calculation.
  • State a meaningful limitation or testable next step.

Problem 8

Illustrative ideal ramps raise the same load by 0.5 m. Ramp A is 1 m long and B 2 m long; measured input forces are 20 and 10 N under the simplified no-loss model. Compare input work and explain the force–distance trade-off. State why actual friction would change the required input.
Answer and explanation

Both have modeled input work 20 J: 20×1 and 10×2. The longer ramp reduces force while increasing travel distance for the same lift; it does not make energy. Actual friction can require greater input work and introduce thermal transfers. The simple along-ramp calculation uses the stated force direction and ideal model.

Both have modeled input work 20 J: 20×1 and 10×2. The longer ramp reduces force while increasing travel distance for the same lift; it does not make energy. Actual friction can require greater input work and introduce thermal transfers. The simple along-ramp calculation uses the stated force direction and ideal model.

Response criteria

  • Use the supplied conditions and relevant evidence.
  • Explain the scientific mechanism or calculation.
  • State a meaningful limitation or testable next step.

Problem 9

A lever trades force against its distance from the pivotA lever trades force against its distance from the pivotEffort: 75 N downLoad on lever: 300 N downPivot support upArm: 4 m1 mTurning effects: 75×4 = 300×1. Forces shown act on the lever.
The ideal lever is balanced when the 75 N effort acts 4 m from the pivot and the 300 N load force acts 1 m from it. The turning effects match even though the forces differ. Both downward red arrows are forces on the lever; its upward force on the load is a different receiver’s force. Arrow lengths are qualitative here, while the arm distances and force labels supply the calculation.
For this unit’s illustrated case, why can the smaller effort balance the larger load force? Would moving the effort closer to the pivot keep the same balance?
Answer and explanation

Its arm is four times as long: 75×4 = 300×1. Moving the effort closer reduces its turning effect, so a larger effort would be needed under the same ideal conditions.

The pivot is the turning point. A force’s perpendicular distance from it affects turning. The lever does not create energy; during a small movement the long effort end travels farther than the short load end.

Its arm is four times as long: 75×4 = 300×1. Moving the effort closer reduces its turning effect, so a larger effort would be needed under the same ideal conditions.

Response criteria

  • Use the named labels, directions or supplied quantities accurately.
  • Connect the visual evidence to the scientific mechanism or calculation.
  • State the relevant model conditions or limitation.

Problem 10

For an ideal balanced lever, the load exerts 180 N at an arm 0.2 m long. The effort arm is 0.6 m. Find the effort force and explain its distance tradeoff.
Answer and explanation

Effort is 180×0.2/0.6 = 60 N. The effort end travels about three times the load-end distance for the small-motion ideal comparison; the lever does not create energy.

Match turning effects F×arm on opposite sides.

Connect the 3:1 arm ratio to effort travel as well as force.

Effort is 180×0.2/0.6 = 60 N. The effort end travels about three times the load-end distance for the small-motion ideal comparison; the lever does not create energy.

Response criteria

  • Use the named labels, directions or supplied quantities accurately.
  • Connect the visual evidence to the scientific mechanism or calculation.
  • State the relevant model conditions or limitation.

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