Bonding, Formulas & Molecular Structure — Chapter Practice, Grade 11
Build names, formulas, Lewis structures, and structure-property explanations.
Problem 1
- a halogen
- a metal
- a nonmetal
- a noble gas
Answer and explanation
a metal
Metals hold their few valence electrons loosely and lose them to become positive cations.
Problem 2
- a molecule
- a cation
- an anion
- a proton
Answer and explanation
an anion
Gaining an electron gives the atom a negative charge, making it an anion (Cl⁻).
Problem 3
Answer and explanation
3
Two Al³⁺ give +6, so you need three O²⁻ (−2 each) to reach −6 and balance the charge: Al₂O₃.
Problem 4
- Solid salt contains no charged particles
- Electrons flow easily through solid salt
- Melting adds extra electrons to the salt
- The ions are locked in place in the solid lattice but are free to move when molten
Answer and explanation
The ions are locked in place in the solid lattice but are free to move when molten
Conduction needs mobile charges; the lattice freezes the ions in place, but melting frees them to move and carry current.
Problem 5
Answer and explanation
Sodium has 1 valence electron and chlorine has 7. Sodium transfers its single electron to chlorine, so both reach a full outer shell. Sodium becomes Na⁺ and chlorine becomes Cl⁻, and the opposite charges attract to form the ionic bond.
Problem 6
Answer and explanation
5
Balancing +3 and −2 needs 2 cations (+6) and 3 anions (−6), so one formula unit has 2 + 3 = 5 ions.
Problem 7
Hints
Ionic formulas give ratios in a lattice, not necessarily individual molecules.
Answer and explanation
CaCl₂, because +2 balances two −1 charges.
Problem 8
Hints
State what the supplied observations or conditions establish, and separate that from any assumption.
Answer and explanation
Mobile ions carry charge in the melt; ions are constrained in the solid lattice under ordinary conditions.
Problem 9
Answer and explanation
Dissolved ions can move through the solution; lattice-bound ions in the ordinary solid are far less mobile.
A solid ionic crystal contains charged ions, but their positions are constrained by the lattice and they do not provide ordinary bulk ionic conduction. Melting or dissolving can make ions mobile, allowing them to carry current under suitable conditions. This does not mean every ionic compound dissolves readily or that solid conductivity is mathematically zero under all conditions. Identify phase, temperature, concentration and the relevant charge carrier before interpreting a conductivity comparison.
Dissolved ions can move through the solution; lattice-bound ions in the ordinary solid are far less mobile.
Response criteria
- Interpret labels, structures, axes, units and directions correctly.
- Explain the chemistry relationship or mechanism.
- Respect stated assumptions and distinguish observation from inference.
Problem 10
Answer and explanation
The least common charge magnitude is 6: two Al³⁺ and three O²⁻ give +6−6=0, so Al₂O₃. The formula states a stoichiometric ratio in an extended solid, not a claim of isolated five-ion molecules.
The least common charge magnitude is 6: two Al³⁺ and three O²⁻ give +6−6=0, so Al₂O₃. The formula states a stoichiometric ratio in an extended solid, not a claim of isolated five-ion molecules.
Response criteria
- Use the stated measurements or conditions, with correct units.
- Connect the result to the chemical mechanism or evidence relationship.
- Identify the assumption, model limit or further evidence requested.
Problem 11
- share electrons
- lose electrons
- gain protons
- transfer electrons
Answer and explanation
share electrons
Covalent bonding is the sharing of one or more pairs of electrons between atoms.
Problem 12
- two metals
- a metal and a nonmetal
- two nonmetals
- two noble gases
Answer and explanation
two nonmetals
Two nonmetals both attract electrons strongly, so they share rather than transfer, forming covalent bonds.
Problem 13
Answer and explanation
2
A single bond is one shared pair, and a pair is 2 electrons.
Problem 14
Answer and explanation
6
A triple bond is 3 shared pairs, and 3 pairs × 2 electrons = 6 electrons.
Problem 15
Answer and explanation
In a molecular compound the covalent bonds inside each molecule are strong, but the attractions between separate molecules are weak, so little energy is needed to pull the molecules apart. In an ionic compound every ion is locked to its neighbors by strong electrostatic forces throughout the lattice, so far more energy — a higher temperature — is needed to break it apart.
Problem 16
- 1
- 2
- 3
- 0
Answer and explanation
2
Each oxygen shares 2 pairs in its double bond and keeps 2 lone pairs of its own, completing its octet.
Problem 17
Hints
A shared pair is not ownership transferred permanently to only one atom.
Answer and explanation
Six electrons in three shared pairs in the simple bond model.
Problem 18
Hints
State what the supplied observations or conditions establish, and separate that from any assumption.
Answer and explanation
Partial charge separation can create a net molecular dipole without net charge.
Problem 19
Answer and explanation
No. Bond order supports a qualitative comparison for suitable species, but measured energy depends on the full bonding environment and defined process.
Bond order summarizes bonding in a model: a Lewis single, double or triple line commonly represents one, two or three shared pairs. For comparable atom pairs, higher bond order often corresponds to shorter, stronger bonds, but bond energies are not exact integer multiples and depend on the surrounding molecule. Bond dissociation energy concerns a specified bond-breaking process. Delocalized structures can have intermediate effective orders, so a selected Lewis drawing should not be treated as a direct ruler or calorimeter.
No. Bond order supports a qualitative comparison for suitable species, but measured energy depends on the full bonding environment and defined process.
Response criteria
- Interpret labels, structures, axes, units and directions correctly.
- Explain the chemistry relationship or mechanism.
- Respect stated assumptions and distinguish observation from inference.
Problem 20
Answer and explanation
CO₂ is linear with equal opposing bond contributions that cancel in the ideal symmetric molecule. H₂O is bent, so its bond dipoles do not cancel. Geometry and the full charge distribution matter.
CO₂ is linear with equal opposing bond contributions that cancel in the ideal symmetric molecule. H₂O is bent, so its bond dipoles do not cancel. Geometry and the full charge distribution matter.
Response criteria
- Use the stated measurements or conditions, with correct units.
- Connect the result to the chemical mechanism or evidence relationship.
- Identify the assumption, model limit or further evidence requested.
Problem 21
- separate molecules sharing electron pairs
- neutral atoms locked rigidly in place
- positive ions surrounded by mobile, delocalized electrons
- negative ions in a fixed lattice
Answer and explanation
positive ions surrounded by mobile, delocalized electrons
Metals form positive ions that sit in a shared sea of freely moving delocalized electrons.
Problem 22
- low density
- transparency
- brittleness
- electrical conductivity
Answer and explanation
electrical conductivity
Free-moving electrons can drift under a voltage, carrying an electric current, so metals conduct electricity.
Problem 23
- Their ions can slide past one another while the electron sea keeps holding them together
- Their bonds are rigid and point in fixed directions
- They contain no electrons to get in the way
- They are made of separate small molecules
Answer and explanation
Their ions can slide past one another while the electron sea keeps holding them together
When struck, layers of metal ions shift, but the mobile electron sea flows with them and keeps the metal bonded, so it bends instead of breaking.
Problem 24
Answer and explanation
In ionic bonding, electrons are fully transferred from a metal to a nonmetal, creating positive and negative ions locked in a rigid lattice. In metallic bonding, the metal atoms' valence electrons are not transferred to any single atom but are shared among all of them in a mobile 'sea,' so the electrons stay free to move and the bond reaches in every direction.
Problem 25
- its rigid ionic lattice
- the free electrons absorbing and re-emitting light
- the metal's very high density
- electrons that are tightly bound to each atom
Answer and explanation
the free electrons absorbing and re-emitting light
The delocalized electrons readily absorb light and re-emit it, reflecting it back to give a shiny surface.
Problem 26
- Salt is much softer than copper
- Copper is actually a gas at room temperature
- Copper's electron sea lets layers of ions shift while staying bonded, but shifting an ionic lattice aligns like charges that repel and split it
- Copper contains no chemical bonds at all
Answer and explanation
Copper's electron sea lets layers of ions shift while staying bonded, but shifting an ionic lattice aligns like charges that repel and split it
The mobile electron sea holds shifting metal ions together, while in an ionic solid a shifted layer brings like charges together, and they repel and cleave the crystal.
Problem 27
Hints
A model explains trends, but real alloys and structures affect behavior.
Answer and explanation
It has mobile delocalized electrons; ordinary ionic solids lack comparably mobile ions.
Problem 28
Hints
State what the supplied observations or conditions establish, and separate that from any assumption.
Answer and explanation
No. Composition, crystal structure, defects and processing affect mechanical properties.
Problem 29
Answer and explanation
The substitutional species replaces a host-site occupant; the interstitial species occupies a space between host sites in the simplified arrangement.
An alloy combines a metallic element with one or more other elements. In a substitutional model, some host sites are occupied by another species; in an interstitial model, smaller atoms occupy spaces between selected host sites. Both can influence dislocation motion and properties. Real alloys may include several phases and complex microstructures, so a uniform dot pattern is not a universal atom-by-atom picture. State composition, treatment and measured property before recommending an alloy for a design.
The substitutional species replaces a host-site occupant; the interstitial species occupies a space between host sites in the simplified arrangement.
Response criteria
- Interpret labels, structures, axes, units and directions correctly.
- Explain the chemistry relationship or mechanism.
- Respect stated assumptions and distinguish observation from inference.
Problem 30
Answer and explanation
P satisfies both stated constraints. Q fails conduction and R fails strength. Cost, corrosion, fatigue, fabrication or service temperature could still change the decision.
P satisfies both stated constraints. Q fails conduction and R fails strength. Cost, corrosion, fatigue, fabrication or service temperature could still change the decision.
Response criteria
- Use the stated measurements or conditions, with correct units.
- Connect the result to the chemical mechanism or evidence relationship.
- Identify the assumption, model limit or further evidence requested.
Problem 31
- always stay at fixed 90° angles
- have no effect on the shape
- attract each other
- repel and spread as far apart as possible
Answer and explanation
repel and spread as far apart as possible
Electron groups are all negative, so they repel and spread out as far as possible, which sets the shape.
Problem 32
- linear
- tetrahedral
- trigonal pyramidal
- bent
Answer and explanation
linear
Two electron groups push to opposite sides, giving a linear shape with a 180° bond angle.
Problem 33
Answer and explanation
109.5 °
Four electron groups spread to the corners of a tetrahedron, giving bond angles of about 109.5°.
Problem 34
- Water is bent, so its bond dipoles don't cancel, while CO₂ is linear and symmetric, so its dipoles cancel
- Water has no polar bonds
- Carbon dioxide has no definite shape
- Water is actually an ionic compound
Answer and explanation
Water is bent, so its bond dipoles don't cancel, while CO₂ is linear and symmetric, so its dipoles cancel
Molecular polarity depends on both bond polarity and shape; water's bent shape leaves a net dipole, while CO₂'s symmetric linear shape cancels its dipoles.
Problem 35
Answer and explanation
A hydrogen bond is a strong attraction between a hydrogen atom bonded to N, O, or F in one molecule and a lone pair on the N, O, or F of a neighboring molecule. Water molecules form many hydrogen bonds with one another, so it takes a lot of extra energy — a higher temperature — to pull them apart into a gas, giving water an unusually high boiling point.
Problem 36
- tetrahedral
- trigonal pyramidal
- linear
- trigonal planar
Answer and explanation
trigonal pyramidal
The four electron groups arrange tetrahedrally, but with only three atoms attached the visible shape is trigonal pyramidal; the lone pair pushes the N–H bonds down to about 107°.
Problem 37
Hints
Compare CO₂ with bent H₂O, where dipoles do not cancel.
Answer and explanation
Its bond dipoles have components that add rather than completely cancel.
Problem 38
Hints
State what the supplied observations or conditions establish, and separate that from any assumption.
Answer and explanation
The symmetric distribution gives no permanent net dipole.
Problem 39
Answer and explanation
In the symmetric linear molecule, equal opposing contributions cancel. Geometry is needed along with bond polarity.
A dipole moment has direction as well as magnitude. Symmetry can make equal bond contributions cancel, as in an isolated ideal linear CO₂ molecule. In bent H₂O, the corresponding contributions do not cancel, producing a net molecular dipole. A bond can therefore be polar while its entire molecule has no permanent net dipole. The selected arrows point toward the negative ends as a classroom convention; a quantitative dipole calculation needs the actual charge distribution rather than these unscaled arrows alone.
In the symmetric linear molecule, equal opposing contributions cancel. Geometry is needed along with bond polarity.
Response criteria
- Interpret labels, structures, axes, units and directions correctly.
- Explain the chemistry relationship or mechanism.
- Respect stated assumptions and distinguish observation from inference.
Problem 40
Answer and explanation
The electron-domain arrangement is approximately tetrahedral and the molecular shape is bent. Lone-pair interactions and the actual chemical species alter angles; 109.5° is an ideal tetrahedral reference rather than an exact universal bond angle.
The electron-domain arrangement is approximately tetrahedral and the molecular shape is bent. Lone-pair interactions and the actual chemical species alter angles; 109.5° is an ideal tetrahedral reference rather than an exact universal bond angle.
Response criteria
- Use the stated measurements or conditions, with correct units.
- Connect the result to the chemical mechanism or evidence relationship.
- Identify the assumption, model limit or further evidence requested.
Problem 41
Answer and explanation
Mg(NO₃)₂: one Mg²⁺ balances two NO₃⁻.
Response criteria
- State a scientifically accurate conclusion.
- Show the calculation or mechanism that supports it.
- Include units, conditions, or limits where relevant.
Problem 42
Hints
Write the relationship first; substitute with consistent units.
Answer and explanation
24 atoms
2 ×3 ×4 = 24.
Problem 43
Hints
List the given quantities, select a relationship, and check units before substituting.
Answer and explanation
24 atoms
4×2×3=24.
Problem 44
Answer and explanation
Ca²⁺ and CO₃²⁻ balance in the smallest 1:1 ratio.
Response criteria
- State a scientifically accurate conclusion.
- Show the calculation or mechanism that supports it.
- Include units, conditions, or limits where relevant.
Problem 45
Hints
The Roman numeral gives oxidation state, not number of iron atoms.
Answer and explanation
Ca(NO₃)₂; two nitrate ions balance calcium's +2 charge.
Problem 46
Hints
State what the supplied observations or conditions establish, and separate that from any assumption.
Answer and explanation
Copper(II) chloride, since two chlorides require Cu²⁺.
Problem 47
Answer and explanation
Six oxygen atoms occur in two nitrate groups, along with two nitrogen atoms. CaNO₆ would lose a nitrogen and fail to represent the stated ions.
A polyatomic ion is a charged group of covalently connected atoms, such as nitrate NO₃⁻ or sulfate SO₄²⁻. Its internal formula is retained when charge balance determines how many groups are needed. Calcium nitrate therefore needs two nitrate ions, written Ca(NO₃)₂, giving one Ca, two N and six O atoms. Parentheses group the ion; they do not change its internal subscript to force neutrality. Learn common ion names and charges as linked information, and distinguish similarly named but chemically different ions.
Six oxygen atoms occur in two nitrate groups, along with two nitrogen atoms. CaNO₆ would lose a nitrogen and fail to represent the stated ions.
Response criteria
- Interpret labels, structures, axes, units and directions correctly.
- Explain the chemistry relationship or mechanism.
- Respect stated assumptions and distinguish observation from inference.
Problem 48
Answer and explanation
Fe³⁺ and SO₄²⁻ require Fe₂(SO₄)₃: two Fe, three S and twelve O atoms. N₂O₃ is dinitrogen trioxide. The Roman numeral and prefixes serve different bookkeeping roles.
Fe³⁺ and SO₄²⁻ require Fe₂(SO₄)₃: two Fe, three S and twelve O atoms. N₂O₃ is dinitrogen trioxide. The Roman numeral and prefixes serve different bookkeeping roles.
Response criteria
- Use the stated measurements or conditions, with correct units.
- Connect the result to the chemical mechanism or evidence relationship.
- Identify the assumption, model limit or further evidence requested.
Problem 49
Hints
Write the relationship first; substitute with consistent units.
Answer and explanation
8 electrons
5+4−1 = 8.
Problem 50
Answer and explanation
Its electron density points in one bond direction, despite containing two shared pairs.
Response criteria
- State a scientifically accurate conclusion.
- Show the calculation or mechanism that supports it.
- Include units, conditions, or limits where relevant.
Problem 51
Hints
List the given quantities, select a relationship, and check units before substituting.
Answer and explanation
32 electrons
6+4×6+2=32.
Problem 52
Answer and explanation
No. Resonance drawings represent one delocalized bonding structure with equivalent bonds in the idealized ion.
Response criteria
- State a scientifically accurate conclusion.
- Show the calculation or mechanism that supports it.
- Include units, conditions, or limits where relevant.
Problem 53
Hints
Formal electron counting is a model; resonance is not rapid physical switching.
Answer and explanation
5 from N plus 3 from H=8; three bonds and one lone pair on N in the simple model.
Problem 54
Hints
State what the supplied observations or conditions establish, and separate that from any assumption.
Answer and explanation
They help evaluate plausible electron arrangements, with known exceptions and charge constraints.
Problem 55
Answer and explanation
The electron inventory represents a species with one fewer electron than the neutral-atom sum; the assignments must reproduce that total charge.
Formal charge assigns bonding electrons equally between bonded atoms: valence count minus nonbonding electrons minus half the bonding electrons. In NH₄⁺, nitrogen has four single bonds and no lone pair, giving formal charge +1; each hydrogen has zero. The sum must equal the species’ net charge. Formal charge helps compare Lewis candidates but is not a direct measurement of actual partial charge, and it is distinct from oxidation-number bookkeeping, which assigns bonding electrons differently.
The electron inventory represents a species with one fewer electron than the neutral-atom sum; the assignments must reproduce that total charge.
Response criteria
- Interpret labels, structures, axes, units and directions correctly.
- Explain the chemistry relationship or mechanism.
- Respect stated assumptions and distinguish observation from inference.
Problem 56
Answer and explanation
Total valence electrons are 5+4(1)−1=8. Nitrogen formal charge is 5−0−4=+1 and each H is zero. The flat Lewis connectivity does not specify measured angles; the common molecular arrangement is tetrahedral.
Total valence electrons are 5+4(1)−1=8. Nitrogen formal charge is 5−0−4=+1 and each H is zero. The flat Lewis connectivity does not specify measured angles; the common molecular arrangement is tetrahedral.
Response criteria
- Use the stated measurements or conditions, with correct units.
- Connect the result to the chemical mechanism or evidence relationship.
- Identify the assumption, model limit or further evidence requested.