Periodic Trends — Print · Grade 11 Science
Chapter: Atoms, Electrons & PeriodicityPeriodic Trends
Learning goals
- I can describe how atomic radius, ionization energy, and electronegativity change across a period and down a group.
- I can explain these trends using effective nuclear charge, shielding, and distance from the nucleus.
- I can use the trends to compare two elements and predict relative reactivity.
Readings for this unit
Before this unit
Nuclear attraction, shielding, and periodic structure.
Use the detailed parent plan: two core 50–60-minute sessions per focused unit, with a third assigned for selected calculation/modeling topics. First study the core explanation and Parts 1–2 with their figures/checks; next study Parts 3–4, the whole-unit application, worked cases, varied practice and exit check. Attempt reasoning before opening guidance. Extend time when actual understanding requires it; investigations and chapter assessments have separate sessions.
Start with something to explain
Why does an ion’s electron count not completely determine its size?
Illustrative evidence case. O²⁻ and Na⁺ each have ten electrons but have different nuclear charges.
Notice and wonder
Record two observations using the stated quantities or relationships. Keep observations separate from possible causes. Write one question that a new measurement could help answer.
Why does an ion’s electron count not completely determine its size?
Your first model
Sketch equal electron totals and label the nuclei separately.
Build the language from the idea
- atomic radius
- A measure of the size of an atom, roughly the distance from the nucleus to the outermost electrons.
- ionization energy
- The energy required to remove the most loosely held electron from a neutral atom.
- electronegativity
- A measure of how strongly an atom attracts the shared electrons in a chemical bond.
- effective nuclear charge (Zeff)
- The net positive pull actually felt by a valence electron, after inner electrons cancel out some of the nuclear charge.
- shielding (screening)
- The way inner-shell electrons block, or screen, valence electrons from feeling the full charge of the nucleus.
- periodic trend
- A predictable pattern in a property that repeats as you move across periods or down groups.
Because the periodic table is arranged by electron configuration, its properties do not scatter randomly — they slide in smooth, predictable periodic trends. Almost every trend comes down to a tug-of-war between two forces: the nucleus pulling valence electrons inward, and the distance and shielding pushing back. Learn to weigh those two factors and you can predict an element's behavior from its address on the table alone.
The key concept is effective nuclear charge (Zeff) — the net pull a valence electron actually feels once the inner electrons have canceled out part of the nuclear charge by shielding it. Moving left to right across a period, protons are added to the nucleus while the new electrons all crowd into the same energy level, adding almost no extra shielding. So Zeff climbs steadily across a period, gripping the valence electrons ever more tightly. Moving down a group, each step adds a whole new shell of electrons, so the valence electrons sit farther out and are better shielded — the nucleus's grip on them loosens.
Atomic radius follows directly. Across a period, rising Zeff pulls the electron cloud inward, so atoms get smaller left to right — even though you are adding electrons. Down a group, each new energy level puts the outermost electrons farther from the nucleus, so atoms get larger top to bottom. Put together: the biggest atoms sit at the bottom-left of the table (like cesium) and the smallest nonmetal atoms at the top-right (like fluorine).
Ionization energy — the energy needed to yank off the outermost electron — runs as the mirror image of radius, and for the same reason. In a small atom with high Zeff, the outer electron is held close and tight, so it takes a lot of energy to remove: ionization energy increases across a period. In a large atom, the outer electron is far away and well shielded, so it comes off easily: ionization energy decreases down a group. Whenever an electron is held tightly, it is both hard to remove and hard to pull away — so small atoms tend to have high ionization energies.
Electronegativity measures how strongly an atom pulls on the electrons it *shares* in a bond, and it follows the same pattern as ionization energy: it increases across a period and decreases down a group. That makes fluorine, at the top right (noble gases aside), the most electronegative element of all. On the widely used Pauling scale fluorine is set near 4.0, while the reactive metals at the bottom left score below 1.0. Noble gases are usually left out because they rarely bond at all.
These three trends together explain reactivity, which is the bridge to chemical bonding. Metals on the lower left have large radii, low ionization energies, and low electronegativities, so they give up electrons easily — that is why cesium reacts explosively while its group-mate lithium reacts more gently. Nonmetals on the upper right have small radii, high ionization energies, and high electronegativities, so they grab electrons hungrily — which is why fluorine is the most aggressive nonmetal there is. Read an element's position, weigh Zeff against distance, and the periodic table becomes a working prediction machine — exactly the promise of this unit's essential question.
Model check: General trends have exceptions; do not use a trend arrow as an exact numerical table. K has an occupied outer shell farther from the nucleus with more inner shielding, outweighing its greater proton count in this comparison.
Build your understanding
Use the detailed parent plan: two core 50–60-minute sessions per focused unit, with a third assigned for selected calculation/modeling topics. First study the core explanation and Parts 1–2 with their figures/checks; next study Parts 3–4, the whole-unit application, worked cases, varied practice and exit check. Attempt reasoning before opening guidance. Extend time when actual understanding requires it; investigations and chapter assessments have separate sessions.
Part 1 · Balance nuclear attraction with shielding
Shielding describes how other electrons affect the attraction experienced by an electron. Effective nuclear charge is a useful model of the net attraction after these interactions are considered. Across many main-group periods, increasing Z with similar shell structure tends to draw outer density inward. Down a group, additional occupied shells often increase size despite greater Z. An atomic radius also depends on how it is defined and measured, so compare compatible radius datasets rather than treating a cartoon boundary as an exact surface.
Read the visual model
Identify the labeled structures and units, then trace the arrows or compare values under the caption’s stated conditions. Separate the displayed evidence from a further inference. Write your reasoning before opening the guidance.
Why can an atom farther down a group be larger despite having more protons?
Visual reasoning — after your attempt
Added occupied shells and shielding can place outer electron density farther from the nucleus; proton count alone does not fix radius.
Outer-electron attraction depends on nuclear charge, shielding by other electrons, distance, and electron interactions. Across many periods, increasing effective attraction tends to contract atomic radius. Down many groups, added shells increase size. These competing factors explain broad trends rather than relying on arrows alone.
Compare main-group atoms within one period, then atoms in one group. State which factor changes before predicting size. The word bigger needs a defined radius convention.
Optional guided lab · Test a trend and its limits
Optional guided lab · Test a trend and its limits
Optional external exploration — WeduLab. Complete the local explanation first. The task and practice record here are independently written for this course. Choose this in place of comparable practice or allow extra time; it does not add a required session to the year plan.
Predict the broad atomic-size order for neutral Na, Mg and Cl, then predict whether Na or K is larger. Atomic radius depends on how a size is defined from experimental or calculated evidence. Compare like radius definitions; do not mix an ionic radius with a neutral atom’s radius.
Explore for about 15–20 minutes after the attraction/shielding explanation. Select the atomic-radius display and compare Na, Mg and Cl across period 3; then compare Na and K down group 1. Record the property name, units and any stated radius definition before recording values. Switch to first ionization energy and note whether its broad trend reverses. If the source does not identify a radius convention, make only a qualitative comparison and state that limitation.
The column heights and colored atom pictures represent selected data or schematic models, not literal atom shapes or electron tracks. The simple outer-electron/group pattern works most directly for selected main-group elements; it is not a universal counting rule for transition elements, and helium is an exception to the common eight-valence-electron noble-gas pattern. A general trend does not eliminate measured exceptions.
No-lab route: the original supplied record below contains everything needed for the question. It is not measured evidence collected from WeduLab. Label any separate observations you collect as simulation output, with settings and date.
| Original comparison task | Atomic numbers | Broad neutral-atom size prediction |
|---|---|---|
| Across period 3: Na, Mg, Cl | 11, 12, 17 | Na > Mg > Cl, comparing a consistent size convention |
| Down group 1: Na, K | 11, 19 | K > Na |
| Na⁺ and Mg²⁺ ions | 11 and 12; both have 10 electrons | Mg²⁺ smaller than Na⁺ in a consistent ionic comparison |
Question 1
Explain the two neutral-atom comparisons, then explain why the Na⁺/Mg²⁺ comparison is a different kind of comparison. Why should a student avoid copying a radius number without its definition?
Worked solution and marking guidance
Across the selected period, increasing nuclear charge with electrons in the same principal valence shell generally increases effective attraction and reduces size.
Down group 1, an additional occupied principal shell and shielding generally increase size.
The two selected ions are isoelectronic, meaning they have the same electron count; Mg²⁺ has the greater nuclear charge. Ionic radii and neutral-atom radii are different quantities and depend on conventions and context.
The qualitative orders follow the stated comparisons; the table supplies reasoning tasks rather than measured radius values. A radius number without its type, units and context can support an invalid comparison.
- Explain attraction and shielding rather than memorizing an arrow.
- Keep neutral and ionic comparisons distinct.
- Record the property definition and acknowledge exceptions and model limits.
Pause and explain
Why can a larger proton count accompany a smaller atom across a period?
Check your reasoning after answering
Greater effective nuclear attraction can pull the occupied cloud closer when shielding changes less than nuclear charge within the same principal shell.
Part 2 · Distinguish ionization energy and electronegativity
First ionization energy is the energy required to remove an electron from an isolated gaseous atom in the specified state. Electronegativity instead describes an atom’s tendency to attract shared electron density in a bond and depends on a chosen scale. They can have related broad trends but are not interchangeable units or definitions. Electron affinity adds another distinct electron-addition energy account. State the process, charge state and conditions before comparing numbers or predicting bonding behavior.
Read the visual model
Identify the labeled structures and units, then trace the arrows or compare values under the caption’s stated conditions. Separate the displayed evidence from a further inference. Write your reasoning before opening the guidance.
Does a high electronegativity value directly give the energy required to remove an electron from a gaseous atom?
Visual reasoning — after your attempt
No. Electronegativity concerns bonded electron attraction on a model scale; ionization energy is a specified removal energy.
First ionization energy concerns removing an electron from an isolated gaseous atom. Electronegativity is a bonding-context tendency to attract shared electrons. Electron affinity describes another energy change and is not identical to either term. Similar trend directions do not make these quantities interchangeable.
A high first-ionization-energy value suggests difficult electron removal under its defined conditions. It does not directly give a bond energy or a complete reaction-rate prediction.
Pause and explain
Why should ionization energy not be described as attraction to shared electrons?
Check your reasoning after answering
That describes electronegativity. Ionization energy is energy associated with removing an electron from a specified gaseous particle.
Part 3 · Compare ions using electron count and nuclear charge
Isoelectronic species have the same electron count under the compared state. O²⁻, F⁻ and Na⁺ each have ten electrons, but their proton counts rise from eight to eleven. Within this selected series, stronger nuclear attraction generally contracts the electron distribution, giving O²⁻ the larger and Na⁺ the smaller radius under compatible definitions. This is different from saying every positive ion of every element is smaller than every negative ion. Match the electron count and comparison conditions first.
Read the visual model
Identify the labeled structures and units, then trace the arrows or compare values under the caption’s stated conditions. Separate the displayed evidence from a further inference. Write your reasoning before opening the guidance.
Which is smallest in the displayed isoelectronic series, and which variable supports the comparison?
Visual reasoning — after your attempt
Na⁺ is smallest in the usual comparison; all three have ten electrons but Na⁺ has the largest proton count, 11.
Cations often have smaller radii than their corresponding neutral atoms; anions often larger. In an isoelectronic sequence, greater nuclear charge usually produces a smaller radius because the same electron population experiences stronger attraction. Use consistent radius data rather than comparing unrelated conventions.
O²⁻, F⁻, Na⁺, and Mg²⁺ each have ten electrons. Increasing proton count from 8 to 12 gives a useful decreasing-radius prediction across that sequence.
Pause and explain
Why does equal electron count not mean equal ionic radius?
Check your reasoning after answering
Different proton counts change nuclear attraction to the same number of electrons. Electron count alone does not determine radius.
Part 4 · Use exceptions to refine the model
Broad periodic tendencies reflect nuclear charge, shell occupancy and electron interactions. Local ionization-energy exceptions can arise when an electron enters a higher-energy subshell or begins pairing in an orbital. Such departures refine the explanation rather than invalidate every periodic comparison. An invented trend graph can teach how to reason about a local dip, but real element assignments and numeric values require an appropriate reference table. Never treat a broad arrow as an exact ranking without checking the species and quantity.
Read the visual model
Identify the labeled structures and units, then trace the arrows or compare values under the caption’s stated conditions. Separate the displayed evidence from a further inference. Write your reasoning before opening the guidance.
Why does one local dip not show that increasing nuclear charge has no influence?
Visual reasoning — after your attempt
Several effects operate together; a change in subshell or pairing can offset part of the nuclear-attraction tendency for that comparison.
Subshell structure and electron pairing can create departures from a smooth ionization-energy trend. A large jump in successive ionization energies can suggest removal from an inner shell after valence electrons are gone. Do not treat a trend as proof that each neighboring pair must follow it.
If successive removals have moderately increasing energies followed by a very large jump after two electrons, a two-valence-electron interpretation may be appropriate for the supplied main-group model.
Pause and explain
What can a large successive-ionization jump suggest?
Check your reasoning after answering
It can indicate that outer electrons have been removed and the next electron belongs to a more tightly bound inner-shell arrangement.
Apply the whole unit · Rank an isoelectronic series
Illustrative ions O²⁻, F⁻, Na⁺, and Mg²⁺ have proton counts 8, 9, 11, and 12 and each has ten electrons. Use the introductory isoelectronic-radius model.
Your task
Predict the radius order, explain the mechanism, compare Na and Na⁺ qualitatively, and state why the same rule cannot rank every arbitrary pair of atoms without considering shells and reference data.
What your response should show
- Choose the appropriate chemical model or relationship and state its conditions.
- Show substitutions, units, particle or charge counts, and intermediate reasoning as relevant.
- Use supplied evidence to justify the conclusion; distinguish observation from inference.
- Identify a meaningful limitation, uncertainty, or next measurement.
Response guidance — after your attempt
Verify electron count: 8+2, 9+1, 11−1, 12−2 all equal 10.
Compare nuclear charge with the same electron population.
Predict decreasing radius: O²⁻>F⁻>Na⁺>Mg²⁺.
For Na to Na⁺, removal of the outer 3s electron gives a smaller occupied-shell arrangement.
The ranking follows increasing attraction in the stated isoelectronic model. It is not based simply on the written charge sign or total mass. Different shells, configurations, and radius definitions matter for other comparisons; use reliable measured data to test the prediction rather than assuming one arrow answers every case.
Scientific references and source-model foundations
Parent / teacher teaching notes
Ask for a mechanism sentence before ranking. Compare electron counts explicitly and distinguish ionization energy from electronegativity. Ask the learner to explain each particle symbol, axis, unit and arrow before calculating. Distinguish hypothetical models and calculated curves from measured records. Public OpenSciEd excerpts here are selected foundation prompts, not complete high-school teacher editions or an endorsement. All required advanced explanations and practice are provided locally.
A periodic table with arrows showing that atomic radius increases down and to the left, while ionization energy and electronegativity increase up and to the right.
The key idea
Periodic tendencies reflect nuclear attraction, shielding, shell structure and electron interactions. Compare the defined property and species; broad radius, ionization-energy and electronegativity trends have local exceptions.
Effective Nuclear Charge (simple approximation)
Zeff ≈ (number of protons) − (number of core electrons)
core electrons are the inner-shell (non-valence) electrons that shield the valence electrons; a higher Zeff means the valence electrons are held more tightly, giving a smaller radius and a higher ionization energy.
Worked examples
Example 1
- Both sodium and chlorine are in Period 3, so compare them across the period.
- Across a period, effective nuclear charge rises and pulls the electron cloud inward, so atomic radius decreases from left to right.
- Sodium (Group 1) sits far to the left of chlorine (Group 17), so sodium's electrons are pulled in less tightly.
Example 2 · Worked application
- Both add electrons mainly to the same principal level.
- Nuclear charge increases across the period with incomplete additional shielding.
- Greater effective attraction generally contracts the electron distribution.
Trend statements require a specified property and comparable definition.
Example 3
- Magnesium and barium are both in Group 2, so compare them down the group.
- Down a group, atoms gain energy levels, so the outermost electron sits farther out and is better shielded — it is easier to remove.
- Magnesium is higher up in the group than barium, so its valence electron is held more tightly and takes more energy to remove.
Example 4 · Find and fix the mistake
- Test the claim against the stated conditions: Trend statements require a specified property and comparable definition.
- Across a period it generally decreases; down a group added principal levels tend to increase size.
Trend statements require a specified property and comparable definition.
Example 5 · Reason from the visual model
- Isoelectronic species have the same electron count under the compared state. O²⁻, F⁻ and Na⁺ each have ten electrons, but their proton counts rise from eight to eleven. Within this selected series, stronger nuclear attraction generally contracts the electron distribution, giving O²⁻ the larger and Na⁺ the smaller radius under compatible definitions. This is different from saying every positive ion of every element is smaller than every negative ion. Match the electron count and comparison conditions first.
- Na⁺ is smallest in the usual comparison; all three have ten electrons but Na⁺ has the largest proton count, 11.
Original equal-electron inventory. Bar lengths show electron counts only, not ionic radii.
Avoid these mistakes
- General trends have exceptions; do not use a trend arrow as an exact numerical table.
Check your understanding
Explain why K is usually larger than Na.
Discuss the answer
K has an occupied outer shell farther from the nucleus with more inner shielding, outweighing its greater proton count in this comparison.
Return to the phenomenon
Return to the initial case. Why does an ion’s electron count not completely determine its size? Revise your drawing or explanation using two named ideas and one stated limitation.
Compare explanations after your attempt
The shared count does not cancel the stronger nuclear attraction from eleven protons in Na⁺ compared with eight in O²⁻. Radius remains a defined comparison, not a rigid shell size.
What should we investigate next?
Which comparison would test a remaining uncertainty? State what you would change, keep comparable and measure.
Investigate, calculate and revise
Keep a first model and an evidence-supported revision. Attempt each task before opening guidance; all required explanations and supplied-data routes are available locally.
Activity 1 · Return to the opening case
Use the opening phenomenon, unit definitions and explained Parts 1–4.
Your task
Return to the initial case. Why does an ion’s electron count not completely determine its size? Revise your drawing or explanation using two named ideas and one stated limitation.
Success criteria
- Use the stated observations and appropriate units.
- Connect a labeled model with the chemical mechanism.
- State assumptions and an evidence limitation.
- Explain a substantive revision or next test.
Hint
Keep species identity, material transfer and energy account distinct.
Response guidance — discuss after your attempt
The shared count does not cancel the stronger nuclear attraction from eleven protons in Na⁺ compared with eight in O²⁻. Radius remains a defined comparison, not a rigid shell size.
Activity 2 · Transfer to a changed case
Cover the worked answer and use the explained models, relationships and notebook.
Your task
Rank Ne, F⁻ and Mg²⁺ by the usual radius trend for an isoelectronic series. Give electron/proton counts and the model limitation.
Success criteria
- Use the stated measurements or conditions, with correct units.
- Connect the result to the chemical mechanism or evidence relationship.
- Identify the assumption, model limit or further evidence requested.
Hint
Name known quantities and conditions, show intermediate steps and check conservation.
Response guidance — discuss after your attempt
All have ten electrons; proton counts are F=9, Ne=10, Mg=12. The usual order is F⁻ > Ne > Mg²⁺ under a compatible radius comparison. Defined atomic/ionic radii and environments must be matched before treating reference numbers as directly interchangeable.
Words to know
- atomic radius
- A measure of the size of an atom, roughly the distance from the nucleus to the outermost electrons.
- ionization energy
- The energy required to remove the most loosely held electron from a neutral atom.
- electronegativity
- A measure of how strongly an atom attracts the shared electrons in a chemical bond.
- effective nuclear charge (Zeff)
- The net positive pull actually felt by a valence electron, after inner electrons cancel out some of the nuclear charge.
- shielding (screening)
- The way inner-shell electrons block, or screen, valence electrons from feeling the full charge of the nucleus.
- periodic trend
- A predictable pattern in a property that repeats as you move across periods or down groups.
The trend that flips: ionic radius
Atomic radius has a twin that behaves in reverse. When an atom loses electrons to become a positive cation, it shrinks dramatically — often to less than half its former size — because the electrons that remain feel the nucleus's full pull. When an atom gains electrons to become a negative anion, it swells instead. Line up ions that have the same electron count (like O²⁻, F⁻, Na⁺, and Mg²⁺) and the one with the most protons is the smallest, its nucleus reeling the same cloud in tighter.
The trends aren't perfectly smooth
Ionization energy generally climbs across a period, but it hiccups in a couple of revealing spots. Pulling an electron from oxygen is actually a touch easier than from nitrogen, because nitrogen's half-filled 2p sublevel is extra stable while oxygen has one paired electron that repels its partner. These little dips are not flaws in the trend — they are evidence that the stability of half-filled and full sublevels (the same effect that bends chromium's configuration) is a genuine physical force.
Effective nuclear charge, made concrete
Why doesn't sodium's outer electron feel the full +11 of its nucleus? Because the ten inner core electrons stand between them and cancel out most of that pull through shielding. The lone valence electron effectively feels only about +1, which is exactly why it is so loosely held and so easily lost. Effective nuclear charge is just this idea — the net tug that survives after the core electrons take their cut — and it is the engine running underneath nearly every periodic trend.
Why sodium explodes and gold never rusts
These trends are really a map of reactivity. Metals at the lower left have low ionization energies, so they surrender electrons eagerly — drop cesium or sodium into water and it reacts violently. Metals with high ionization energies cling to their electrons instead, which is why gold and platinum can sit in jewelry for centuries without tarnishing. Reactivity is not a grab-bag of facts to memorize but a direct reading of an element's address on the table.
From trends to bonds: predicting how atoms join
The payoff of electronegativity is that the difference between two atoms predicts the kind of bond they will form. A large difference — a hungry nonmetal meeting a generous metal, like sodium and chlorine — means electrons are handed over outright in an ionic bond. A small difference means the electrons are shared in a covalent bond, and between two metals the electrons roam freely in a metallic bond. That single comparison, read straight off the periodic table, is the doorway into the entire next unit on chemical bonding.
In the real world
Battery designers chase metals with low ionization energy (they give up electrons easily), while electronegativity differences let chemists predict whether two elements will form an ionic or a covalent bond.
Exit check
Explain why K is usually larger than Na.
Check your explanation after answering
K has an occupied outer shell farther from the nucleus with more inner shielding, outweighing its greater proton count in this comparison.
Explain your reasoning without notes. If a key idea is missing, revisit the lesson and try again.
Problem 1
- increases
- decreases
- stays the same
- doubles each time
Answer and explanation
decreases
Rising effective nuclear charge across a period pulls the electron cloud inward, so atoms get smaller.
Problem 2
- chlorine (Cl)
- sodium (Na)
- fluorine (F)
- oxygen (O)
Answer and explanation
fluorine (F)
Fluorine, at the top right of the table (excluding noble gases), is the most electronegative element.
Problem 3
- stays the same
- becomes negative
- increases
- decreases
Answer and explanation
decreases
Down a group, the outer electron is farther out and better shielded, so it is easier to remove — ionization energy decreases.
Problem 4
Answer and explanation
7
Zeff ≈ 9 − 2 = 7. The 7 valence electrons feel a strong pull, which is why fluorine is so small and so electronegative.
Problem 5
Answer and explanation
Across a period, protons are added to the nucleus while the new electrons enter the same energy level, adding little shielding. Effective nuclear charge rises, so the stronger pull draws the whole electron cloud inward and the atom shrinks.
Problem 6
- high ionization energy
- low ionization energy
- zero ionization energy
- negative ionization energy
Answer and explanation
high ionization energy
A small radius means the outer electron is close to the nucleus and held tightly, so it takes a lot of energy to remove — a high ionization energy.
Problem 7
Hints
Trend statements require a specified property and comparable definition.
Answer and explanation
Na⁺ is smaller; losing the outer electron removes the occupied outer level and changes electron interactions.
Problem 8
Hints
State what the supplied observations or conditions establish, and separate that from any assumption.
Answer and explanation
Orbital structure, electron pairing and measurement definitions produce exceptions; consult data for precise comparisons.
Problem 9
Answer and explanation
Na⁺ is smallest in the usual comparison; all three have ten electrons but Na⁺ has the largest proton count, 11.
Isoelectronic species have the same electron count under the compared state. O²⁻, F⁻ and Na⁺ each have ten electrons, but their proton counts rise from eight to eleven. Within this selected series, stronger nuclear attraction generally contracts the electron distribution, giving O²⁻ the larger and Na⁺ the smaller radius under compatible definitions. This is different from saying every positive ion of every element is smaller than every negative ion. Match the electron count and comparison conditions first.
Na⁺ is smallest in the usual comparison; all three have ten electrons but Na⁺ has the largest proton count, 11.
Response criteria
- Interpret labels, structures, axes, units and directions correctly.
- Explain the chemistry relationship or mechanism.
- Respect stated assumptions and distinguish observation from inference.
Problem 10
Answer and explanation
All have ten electrons; proton counts are F=9, Ne=10, Mg=12. The usual order is F⁻ > Ne > Mg²⁺ under a compatible radius comparison. Defined atomic/ionic radii and environments must be matched before treating reference numbers as directly interchangeable.
All have ten electrons; proton counts are F=9, Ne=10, Mg=12. The usual order is F⁻ > Ne > Mg²⁺ under a compatible radius comparison. Defined atomic/ionic radii and environments must be matched before treating reference numbers as directly interchangeable.
Response criteria
- Use the stated measurements or conditions, with correct units.
- Connect the result to the chemical mechanism or evidence relationship.
- Identify the assumption, model limit or further evidence requested.