Bonding, Formulas & Molecular Structure — Print · Physical Science: Chemistry, Grade 11
Build names, formulas, Lewis structures, and structure-property explanations.
Printable chapter lessons and review.
Ionic Bonding
Learning goals
- I can explain how atoms transfer electrons to form cations and anions, and predict a monatomic ion's charge from its group.
- I can write formulas and names for simple ionic compounds by balancing positive and negative charges.
Readings for this unit
Before this unit
Ions and charge neutrality.
Use the detailed parent plan: two core 50–60-minute sessions per focused unit, with a third assigned for selected calculation/modeling topics. First study the core explanation and Parts 1–2 with their figures/checks; next study Parts 3–4, the whole-unit application, worked cases, varied practice and exit check. Attempt reasoning before opening guidance. Extend time when actual understanding requires it; investigations and chapter assessments have separate sessions.
Start with something to explain
Why does a crystal containing charged ions conduct poorly until its ions can move?
Illustrative evidence case. A selected salt is poorly conducting as an ordinary solid but conducts when dissolved.
Notice and wonder
Record two observations using the stated quantities or relationships. Keep observations separate from possible causes. Write one question that a new measurement could help answer.
Why does a crystal containing charged ions conduct poorly until its ions can move?
Your first model
Label the charge carriers and whether they can travel through the sample.
Build the language from the idea
- ionic bond
- Electrostatic attraction among oppositely charged ions in the specified arrangement; ion formation by electron transfer is a distinct part of the account.
- ion
- An atom (or group of atoms) that carries an electric charge because it has lost or gained electrons.
- cation
- A positively charged ion, formed when an atom loses one or more electrons (typically a metal).
- anion
- A negatively charged ion, formed when an atom gains one or more electrons (typically a nonmetal).
- octet rule
- The tendency of atoms to gain, lose, or share electrons until their outermost shell holds a stable set of eight valence electrons.
- crystal lattice
- The orderly, repeating three-dimensional arrangement of ions in an ionic solid.
- formula unit
- The simplest whole-number ratio of ions in an ionic compound (for example, NaCl).
- polyatomic ion
- A charged group of covalently bonded atoms that acts as a single unit, such as nitrate (NO₃⁻) or sulfate (SO₄²⁻).
A chemical bond describes interactions that hold atoms or ions in a stable arrangement under suitable conditions. Bond formation can lower potential energy relative to separated particles, but whether an overall process occurs also depends on entropy, temperature, and the complete chemical system. The octet rule is a useful main-group pattern with exceptions, not a goal that atoms try to achieve. In ionic compounds, ionic bonding is electrostatic attraction throughout a lattice; electron transfer helps account for ion formation but is not itself the lattice bond.
Many common metals form cations and many common nonmetals form anions. Removing an electron from an isolated atom requires energy; it is not automatically cheap or favorable merely because the atom is a metal. Electron attachment, lattice formation, and other changes contribute to the full energy account. Losing electrons leaves a positive ion because protons outnumber electrons; gaining electrons gives a negative ion. Charge balance and measured properties help identify the resulting compound.
In a simple electron-count account for sodium chloride, a neutral sodium atom becomes Na⁺ by losing one electron and a neutral chlorine atom becomes Cl⁻ by gaining one. Na⁺ has 11 protons and 10 electrons; Cl⁻ has 17 protons and 18 electrons. Their noble-gas-like configurations are useful main-group patterns. In solid NaCl, opposite charges attract in an extended lattice. This ionic model describes charge and structure without requiring isolated atom pairs or claiming that real electron density has perfectly sharp boundaries.
It would be a mistake to picture salt as tidy little Na⁺–Cl⁻ pairs floating around. Because the attraction of a charge reaches out in every direction, each Na⁺ pulls on every nearby Cl⁻ and vice versa, and the ions stack into a vast, orderly, three-dimensional crystal lattice — in salt, each sodium is surrounded by six chlorines and each chlorine by six sodiums. A single grain of salt holds billions upon billions of ions locked in this repeating grid. That's why chemists don't call 'NaCl' a molecule; it's a formula unit, the simplest whole-number ratio of ions in the lattice.
Many ionic solids have relatively high melting temperatures because separating ions from an ordered lattice requires energy. They are often brittle: shifting layers can bring like charges closer and promote fracture. Their ions are not free to carry sustained current through an ordinary solid lattice, while a molten ionic compound or a solution containing mobile ions can conduct. Not every ionic compound dissolves readily in water, and conductivity depends on how many mobile charged particles are present.
An ionic formula balances total cation and anion charge in the simplest whole-number ratio. Mg²⁺ requires two Cl⁻ ions, giving MgCl₂. Al³⁺ and O²⁻ require a 2:3 ratio, giving Al₂O₃. A criss-cross shortcut must be followed by reduction to the simplest ratio; Mg²⁺ and O²⁻ give MgO, not Mg₂O₂. Preserve a polyatomic ion as a group and use parentheses when needed, as in Ca(NO₃)₂. Variable-charge metals require an appropriate Roman numeral in the name.
Model check: Ionic solids are extended lattices, not isolated little NaCl molecules. Ca²⁺ needs two Cl⁻ ions for neutrality; a 1:1 formula would carry +1 net charge.
Build your understanding
Use the detailed parent plan: two core 50–60-minute sessions per focused unit, with a third assigned for selected calculation/modeling topics. First study the core explanation and Parts 1–2 with their figures/checks; next study Parts 3–4, the whole-unit application, worked cases, varied practice and exit check. Attempt reasoning before opening guidance. Extend time when actual understanding requires it; investigations and chapter assessments have separate sessions.
Part 1 · Explain ion formation and lattice attraction
An ion has a net electric charge because its electron and proton counts differ. Magnesium can lose two electrons and chlorine can gain one per atom in a selected ionic-compound account. Ionic bonding is the electrostatic attraction among oppositely charged ions, not electron transfer itself. Creating separated ions has its own energy costs and releases; formation of a crystal or solution changes the total balance. The arrows here track electrons, not proof that each isolated step occurs spontaneously.
Read the visual model
Identify the labeled structures and units, then trace the arrows or compare values under the caption’s stated conditions. Separate the displayed evidence from a further inference. Write your reasoning before opening the guidance.
Why are two chloride ions needed for one magnesium ion in MgCl₂?
Visual reasoning — after your attempt
Each chloride ion has charge −1, so two balance the +2 charge of Mg²⁺. Total charge is zero.
Electron transfer is a useful model for producing oppositely charged ions. Ionic bonding describes the electrostatic attraction within the resulting structure, not just the transfer event. A bulk ionic solid is an extended lattice, so a formula such as NaCl describes the simplest ion ratio rather than isolated molecules.
Sodium can form Na⁺ and chlorine Cl⁻. Each ion interacts with surrounding ions throughout a lattice; drawing only one pair leaves out that extended structure.
Pause and explain
Is NaCl normally a collection of isolated NaCl molecules?
Check your reasoning after answering
No. Bulk solid sodium chloride is an extended ionic lattice; NaCl states its simplest ion ratio.
Part 2 · Construct a neutral formula
An ionic lattice is an extended arrangement stabilized by electrostatic interactions throughout the crystal. A formula such as NaCl gives the simplest neutral ratio of sodium to chloride ions; it does not imply isolated two-atom molecules in the solid. A two-dimensional alternating sketch highlights attraction and repulsion but omits the actual three-dimensional coordination. Distinguish a formula unit, a stoichiometric counting unit, from a discrete molecule before calculating particle numbers or drawing a dissolved sample.
Read the visual model
Identify the labeled structures and units, then trace the arrows or compare values under the caption’s stated conditions. Separate the displayed evidence from a further inference. Write your reasoning before opening the guidance.
Does each positive ion in the lattice belong to only one negative-ion partner?
Visual reasoning — after your attempt
No. The extended structure involves interactions with many neighboring ions; NaCl describes the overall 1:1 ratio.
Combine positive and negative charges so total charge is zero, then express the simplest whole-number ratio. A subscript counts ions or atoms in the formula unit and is not the charge itself. Keep polyatomic ions intact when their identity is supplied.
Mg²⁺ and Cl⁻ require one magnesium for two chloride ions: MgCl₂. Two chlorides contribute −2, balancing +2.
Pause and explain
Why is MgCl not neutral for the supplied ions?
Check your reasoning after answering
One Mg²⁺ and one Cl⁻ total +1. Two chloride ions are required to balance one magnesium ion.
Part 3 · Connect structure to observable properties
A solid ionic crystal contains charged ions, but their positions are constrained by the lattice and they do not provide ordinary bulk ionic conduction. Melting or dissolving can make ions mobile, allowing them to carry current under suitable conditions. This does not mean every ionic compound dissolves readily or that solid conductivity is mathematically zero under all conditions. Identify phase, temperature, concentration and the relevant charge carrier before interpreting a conductivity comparison.
Read the visual model
Identify the labeled structures and units, then trace the arrows or compare values under the caption’s stated conditions. Separate the displayed evidence from a further inference. Write your reasoning before opening the guidance.
Why can a salt solution conduct even though an intact salt crystal usually conducts poorly?
Visual reasoning — after your attempt
Dissolved ions can move through the solution; lattice-bound ions in the ordinary solid are far less mobile.
Strong lattice interactions often give high melting temperatures. Brittle failure can occur when displaced layers bring like charges into unfavorable alignment. Electrical conduction requires mobile charge carriers: ions are fixed in the ideal solid lattice but can move in a melt or a suitable aqueous solution.
A solid salt can be a poor conductor while its solution conducts. This difference is consistent with ion mobility, not proof that the ions became electrons.
Pause and explain
Why can dissolved salt conduct while the solid does not conduct well?
Check your reasoning after answering
Dissolved ions can move and carry charge. In the solid lattice, ions are not freely mobile under ordinary conditions.
Part 4 · Keep energy and exceptions in the account
Bringing oppositely charged gaseous ions into a lattice releases energy in the chosen system account. A lattice enthalpy definition may refer to formation or separation, with opposite signs; state the convention. Formation from elements additionally involves changes such as atomization, electron removal and electron addition. Favorable lattice stabilization does not mean ionizing an isolated metal costs no energy. Compare the complete cycle and conditions before predicting a compound’s formation or solubility.
Read the visual model
Identify the labeled structures and units, then trace the arrows or compare values under the caption’s stated conditions. Separate the displayed evidence from a further inference. Write your reasoning before opening the guidance.
Why does a downward lattice-formation arrow not prove that every earlier ion-formation step releases energy?
Visual reasoning — after your attempt
The arrow represents one selected step. Other steps can require energy, and the overall balance must include all of them.
Forming isolated ions costs or releases energy in separate steps; lattice formation releases energy. Overall stability depends on the complete energy account, not a universal desire for an octet. Not every ionic compound dissolves readily, and conductivity also depends on ion quantity and mobility.
A charge-balanced formula does not guarantee high solubility. Use a supplied solubility rule or measured result rather than assuming all salts fully dissolve.
Pause and explain
Does correct charge balance prove a salt is water-soluble?
Check your reasoning after answering
No. Solubility depends on interactions in the solid and solution and must be checked using suitable data or rules.
Apply the whole unit · Explain an ionic formula and conductivity
Illustrative ion set: Al³⁺ and O²⁻. A separate supplied soluble salt conducts strongly in solution but poorly as a dry solid.
Your task
Construct the simplest neutral aluminum/oxide ratio, sketch an extended-lattice fragment, and explain the conductivity contrast using mobile charges. State what the formula alone cannot establish.
What your response should show
- Choose the appropriate chemical model or relationship and state its conditions.
- Show substitutions, units, particle or charge counts, and intermediate reasoning as relevant.
- Use supplied evidence to justify the conclusion; distinguish observation from inference.
- Identify a meaningful limitation, uncertainty, or next measurement.
Response guidance — after your attempt
Least common charge magnitude is 6.
Two Al³⁺ supply +6 and three O²⁻ supply −6.
Write Al₂O₃ and verify neutrality.
Use fixed lattice ions versus mobile dissolved ions to interpret the separate conductivity record.
Al₂O₃ expresses a neutral 2: 3 formula-unit ratio, not an isolated molecule model for its bulk solid. The conductivity record concerns a separately supplied soluble salt and should not be assumed to describe aluminum oxide. Formula neutrality alone does not determine solubility, melting temperature, or exact conductivity.
Scientific references and source-model foundations
Parent / teacher teaching notes
Require a signed-charge sum and distinguish transfer, attraction, and mobility. Avoid conflating a formula prediction with a measured property. Ask the learner to explain each particle symbol, axis, unit and arrow before calculating. Distinguish hypothetical models and calculated curves from measured records. Public OpenSciEd excerpts here are selected foundation prompts, not complete high-school teacher editions or an endorsement. All required advanced explanations and practice are provided locally.
The key idea
Ionic bonding is electrostatic attraction in an ionic arrangement. Ion formation, lattice stabilization, formula neutrality and ion mobility explain different parts of a compound’s chemistry; electron transfer alone is not the bond or the full energy balance.
Charge Balance in an Ionic Formula
(number of cations) × (cation charge) = (number of anions) × (anion charge)
an ionic compound must be electrically neutral, so the total positive charge equals the total negative charge. Example: for Al³⁺ and O²⁻, 2 × 3 = 3 × 2, giving Al₂O₃. Always reduce the subscripts to the simplest whole-number ratio.
Worked examples
Example 1
- Find each ion's charge from its group. Magnesium is in Group 2, so it loses 2 electrons to form Mg²⁺. Chlorine is in Group 17, so it gains 1 electron to form Cl⁻.
- Balance the charges so the compound is neutral: one Mg²⁺ (+2) needs two Cl⁻ (−1 each) to cancel it.
- Write the formula with those subscripts: one Mg and two Cl.
Example 2 · Worked application
- Find a common total charge magnitude: 6.
- Two Al³⁺ ions give +6; three O²⁻ ions give −6.
- Write the lowest whole-number formula-unit ratio.
Ionic formulas give ratios in a lattice, not necessarily individual molecules.
Example 3
- Total positive charge must equal total negative charge. The charges are +3 and −2, whose least common multiple is 6.
- To reach +6 you need two Al³⁺ (2 × 3 = 6); to reach −6 you need three O²⁻ (3 × 2 = 6).
- Criss-crossing the charges gives the subscripts: Al₂O₃.
Example 4 · Find and fix the mistake
- Test the claim against the stated conditions: Ionic formulas give ratios in a lattice, not necessarily individual molecules.
- A one-to-one pair has net +1; charge balance requires a 2:3 ratio.
Ionic formulas give ratios in a lattice, not necessarily individual molecules.
Example 5 · Reason from the visual model
- A solid ionic crystal contains charged ions, but their positions are constrained by the lattice and they do not provide ordinary bulk ionic conduction. Melting or dissolving can make ions mobile, allowing them to carry current under suitable conditions. This does not mean every ionic compound dissolves readily or that solid conductivity is mathematically zero under all conditions. Identify phase, temperature, concentration and the relevant charge carrier before interpreting a conductivity comparison.
- Dissolved ions can move through the solution; lattice-bound ions in the ordinary solid are far less mobile.
Original qualitative mobility comparison; arrows indicate possible ion motion, not a specific voltage polarity or measured conductivity.
Avoid these mistakes
- Ionic solids are extended lattices, not isolated little NaCl molecules.
Check your understanding
Why does Ca form CaCl₂ rather than CaCl?
Discuss the answer
Ca²⁺ needs two Cl⁻ ions for neutrality; a 1:1 formula would carry +1 net charge.
Return to the phenomenon
Return to the initial case. Why does a crystal containing charged ions conduct poorly until its ions can move? Revise your drawing or explanation using two named ideas and one stated limitation.
Compare explanations after your attempt
Charge alone is insufficient: sustained current needs mobile carriers. Dissolution changes ion mobility and interactions without changing their element identities.
What should we investigate next?
Which comparison would test a remaining uncertainty? State what you would change, keep comparable and measure.
Investigate, calculate and revise
Keep a first model and an evidence-supported revision. Attempt each task before opening guidance; all required explanations and supplied-data routes are available locally.
Activity 1 · Return to the opening case
Use the opening phenomenon, unit definitions and explained Parts 1–4.
Your task
Return to the initial case. Why does a crystal containing charged ions conduct poorly until its ions can move? Revise your drawing or explanation using two named ideas and one stated limitation.
Success criteria
- Use the stated observations and appropriate units.
- Connect a labeled model with the chemical mechanism.
- State assumptions and an evidence limitation.
- Explain a substantive revision or next test.
Hint
Keep species identity, material transfer and energy account distinct.
Response guidance — discuss after your attempt
Charge alone is insufficient: sustained current needs mobile carriers. Dissolution changes ion mobility and interactions without changing their element identities.
Activity 2 · Transfer to a changed case
Cover the worked answer and use the explained models, relationships and notebook.
Your task
Al³⁺ combines with O²⁻. Find the simplest neutral formula and explain why it is not a five-ion molecule drawing for the solid.
Success criteria
- Use the stated measurements or conditions, with correct units.
- Connect the result to the chemical mechanism or evidence relationship.
- Identify the assumption, model limit or further evidence requested.
Hint
Name known quantities and conditions, show intermediate steps and check conservation.
Response guidance — discuss after your attempt
The least common charge magnitude is 6: two Al³⁺ and three O²⁻ give +6−6=0, so Al₂O₃. The formula states a stoichiometric ratio in an extended solid, not a claim of isolated five-ion molecules.
Words to know
- ionic bond
- Electrostatic attraction among oppositely charged ions in the specified arrangement; ion formation by electron transfer is a distinct part of the account.
- ion
- An atom (or group of atoms) that carries an electric charge because it has lost or gained electrons.
- cation
- A positively charged ion, formed when an atom loses one or more electrons (typically a metal).
- anion
- A negatively charged ion, formed when an atom gains one or more electrons (typically a nonmetal).
- octet rule
- The tendency of atoms to gain, lose, or share electrons until their outermost shell holds a stable set of eight valence electrons.
- crystal lattice
- The orderly, repeating three-dimensional arrangement of ions in an ionic solid.
- formula unit
- The simplest whole-number ratio of ions in an ionic compound (for example, NaCl).
- polyatomic ion
- A charged group of covalently bonded atoms that acts as a single unit, such as nitrate (NO₃⁻) or sulfate (SO₄²⁻).
How electricity revealed the ions hiding inside salt
For centuries no one knew that tame table salt hid a violent metal and a poison gas. In 1807 the chemist Humphry Davy passed electricity through molten compounds and tore them apart, isolating pure sodium and potassium for the first time — soft, silvery metals so reactive they can burst into flame on water. The experiment worked precisely because melting frees the ions to move toward the electrodes, the very same reason molten salt conducts electricity while the solid does not.
Why a 'molecule of salt' doesn't exist
It's tempting to talk about 'a molecule of NaCl,' but there's no such thing. In a salt crystal every Na⁺ is surrounded by six Cl⁻ and every Cl⁻ by six Na⁺, an endless three-dimensional grid with no way to point to one sodium and say that chlorine belongs to it. That's why chemists use the term formula unit instead of molecule: NaCl only tells you the 1-to-1 ratio of ions, not a count of atoms locked into a separate particle.
What makes one salt melt hotter than another
Table salt melts at about 801°C, but magnesium oxide (MgO) doesn't melt until a staggering 2852°C — hot enough to line furnaces. The difference is charge. In NaCl the ions carry ±1, but in MgO they carry ±2, and the force between charges climbs steeply as the charges grow and the ions pack closer together. A stronger electrostatic attraction means a stronger lattice, which means a far higher melting point — the melting point is a direct readout of how tightly the ions are gripped.
How water pulls a crystal apart
Drop salt into water and the rigid lattice dissolves away at room temperature — how? Water molecules are polar (a fact you'll meet in the geometry lesson), with a slightly negative oxygen end and slightly positive hydrogen ends. The negative ends swarm each Na⁺ and the positive ends surround each Cl⁻, tugging the ions out of the lattice and wrapping them in a hydration shell. Once free and drifting, those ions can carry a current — which is exactly why saltwater conducts electricity and pure water barely does.
The criss-cross trap: don't forget to reduce
The criss-cross shortcut — drop each ion's charge as the other ion's subscript — is handy but has one famous trap. Cross Mg²⁺ with O²⁻ and you'd write 'Mg₂O₂,' yet the real formula is MgO. Because a formula unit is the simplest whole-number ratio, you must always reduce the subscripts to their lowest terms. Criss-cross gives you a correct ratio, but only after you divide out any common factor does it give the correct formula.
In the real world
Ionic compounds are everywhere: table salt (NaCl) seasons and preserves food, and the calcium phosphate that stiffens your bones is an ionic mineral. The dissolved ions called electrolytes — sodium, potassium, and calcium — carry the electrical signals that fire your nerves and beat your heart.
Exit check
Why does Ca form CaCl₂ rather than CaCl?
Check your explanation after answering
Ca²⁺ needs two Cl⁻ ions for neutrality; a 1:1 formula would carry +1 net charge.
Explain your reasoning without notes. If a key idea is missing, revisit the lesson and try again.
Covalent Bonding
Learning goals
- I can explain how nonmetal atoms share electron pairs to form single, double, and triple covalent bonds and complete their octets.
- I can draw simple Lewis structures and identify bonding pairs and lone pairs.
Readings for this unit
Before this unit
Valence electrons and shared pairs.
Use the detailed parent plan: two core 50–60-minute sessions per focused unit, with a third assigned for selected calculation/modeling topics. First study the core explanation and Parts 1–2 with their figures/checks; next study Parts 3–4, the whole-unit application, worked cases, varied practice and exit check. Attempt reasoning before opening guidance. Extend time when actual understanding requires it; investigations and chapter assessments have separate sessions.
Start with something to explain
Does the word covalent tell you whether a substance consists of molecules?
Illustrative evidence case. H₂ is molecular while diamond has an extended carbon-bond network.
Notice and wonder
Record two observations using the stated quantities or relationships. Keep observations separate from possible causes. Write one question that a new measurement could help answer.
Does the word covalent tell you whether a substance consists of molecules?
Your first model
Sketch the difference between within-molecule bonds and connections across a solid.
Build the language from the idea
- covalent bond
- Bonding involving shared electron density between atoms; Lewis lines represent shared pairs in a simplified model.
- molecule
- A neutral group of atoms held together by covalent bonds.
- bonding pair
- A pair of electrons shared between two atoms, forming a covalent bond.
- lone pair
- A pair of valence electrons on an atom that is not shared in a bond.
- Lewis structure
- A diagram that shows an atom's or molecule's valence electrons as dots and each bonding pair as a line.
- double bond
- A covalent bond in which two pairs of electrons (four electrons) are shared.
- triple bond
- A covalent bond in which three pairs of electrons (six electrons) are shared.
- diatomic molecule
- A molecule made of exactly two atoms, such as O₂ or N₂.
A covalent bond involves shared electron density in an interacting atomic arrangement. A Lewis line represents a shared pair for bookkeeping, not a rigid connection or atoms consciously reaching a compromise. Covalent bonding can produce discrete molecules, such as H₂O, or extended network structures, such as diamond. The octet rule is a useful pattern for many main-group examples, with known exceptions; it does not itself supply a physical cause or a complete energy account.
Picture two hydrogen atoms drifting together. Each brings a single electron, and rather than one stealing from the other, they pool their two electrons into one shared bonding pair that both nuclei attract. That shared pair — one pair, two electrons — is a single covalent bond, often drawn as a simple line: H–H. Not every electron gets shared, though. In water, the oxygen atom shares one pair with each hydrogen but keeps two pairs entirely to itself; electrons that aren't shared are called lone pairs, and, as you'll see in the next lesson, they quietly shape the whole molecule.
A double bond is represented by two shared pairs in a simple Lewis model, and a triple bond by three. Comparable atom pairs often have shorter, stronger bonds at higher order, but this is not a universal comparison across unrelated species or a claim that bond energy is an exact multiple of pair count. Nitrogen’s strong N≡N bond helps explain some kinetic barriers, while actual reactivity still depends on pathway and conditions.
Chemists keep track of all these shared and unshared electrons with Lewis structures — simple maps that show every valence electron as a dot and every bonding pair as a line. To draw one, you add up the valence electrons from all the atoms, connect the atoms with single bonds, and then hand out the leftover electrons as lone pairs until each atom (except hydrogen, which is content with just two) is surrounded by eight. If there aren't enough electrons to give everyone an octet with single bonds, you pull lone pairs in to make double or triple bonds. The Lewis structure of water, for instance, shows two O–H bonding pairs and two lone pairs resting on the oxygen.
In many molecular substances, ordinary melting or boiling changes arrangements and intermolecular interactions while the molecules’ internal covalent connections remain intact. Extended covalent networks require another structural account. Melting, boiling and conductivity depend on size, shape, phase and electronic/ionic carriers, so low boiling or poor conduction is not a definition of every covalent substance.
So covalently bonded atoms build an astonishing range of substances through varied bonding arrangements — the O₂ you breathe, the CO₂ you exhale, the water that fills the oceans, and the enormous molecules of DNA and protein that run every living cell. Understanding *how many* pairs atoms share, and *where* the lone pairs sit, is the launch pad for the final piece of the bonding story: the three-dimensional shapes these molecules fold into, and why those shapes matter so much.
Model check: Sharing need not be equal; polar covalent bonds share electron density unevenly. Three shared pairs give six bonding electrons, not three.
Build your understanding
Use the detailed parent plan: two core 50–60-minute sessions per focused unit, with a third assigned for selected calculation/modeling topics. First study the core explanation and Parts 1–2 with their figures/checks; next study Parts 3–4, the whole-unit application, worked cases, varied practice and exit check. Attempt reasoning before opening guidance. Extend time when actual understanding requires it; investigations and chapter assessments have separate sessions.
Part 1 · Model sharing without literal electron ownership
A covalent bond involves shared electron density between atoms. Attraction between nuclei and electron density competes with repulsions, producing a characteristic equilibrium distance for a specified species. A drawn line commonly represents a shared pair in a Lewis model, not a solid rod or proof that the electrons remain at the midpoint. Electrons are not permanently assigned to one nucleus by physical ownership; formal electron assignments are bookkeeping conventions used for different questions.
Read the visual model
Identify the labeled structures and units, then trace the arrows or compare values under the caption’s stated conditions. Separate the displayed evidence from a further inference. Write your reasoning before opening the guidance.
What does the line in the selected H–H drawing represent, and what does it leave out?
Visual reasoning — after your attempt
It represents a shared electron pair in a simplified bonding model. It omits the spatial electron distribution, motion/vibration and full energy account.
A covalent bond involves shared electron density associated with two nuclei. Bond formation reflects an energy balance among attractions and repulsions; bonding does not occur simply because atoms consciously want full shells. A line in a structural formula usually represents one shared pair in an introductory Lewis model.
H₂ has one bonding pair and no lone pairs in its simplest model. O₂ requires a different electron account. Bond lines are representational conventions, not physical sticks.
Pause and explain
What does one Lewis bond line represent?
Check your reasoning after answering
It represents a shared electron pair in the introductory model, rather than a rigid material connector or a definite electron orbit.
Part 2 · Distinguish molecules from network structures
A molecular substance contains discrete molecules with covalent bonds inside each molecule and interactions between molecules. An extended covalent network has bonding connections through a larger structure, as in diamond or silica. Melting or softening mechanisms and electrical behavior depend on that arrangement, not just the word covalent. A square connection sketch here is topological bookkeeping; it is not the tetrahedral geometry of diamond or a claim that carbon always forms four bonds in one flat plane.
Read the visual model
Identify the labeled structures and units, then trace the arrows or compare values under the caption’s stated conditions. Separate the displayed evidence from a further inference. Write your reasoning before opening the guidance.
Why can two covalent substances have very different melting behavior?
Visual reasoning — after your attempt
One may consist of molecules separated mainly by intermolecular interactions, while another requires major network rearrangement; actual structure and conditions matter.
Many covalent substances consist of discrete molecules, but others form extended networks. Molecular boiling often separates molecules without breaking their internal covalent bonds. Network melting can involve much stronger structural disruption. The word covalent alone cannot predict a low boiling point.
Water boiling separates intact H₂O molecules through changes in intermolecular interactions. Diamond has an extended carbon network, so an isolated small-molecule picture is inappropriate.
Pause and explain
Does boiling water break H–O bonds into hydrogen and oxygen?
Check your reasoning after answering
No. Ordinary boiling retains water molecules and changes their intermolecular arrangement. Chemical decomposition would be a different process.
Part 3 · Relate bond order and length with conditions
Bond order summarizes bonding in a model: a Lewis single, double or triple line commonly represents one, two or three shared pairs. For comparable atom pairs, higher bond order often corresponds to shorter, stronger bonds, but bond energies are not exact integer multiples and depend on the surrounding molecule. Bond dissociation energy concerns a specified bond-breaking process. Delocalized structures can have intermediate effective orders, so a selected Lewis drawing should not be treated as a direct ruler or calorimeter.
Read the visual model
Identify the labeled structures and units, then trace the arrows or compare values under the caption’s stated conditions. Separate the displayed evidence from a further inference. Write your reasoning before opening the guidance.
Does a C=C double bond have exactly twice the dissociation energy of every C–C single bond?
Visual reasoning — after your attempt
No. Bond order supports a qualitative comparison for suitable species, but measured energy depends on the full bonding environment and defined process.
Single, double, and triple bonds represent different bonding patterns. For comparable atoms, increasing bond order often means shorter stronger bonds, but actual values depend on the atoms and molecular environment. Do not rank every unrelated bond solely by counting lines.
Compare C–C, C=C, and C≡C in suitable reference data. A higher bond order does not automatically establish a molecule’s boiling temperature, which also depends on intermolecular interactions and structure.
Pause and explain
Why can bond strength not alone predict molecular boiling point?
Check your reasoning after answering
Boiling generally disrupts intermolecular interactions, not the internal covalent bonds. Molecular size, shape, and intermolecular forces matter.
Part 4 · Separate bond polarity from molecular polarity
A polar covalent bond has unequal electron-density distribution associated with different bonded-atom attractions. The symbols δ+ and δ− denote partial charge, distinct from the integer charge of an isolated ion. A bond dipole includes direction and magnitude. A molecule’s net dipole depends on the geometry and combination of all relevant contributions, so polar bonds can cancel in a symmetric molecule. Electronegativity differences are useful guides, not an exact universal boundary between perfectly ionic and perfectly covalent behavior.
Read the visual model
Identify the labeled structures and units, then trace the arrows or compare values under the caption’s stated conditions. Separate the displayed evidence from a further inference. Write your reasoning before opening the guidance.
Why do δ+ and +1 communicate different claims?
Visual reasoning — after your attempt
δ+ indicates a partial charge in a bonding model; +1 denotes a net ionic charge of one elementary-charge unit for the species.
Unequal electron sharing can produce a polar bond. Whole-molecule polarity depends on the vector combination of bond dipoles and geometry. A molecule with polar bonds can be nonpolar if the arrangement cancels the dipoles, so structure is needed in addition to electronegativity differences.
Linear CO₂ has polar C–O bonds arranged oppositely, while bent H₂O does not cancel its bond dipoles. Both require geometry to reach the molecular conclusion.
Pause and explain
Why are polar bonds insufficient to establish a polar molecule?
Check your reasoning after answering
Bond dipoles can cancel in a symmetric arrangement. Molecular shape and all dipoles determine the overall result.
Apply the whole unit · Compare boiling and chemical change
Illustrative records: liquid water becomes vapor with H₂O molecules retained; a supplied electrochemical decomposition produces H₂ and O₂. CO₂ is supplied as linear and H₂O as bent.
Your task
Compare which interactions change in the two water processes, draw molecular polarity arrows, and explain why both polar bonds and molecular geometry are needed to predict polarity.
What your response should show
- Choose the appropriate chemical model or relationship and state its conditions.
- Show substitutions, units, particle or charge counts, and intermediate reasoning as relevant.
- Use supplied evidence to justify the conclusion; distinguish observation from inference.
- Identify a meaningful limitation, uncertainty, or next measurement.
Response guidance — after your attempt
Boiling changes intermolecular organization while retaining H–O bonds in water molecules.
Decomposition rearranges atoms into different substances with new bond patterns.
Draw opposite equal CO₂ bond dipoles and bent H₂O dipoles.
Compare vector cancellation rather than simply counting polar bonds.
Boiling is a physical change; the supplied decomposition is chemical. Linear CO₂ is nonpolar in the symmetric model while bent water is polar. These conclusions concern the provided structures and do not justify performing water electrolysis at home or treating every covalent substance as a low-boiling molecular material.
Scientific references and source-model foundations
Parent / teacher teaching notes
Ask which bonds or interactions change at each stage. Use supplied molecular shapes and insist on a molecule-level polarity conclusion. Ask the learner to explain each particle symbol, axis, unit and arrow before calculating. Distinguish hypothetical models and calculated curves from measured records. Public OpenSciEd excerpts here are selected foundation prompts, not complete high-school teacher editions or an endorsement. All required advanced explanations and practice are provided locally.
The key idea
Covalent bonding involves shared electron density. Discrete molecules and extended networks have different structures and properties. Bond order, polarity and energy comparisons need the actual species and bonding context.
Total Valence Electrons (for a Lewis structure)
total valence e⁻ = sum of every atom's valence electrons (add 1 for each unit of negative charge, subtract 1 for each unit of positive charge)
the first step in drawing a Lewis structure. Example: H₂O = 6 (from O) + 1 + 1 (from the two H) = 8 electrons = 4 pairs.
Electrons Shared in a Bond
shared electrons = 2 × (number of shared pairs)
a single bond shares 1 pair = 2 electrons, a double bond shares 2 pairs = 4 electrons, and a triple bond shares 3 pairs = 6 electrons.
Worked examples
Example 1
- Add up the valence electrons: oxygen contributes 6 and each hydrogen contributes 1, for 6 + 1 + 1 = 8 electrons (4 pairs).
- Bond the oxygen to each hydrogen with a single bond. That uses 2 pairs as bonding pairs (the two O–H bonds).
- Place the remaining 2 pairs on oxygen as lone pairs, completing oxygen's octet (each H is satisfied with its shared pair).
Example 2 · Worked application
- A single bond involves one shared pair; a double bond two.
- For the same bonded atoms, higher bond order generally corresponds to shorter, stronger bonding.
- Actual values depend on chemical context.
A shared pair is not ownership transferred permanently to only one atom.
Example 3
- Each double bond is 2 shared pairs, and each pair is 2 electrons, so one double bond shares 4 electrons.
- There are two double bonds in O=C=O.
- Total shared electrons = 2 double bonds × 4 electrons = 8 electrons.
Example 4 · Find and fix the mistake
- Test the claim against the stated conditions: A shared pair is not ownership transferred permanently to only one atom.
- Electronegativity differences can cause uneven sharing and bond polarity.
A shared pair is not ownership transferred permanently to only one atom.
Example 5 · Reason from the visual model
- Bond order summarizes bonding in a model: a Lewis single, double or triple line commonly represents one, two or three shared pairs. For comparable atom pairs, higher bond order often corresponds to shorter, stronger bonds, but bond energies are not exact integer multiples and depend on the surrounding molecule. Bond dissociation energy concerns a specified bond-breaking process. Delocalized structures can have intermediate effective orders, so a selected Lewis drawing should not be treated as a direct ruler or calorimeter.
- No. Bond order supports a qualitative comparison for suitable species, but measured energy depends on the full bonding environment and defined process.
Original qualitative matched C–C comparison; no universal bond-length or bond-energy dataset is asserted.
Avoid these mistakes
- Sharing need not be equal; polar covalent bonds share electron density unevenly.
Check your understanding
How many electrons are in a triple bond?
Discuss the answer
Three shared pairs give six bonding electrons, not three.
Return to the phenomenon
Return to the initial case. Does the word covalent tell you whether a substance consists of molecules? Revise your drawing or explanation using two named ideas and one stated limitation.
Compare explanations after your attempt
Covalent describes bonding, not one bulk arrangement. Discrete molecules and extended networks need different structural and property explanations.
What should we investigate next?
Which comparison would test a remaining uncertainty? State what you would change, keep comparable and measure.
Investigate, calculate and revise
Keep a first model and an evidence-supported revision. Attempt each task before opening guidance; all required explanations and supplied-data routes are available locally.
Activity 1 · Return to the opening case
Use the opening phenomenon, unit definitions and explained Parts 1–4.
Your task
Return to the initial case. Does the word covalent tell you whether a substance consists of molecules? Revise your drawing or explanation using two named ideas and one stated limitation.
Success criteria
- Use the stated observations and appropriate units.
- Connect a labeled model with the chemical mechanism.
- State assumptions and an evidence limitation.
- Explain a substantive revision or next test.
Hint
Keep species identity, material transfer and energy account distinct.
Response guidance — discuss after your attempt
Covalent describes bonding, not one bulk arrangement. Discrete molecules and extended networks need different structural and property explanations.
Activity 2 · Transfer to a changed case
Cover the worked answer and use the explained models, relationships and notebook.
Your task
Compare CO₂ and H₂O: both have polar bonds. Explain why bond polarity alone cannot establish that both molecules have a net dipole.
Success criteria
- Use the stated measurements or conditions, with correct units.
- Connect the result to the chemical mechanism or evidence relationship.
- Identify the assumption, model limit or further evidence requested.
Hint
Name known quantities and conditions, show intermediate steps and check conservation.
Response guidance — discuss after your attempt
CO₂ is linear with equal opposing bond contributions that cancel in the ideal symmetric molecule. H₂O is bent, so its bond dipoles do not cancel. Geometry and the full charge distribution matter.
Words to know
- covalent bond
- Bonding involving shared electron density between atoms; Lewis lines represent shared pairs in a simplified model.
- molecule
- A neutral group of atoms held together by covalent bonds.
- bonding pair
- A pair of electrons shared between two atoms, forming a covalent bond.
- lone pair
- A pair of valence electrons on an atom that is not shared in a bond.
- Lewis structure
- A diagram that shows an atom's or molecule's valence electrons as dots and each bonding pair as a line.
- double bond
- A covalent bond in which two pairs of electrons (four electrons) are shared.
- triple bond
- A covalent bond in which three pairs of electrons (six electrons) are shared.
- diatomic molecule
- A molecule made of exactly two atoms, such as O₂ or N₂.
The chemist who invented the dot diagram
The shared-pair picture you use today came from Gilbert N. Lewis, who in 1916 proposed that atoms bond by sharing pairs of electrons — years before physicists fully understood what an electron even was. He first sketched electrons as dots on the corners of a cube, and that humble idea grew into the Lewis structures chemists still draw a century later. Lewis was nominated for the Nobel Prize dozens of times but never won it, one of the most famous oversights in the history of chemistry.
When the octet rule bends
The octet rule is a superb guide, not an unbreakable law. Hydrogen is satisfied with just two electrons (a 'duet'), not eight. Boron happily settles for only six electrons around it in a molecule like BF₃, staying electron-hungry. And larger atoms from the third row down, like the sulfur in SF₆, can hold more than eight in an 'expanded octet.' Knowing when the rule bends is part of thinking like a chemist rather than memorizing a slogan.
The covalent solids that refuse to melt
You just learned that molecular substances melt at low temperatures — so how can diamond, pure covalently bonded carbon, be the hardest natural material, melting only above 3500°C? The trick is that diamond isn't built from separate little molecules. Every carbon is bonded to four others in one continuous covalent network that runs through the whole crystal, so melting it means shattering countless strong bonds at once. Quartz (SiO₂) and the silicon carbide in sandpaper are network solids too — a giant exception well worth remembering.
The strongest bond in the air you breathe
About four-fifths of every breath is nitrogen gas, N₂, locked by a triple bond so strong (roughly 945 kilojoules per mole) that the gas is almost completely unreactive. That's mostly a blessing — but it also means plants can't use the nitrogen floating right above them. Only lightning and certain bacteria can crack the triple bond naturally, and in the early 1900 s the Haber–Bosch process learned to do it industrially under crushing heat and pressure. The fertilizer it makes now helps feed roughly half the people on Earth.
Why carbon builds a whole branch of chemistry
One covalent atom is so versatile that an entire science is named after it. Carbon has four valence electrons, so it forms four strong covalent bonds and, uniquely, bonds happily to itself — chaining into rings, sheets, and branches of almost unlimited length. That single talent, called catenation, is why there are millions of carbon compounds, from the methane in a stove to the DNA in your cells, and why organic chemistry exists as its own enormous field.
In the real world
The oxygen you breathe (O₂, held by a double bond) and the nitrogen that makes up most of the air (N₂, held by a very strong triple bond) are both covalent molecules. That tough nitrogen triple bond is why the gas is so unreactive — and why turning it into fertilizer to feed the world takes enormous energy.
Exit check
How many electrons are in a triple bond?
Check your explanation after answering
Three shared pairs give six bonding electrons, not three.
Explain your reasoning without notes. If a key idea is missing, revisit the lesson and try again.
Metallic Bonding
Learning goals
- I can describe metallic bonding using the electron-sea model of positive ions in a shared pool of delocalized electrons.
- I can use the electron-sea model to explain metals' conductivity, malleability, ductility, and luster.
Readings for this unit
Before this unit
Metal valence electrons and mobile charge.
Use the detailed parent plan: two core 50–60-minute sessions per focused unit, with a third assigned for selected calculation/modeling topics. First study the core explanation and Parts 1–2 with their figures/checks; next study Parts 3–4, the whole-unit application, worked cases, varied practice and exit check. Attempt reasoning before opening guidance. Extend time when actual understanding requires it; investigations and chapter assessments have separate sessions.
Start with something to explain
Can making a metal stronger create another design tradeoff?
Illustrative evidence case. A selected alloy increases a strength index while reducing a conduction index.
Notice and wonder
Record two observations using the stated quantities or relationships. Keep observations separate from possible causes. Write one question that a new measurement could help answer.
Can making a metal stronger create another design tradeoff?
Your first model
Keep bonding mechanisms separate from the actual service criteria.
Build the language from the idea
- metallic bond
- The attraction between positively charged metal ions and the surrounding sea of delocalized electrons.
- delocalized electrons
- Valence electrons that are not tied to a single atom but move freely throughout a piece of metal.
- electron sea
- The model that pictures a metal's valence electrons as a mobile 'sea' shared by all of the metal ions at once.
- malleable
- Able to be hammered or rolled into thin sheets without breaking.
- ductile
- Able to be drawn out into a wire.
- luster
- The shiny appearance of a polished metal surface.
- alloy
- A mixture of a metal with one or more other elements, such as steel or brass.
You've now seen two ways atoms bond — ionic (electrostatic attraction among ions) and covalent (sharing them between two atoms). But there's a third kind, and it hides in plain sight in the spoon in your drawer and the wire in your wall: metallic bonding, the bond that holds a chunk of pure metal together. Metals are almost all cations-in-waiting — they cling to their valence electrons so loosely that, when millions of metal atoms pack together, something remarkable happens to those outer electrons.
Instead of clinging to individual atoms, valence electron density is delocalized in the simplified model and pool together into a shared, mobile crowd that belongs to the whole piece of metal at once. Chemists picture this as a 'sea of electrons': a lattice of positively charged metal ions sitting in a fluid ocean of delocalized electrons — 'delocalized' meaning the electrons aren't tied to any one atom but are free to roam everywhere. The metallic bond is the strong, reaches-in-every-direction attraction between those fixed positive ions and the negative electron sea washing around them, gluing the metal together.
This one picture explains nearly every famous property of metals. Start with electrical conductivity. Because the electrons in the sea are free to move, the tiniest push from a voltage sends them drifting through the metal — and moving electrons are exactly what an electric current is. The very same mobile electrons also ferry heat quickly from a hot spot to a cold one, which is why a metal spoon left in hot soup soon warms all the way up the handle while a plastic one stays cool.
Next come malleability and ductility — the ability to be hammered into thin sheets or drawn into long wires without shattering. Here the electron sea works like a flexible cushion. When you strike a metal, layers of positive ions slide to new positions, but the electron sea simply flows along with them and keeps holding everything together; no bond is permanently broken. Contrast that with a brittle ionic crystal, where sliding a layer lines up like charges that repel and split the crystal apart. The metal bends; the salt crystal cracks.
The mirror-bright luster of a polished metal comes from those same free electrons: they readily absorb light and re-emit it, bouncing it back to your eye as a shiny surface. And because the metallic bond reaches in every direction and grips the whole lattice at once, most metals are also strong, dense, and high-melting — you have to pour in a lot of energy to tear the ions loose from their electron sea. As a rule, the more valence electrons an atom pours into the sea (and the higher its ion's charge), the stronger the metallic bond: magnesium, giving two electrons per atom, is harder and higher-melting than sodium, which gives only one.
Pure metals are sometimes too soft or too plain for the job, so we mix them into alloys — a metal blended with one or more other elements. Adding carbon to iron makes steel, far stronger than iron alone; copper plus zinc makes brass; copper plus tin makes bronze, the alloy so important that it named an age of human history. The differently sized atoms in an alloy jam up the sliding layers and make the metal harder. From the power grid to skyscrapers to the coins in your pocket, the loose, shared electron sea of metallic bonding is quietly doing the work.
Model check: Not all metals have the same melting point or strength; electron-sea pictures are simplified. Copper has delocalized mobile electrons; salt’s ions are fixed in a lattice under ordinary conditions.
Build your understanding
Use the detailed parent plan: two core 50–60-minute sessions per focused unit, with a third assigned for selected calculation/modeling topics. First study the core explanation and Parts 1–2 with their figures/checks; next study Parts 3–4, the whole-unit application, worked cases, varied practice and exit check. Attempt reasoning before opening guidance. Extend time when actual understanding requires it; investigations and chapter assessments have separate sessions.
Part 1 · Use delocalized electrons to explain metals
A simple metallic bonding model represents positive ion cores interacting with delocalized valence electrons spread through the solid. The cores are not bare nuclei, and the electrons do not form a classical liquid sea with fixed little trajectories. Delocalization helps explain electronic conduction and cohesion. A complete quantum band description is more detailed, but this selected model is useful if its symbols, mobile carriers and limits are stated rather than treating metal as disconnected positive particles.
Read the visual model
Identify the labeled structures and units, then trace the arrows or compare values under the caption’s stated conditions. Separate the displayed evidence from a further inference. Write your reasoning before opening the guidance.
Which parts of the model carry ordinary electronic current, and why are the positive symbols not bare nuclei?
Visual reasoning — after your attempt
Delocalized electrons can carry current. The positive cores include the nucleus and nonvalence electrons in this simplified account.
A metallic-bonding model describes positive ion cores interacting with delocalized valence electrons. The electron population is not fixed into separate pairs between just two neighboring atoms. This model explains mobile charges and bonding throughout a structure, while real metals require more detailed electronic models.
Electrical conduction involves mobile electrons already present in the metal. A current does not mean entire metal nuclei travel down a wire.
Pause and explain
Which particles mainly carry current in a metal?
Check your reasoning after answering
Mobile electrons carry current in the introductory model; the lattice ion cores do not flow through the wire as bulk charge carriers.
Part 2 · Link bonding to shaping and thermal transport
Malleability is the ability to deform under compression without simply shattering. In a simplified metal, layers can shift while delocalized bonding remains distributed, unlike a directional molecular-bond picture. Real deformation involves crystal defects and dislocations, and strength depends on grain structure, alloying and temperature. Heat transport can involve electrons and lattice vibrations. These mechanisms explain tendencies without claiming every metal is equally soft, ductile or thermally conductive under all conditions.
Read the visual model
Identify the labeled structures and units, then trace the arrows or compare values under the caption’s stated conditions. Separate the displayed evidence from a further inference. Write your reasoning before opening the guidance.
Why is “all metals are easy to bend” an overgeneralization of this layer model?
Visual reasoning — after your attempt
The model isolates one bonding feature. Defects, alloy composition, grain structure and conditions strongly affect the actual deformation resistance.
Many metals can be bent or drawn because the bonding can persist as atomic layers rearrange. Electrons and lattice interactions contribute to thermal transport. These broad properties vary by composition, temperature, defects, and structure; metal is not a guarantee of unlimited flexibility or identical conductivity.
Copper wire and a brittle cast alloy can behave differently. Explain the general metallic model while leaving room for structure-specific measurements.
Pause and explain
Why should all metals not be called equally malleable?
Check your reasoning after answering
Composition, crystal structure, defects, and temperature influence mechanical response. The general bonding model supports a pattern, not identical performance.
Part 3 · Treat alloys as engineered mixtures
An alloy combines a metallic element with one or more other elements. In a substitutional model, some host sites are occupied by another species; in an interstitial model, smaller atoms occupy spaces between selected host sites. Both can influence dislocation motion and properties. Real alloys may include several phases and complex microstructures, so a uniform dot pattern is not a universal atom-by-atom picture. State composition, treatment and measured property before recommending an alloy for a design.
Read the visual model
Identify the labeled structures and units, then trace the arrows or compare values under the caption’s stated conditions. Separate the displayed evidence from a further inference. Write your reasoning before opening the guidance.
What distinguishes the two selected alloy models?
Visual reasoning — after your attempt
The substitutional species replaces a host-site occupant; the interstitial species occupies a space between host sites in the simplified arrangement.
An alloy combines elements in a metallic material and can alter strength, corrosion response, or conductivity. Substitutional atoms replace some host atoms; interstitial atoms fit in spaces in a simplified model. Alloys need not have one fixed compound formula or a single universal property improvement.
Small carbon amounts in iron can change mechanical behavior. A stronger alloy may be less conductive or less easily shaped; identify the job before choosing a composition.
Pause and explain
Does adding another element always improve a metal for every use?
Check your reasoning after answering
No. It changes properties with trade-offs. Improvement depends on the intended job and measured constraints.
Part 4 · Compare equivalent designs using measured data
A design criterion is an outcome used to compare options, while a constraint limits what is acceptable. An alloy with greater strength can have lower conductivity or higher cost; the best option depends on the intended service. Define comparable dimensions, temperature, loading and measurement methods before comparing material data. The selected indexes here are invented, unitless teaching scores, not tensile strengths or electrical conductivities. Use them only within the stated decision problem and ask what additional evidence is needed.
Read the visual model
Identify the labeled structures and units, then trace the arrows or compare values under the caption’s stated conditions. Separate the displayed evidence from a further inference. Write your reasoning before opening the guidance.
If a design requires strength index at least 70 and conduction index at least 60, which listed option satisfies both?
Visual reasoning — after your attempt
B meets both; A fails the strength criterion and C fails the conduction criterion. Cost and other service requirements remain unknown.
A material selection should compare the same service, dimensions, and conditions. Conductivity, mass, cost, and corrosion evidence may favor different choices. A microscopic bonding explanation supports interpretation but does not supply all missing engineering measurements.
For a fixed wire job, compare resistance and mass at suitable geometry and temperature. Do not compare equal masses when the task actually requires equal length and cross-section.
Pause and explain
Why must geometry be controlled in a conductivity comparison?
Check your reasoning after answering
Measured resistance depends on length and cross-section as well as material. Unequal geometry can obscure the material comparison.
Apply the whole unit · Choose a conductor under constraints
Illustrative equal-length/equal-area candidates: A has resistance 0.20 Ω and mass 40 g; B has 0.35 Ω and mass 20 g. The job requires resistance at most 0.30 Ω and mass at most 50 g.
Your task
Choose a qualifying material, explain conductivity with the metallic model, discuss a trade-off, and identify missing evidence needed for outdoor long-term use.
What your response should show
- Choose the appropriate chemical model or relationship and state its conditions.
- Show substitutions, units, particle or charge counts, and intermediate reasoning as relevant.
- Use supplied evidence to justify the conclusion; distinguish observation from inference.
- Identify a meaningful limitation, uncertainty, or next measurement.
Response guidance — after your attempt
Check resistance: A passes 0.20≤0.30; B fails 0.35>0.30.
Both pass the 50 g mass limit.
Select A for the supplied criteria, rather than choosing B only for lower mass.
Request corrosion, mechanical durability, and temperature-response evidence for the intended environment.
A qualifies for this measured job and B does not. Delocalized mobile electrons support metallic electrical conduction, but the model alone does not establish measured resistance or lifetime. The lighter B offers a mass advantage that cannot override a required resistance limit. Long-term selection needs additional environmental and structural data.
Scientific references and source-model foundations
Parent / teacher teaching notes
Keep constraints separate from preferences. Ask students to connect particle structure to a property while recognizing what still needs measurement. Ask the learner to explain each particle symbol, axis, unit and arrow before calculating. Distinguish hypothetical models and calculated curves from measured records. Public OpenSciEd excerpts here are selected foundation prompts, not complete high-school teacher editions or an endorsement. All required advanced explanations and practice are provided locally.
The key idea
Metallic bonding can be modeled using positive ion cores and delocalized valence electrons. Conductivity, deformation and alloy properties also depend on structure, defects, composition and conditions.
Worked examples
Example 1
- In copper, each atom releases its valence electrons into a shared 'sea' of delocalized electrons that are free to move.
- When a voltage is applied across the wire, it pushes on these free electrons.
- The electrons drift through the metal in response, and that flow of charge is an electric current.
Example 2 · Worked application
- Delocalized electrons support charge motion through the metal.
- Layers of ion cores can shift while metallic bonding persists.
- This model helps explain conductivity and malleability.
A model explains trends, but real alloys and structures affect behavior.
Example 3
- In gold, the positive metal ions sit in a sea of delocalized electrons.
- When the metal is struck, layers of ions slide to new positions, but the electron sea flows with them and keeps holding the ions together, so the metal changes shape instead of breaking.
- In a salt crystal, shifting a layer of ions lines up like charges (positive next to positive, negative next to negative); they repel strongly and the crystal splits apart.
Example 4 · Find and fix the mistake
- Test the claim against the stated conditions: A model explains trends, but real alloys and structures affect behavior.
- The lattice rearranges within a bonded solid; bending need not break it into independent particles.
A model explains trends, but real alloys and structures affect behavior.
Example 5 · Reason from the visual model
- An alloy combines a metallic element with one or more other elements. In a substitutional model, some host sites are occupied by another species; in an interstitial model, smaller atoms occupy spaces between selected host sites. Both can influence dislocation motion and properties. Real alloys may include several phases and complex microstructures, so a uniform dot pattern is not a universal atom-by-atom picture. State composition, treatment and measured property before recommending an alloy for a design.
- The substitutional species replaces a host-site occupant; the interstitial species occupies a space between host sites in the simplified arrangement.
Original topology comparison; atom sizes, spacing and alloy concentrations are illustrative rather than a specific crystal structure.
Avoid these mistakes
- Not all metals have the same melting point or strength; electron-sea pictures are simplified.
Check your understanding
Why can solid copper conduct while solid salt generally cannot?
Discuss the answer
Copper has delocalized mobile electrons; salt’s ions are fixed in a lattice under ordinary conditions.
Return to the phenomenon
Return to the initial case. Can making a metal stronger create another design tradeoff? Revise your drawing or explanation using two named ideas and one stated limitation.
Compare explanations after your attempt
Composition and microstructure can alter several properties at once. A feasible choice must satisfy the specified constraints and be tested under relevant conditions.
What should we investigate next?
Which comparison would test a remaining uncertainty? State what you would change, keep comparable and measure.
Investigate, calculate and revise
Keep a first model and an evidence-supported revision. Attempt each task before opening guidance; all required explanations and supplied-data routes are available locally.
Activity 1 · Return to the opening case
Use the opening phenomenon, unit definitions and explained Parts 1–4.
Your task
Return to the initial case. Can making a metal stronger create another design tradeoff? Revise your drawing or explanation using two named ideas and one stated limitation.
Success criteria
- Use the stated observations and appropriate units.
- Connect a labeled model with the chemical mechanism.
- State assumptions and an evidence limitation.
- Explain a substantive revision or next test.
Hint
Keep species identity, material transfer and energy account distinct.
Response guidance — discuss after your attempt
Composition and microstructure can alter several properties at once. A feasible choice must satisfy the specified constraints and be tested under relevant conditions.
Activity 2 · Transfer to a changed case
Cover the worked answer and use the explained models, relationships and notebook.
Your task
A part requires strength index ≥60 and conduction index ≥70. Materials P, Q and R score (65,80), (90,50), and (50,95). Select a feasible option and name a missing design consideration.
Success criteria
- Use the stated measurements or conditions, with correct units.
- Connect the result to the chemical mechanism or evidence relationship.
- Identify the assumption, model limit or further evidence requested.
Hint
Name known quantities and conditions, show intermediate steps and check conservation.
Response guidance — discuss after your attempt
P satisfies both stated constraints. Q fails conduction and R fails strength. Cost, corrosion, fatigue, fabrication or service temperature could still change the decision.
Words to know
- metallic bond
- The attraction between positively charged metal ions and the surrounding sea of delocalized electrons.
- delocalized electrons
- Valence electrons that are not tied to a single atom but move freely throughout a piece of metal.
- electron sea
- The model that pictures a metal's valence electrons as a mobile 'sea' shared by all of the metal ions at once.
- malleable
- Able to be hammered or rolled into thin sheets without breaking.
- ductile
- Able to be drawn out into a wire.
- luster
- The shiny appearance of a polished metal surface.
- alloy
- A mixture of a metal with one or more other elements, such as steel or brass.
A 'sea of electrons' proposed before the electron was even understood
The image of metal ions floating in a shared electron ocean dates to Paul Drude in 1900, just three years after the electron was discovered. His free-electron model treated a metal's outer electrons as a kind of gas free to roam the whole solid, and it neatly explained why metals conduct heat and electricity so well. Modern physics has since refined it into 'band theory,' but the simple electron-sea picture is still the first and most useful way to understand a metal.
Metals really are bonded — and strongly
A common misconception is that a lump of metal is just atoms stacked like marbles, held together by nothing but their weight. In fact the attraction between the positive ions and the surrounding electron sea is a genuine, powerful bond — which is exactly why most metals are solid, dense, and hard to melt. Tungsten doesn't melt until 3422°C, the highest melting point of any metal, which is why it is spun into the glowing filaments of old light bulbs, where anything weaker would simply vaporize.
The metal that's liquid in your hand
Not every metallic bond is equally strong, and the range is astonishing. Mercury bonds so weakly that it stays liquid at room temperature, pooling in old thermometers; gallium melts at just under 30°C, so a solid chunk turns to liquid in your palm. At the far extreme sits tungsten with its stubborn 3422°C. As a rule, the more valence electrons an atom pours into the sea — and the higher its ion's charge — the stronger the metallic bond and the higher the melting point.
Two different ways to toughen a metal
Alloys are stronger than pure metals because their mismatched atoms jam the layers so they cannot slide as freely, and there are two neat ways to arrange this. In steel, small carbon atoms squeeze into the gaps between the iron ions — an interstitial alloy. In brass, some copper ions are swapped out for similar-sized zinc — a substitutional alloy. Either way the smooth sliding that makes a pure metal soft is disrupted, and the metal grows harder and stronger.
Why wires warm up — and a few lose all resistance
If the electron sea flows so freely, why does a wire have any resistance at all? Because the positive ions are constantly vibrating, and those jiggling ions scatter the drifting electrons and slow them down. Heat the wire and the ions vibrate harder, so its resistance actually rises with temperature. Cool certain metals close to absolute zero, though, and the vibrations nearly stop — a few become superconductors with exactly zero resistance, a startling effect Heike Kamerlingh Onnes discovered in mercury in 1911.
In the real world
Metallic bonding is why copper wires carry electricity through your walls, why gold can be beaten into leaf far thinner than paper, and why a blacksmith can hammer glowing iron into a new shape without it crumbling. Alloys like steel and bronze let us tune those metallic properties for bridges, tools, and instruments.
Exit check
Why can solid copper conduct while solid salt generally cannot?
Check your explanation after answering
Copper has delocalized mobile electrons; salt’s ions are fixed in a lattice under ordinary conditions.
Explain your reasoning without notes. If a key idea is missing, revisit the lesson and try again.
Molecular Geometry & Polarity
Learning goals
- I can use VSEPR theory to predict the shape of a simple molecule from its bonding groups and lone pairs.
- I can decide whether a bond and a whole molecule are polar or nonpolar, and name the main intermolecular forces.
Readings for this unit
Before this unit
Lewis structures, domain counting, and vector cancellation.
Use the detailed parent plan: two core 50–60-minute sessions per focused unit, with a third assigned for selected calculation/modeling topics. First study the core explanation and Parts 1–2 with their figures/checks; next study Parts 3–4, the whole-unit application, worked cases, varied practice and exit check. Attempt reasoning before opening guidance. Extend time when actual understanding requires it; investigations and chapter assessments have separate sessions.
Start with something to explain
Can a molecule have polar bonds but no permanent net dipole?
Illustrative evidence case. The selected comparison pairs linear CO₂ with bent H₂O.
Notice and wonder
Record two observations using the stated quantities or relationships. Keep observations separate from possible causes. Write one question that a new measurement could help answer.
Can a molecule have polar bonds but no permanent net dipole?
Your first model
Draw directional bond contributions and add them using the geometry.
Build the language from the idea
- VSEPR theory
- Valence Shell Electron Pair Repulsion — the idea that electron groups around a central atom spread out as far apart as possible, which sets the molecule's shape.
- molecular geometry
- The three-dimensional shape formed by the atoms in a molecule.
- electronegativity
- A measure of how strongly an atom pulls on the shared electrons in a bond.
- polar bond
- A covalent bond in which electrons are shared unequally, creating a slightly positive end and a slightly negative end.
- nonpolar bond
- A covalent bond in which electrons are shared equally, with no separation of charge.
- dipole
- A separation of partial positive and partial negative charge across a bond or a whole molecule.
- intermolecular force
- An attraction between separate molecules; these are much weaker than the bonds within a molecule.
- hydrogen bond
- A strong intermolecular attraction between a hydrogen bonded to N, O, or F and a lone pair on the N, O, or F of a neighboring molecule.
A Lewis structure drawn flat on paper hides one of the most important facts about a molecule: it is a real, three-dimensional object with a definite shape. And shape is not a minor detail — it decides how a molecule packs, dissolves, smells, and reacts, and whether a life-saving drug fits its target or misses entirely. The tool chemists use to predict that shape from a simple Lewis structure is VSEPR theory, which stands for Valence Shell Electron Pair Repulsion — a long name for one commonsense idea.
The idea is this: the groups of electrons around a central atom all carry negative charge, so they repel one another and spread out as *far apart as possible*, and that spreading fixes the molecule's shape. Count the 'electron groups' on the central atom — each single, double, or triple bond counts as one group, and so does each lone pair. Two groups push to opposite sides and give a linear shape (180°), as in carbon dioxide, O=C=O. Three groups spread into a flat triangle, or trigonal planar (120°). Four groups point to the corners of a tetrahedron (about 109.5°), the shape of methane, CH₄.
Lone pairs are the plot twist. They take up space and repel just like bonding groups — actually a little *more* strongly — but you don't 'see' them when you name the shape, because the name describes only where the *atoms* are. The oxygen in water has four electron groups (two bonds plus two lone pairs), so they arrange tetrahedrally, but with only two hydrogens attached the visible molecule is bent, its H–O–H angle squeezed to about 104.5°. The nitrogen in ammonia has three bonds and one lone pair, giving a trigonal pyramidal shape. The invisible lone pairs quietly push the atoms into these bent and pyramidal forms.
Shape becomes truly powerful when you combine it with polarity. Recall that in a covalent bond atoms share electrons — but they don't always share them *equally*. Electronegativity measures how strongly an atom pulls on that shared pair, and when two bonded atoms differ in electronegativity, the greedier one hogs the electrons, taking on a slight negative charge while its partner is left slightly positive. That lopsided bond is a polar bond, and the little separation of charge is a dipole. When the two atoms are identical, as in O₂, the sharing is perfectly even and the bond is nonpolar.
Here's the subtle part that trips up many students: a molecule can be full of polar bonds and yet be nonpolar *overall* — it all depends on the shape. Think of each polar bond as an arrow (a dipole) pointing toward the greedier atom. If the molecule is symmetric, those arrows point in balanced directions and cancel out, leaving no net pull. Carbon dioxide is the perfect example: its two C=O bonds are polar, but the molecule is linear, so the two arrows point in exactly opposite directions and cancel — CO₂ is nonpolar. Water has equally polar O–H bonds, but because it is *bent*, the arrows don't cancel; they add up to a net dipole, so water is polar. Same kind of bonds, opposite result — all because of shape.
Molecular polarity, in turn, controls the intermolecular forces — the attractions *between* whole molecules that decide whether a substance is a gas, a liquid, or a solid. The weakest, present in everything, are fleeting London dispersion forces; polar molecules feel stronger dipole–dipole attractions; and the strongest of all is the hydrogen bond, a powerful attraction between a hydrogen bonded to nitrogen, oxygen, or fluorine and a lone pair on a neighboring molecule. Water's abundant hydrogen bonds are why it boils at a startlingly high temperature for such a small molecule, why ice floats, and why it dissolves so much. A simple rule falls out of all this — 'like dissolves like': polar dissolves polar and nonpolar dissolves nonpolar, which is exactly why oil and water refuse to mix.
Model check: Polar bonds do not automatically make a polar molecule. CO₂ is linear with equal opposite bond dipoles that cancel; bent water has a nonzero molecular dipole.
Build your understanding
Use the detailed parent plan: two core 50–60-minute sessions per focused unit, with a third assigned for selected calculation/modeling topics. First study the core explanation and Parts 1–2 with their figures/checks; next study Parts 3–4, the whole-unit application, worked cases, varied practice and exit check. Attempt reasoning before opening guidance. Extend time when actual understanding requires it; investigations and chapter assessments have separate sessions.
Part 1 · Count electron domains around a center
The VSEPR model uses repulsions among valence-electron regions to predict common molecular geometries. An electron domain is a bonding direction or lone-pair region around the chosen central atom; a double or triple bond counts as one direction in this model. CO₂ has two central bonding domains and no central lone pair, so the ideal geometry is linear. VSEPR is a model with a domain of use, not a complete quantum calculation or a rule that every atom in any molecule must be its center.
Read the visual model
Identify the labeled structures and units, then trace the arrows or compare values under the caption’s stated conditions. Separate the displayed evidence from a further inference. Write your reasoning before opening the guidance.
How many central domains does O=C=O have, even though it contains four shared bonding pairs?
Visual reasoning — after your attempt
Two domains around carbon. Each double bond occupies one bonding direction in VSEPR counting.
In the introductory VSEPR model, bonding regions and lone pairs arrange to reduce repulsion. A single, double, or triple bond counts as one domain for basic geometry prediction. Electron-domain geometry includes lone pairs; molecular geometry names the arrangement of atom positions. These are related but distinct descriptions.
A center with four domains has tetrahedral electron-domain geometry. With two bonded atoms and two lone pairs, its molecular geometry is bent, not tetrahedral.
Pause and explain
Why do water’s four domains not mean four surrounding atoms?
Check your reasoning after answering
Two domains are lone pairs and two are O–H bonding regions. Molecular geometry describes the atom positions, which form a bent shape.
Part 2 · Use lone pairs to refine geometry
A lone pair contributes an electron domain but is not an atom in the molecule’s visible nuclear framework. NH₃ has four central domains: three N–H bonding directions and one lone-pair region. Its electron-domain arrangement is approximately tetrahedral, while the molecular shape is trigonal pyramidal. Wedge-and-dash drawings project depth onto a page; they are not flat measured angles. Lone-pair interactions often change bond angles from idealized domain values, so distinguish a model prediction from a precise measured geometry.
Read the visual model
Identify the labeled structures and units, then trace the arrows or compare values under the caption’s stated conditions. Separate the displayed evidence from a further inference. Write your reasoning before opening the guidance.
Why are tetrahedral and trigonal pyramidal both relevant to NH₃ without being synonyms?
Visual reasoning — after your attempt
Tetrahedral describes all four electron domains; trigonal pyramidal describes the positions of the three bonded atoms relative to nitrogen, excluding the lone pair.
Lone pairs influence bonding-region positions, and observed angles may differ from ideal domain angles. VSEPR is a useful qualitative model, not a universal precise-angle calculator. Identify total electrons and a reasonable Lewis structure before naming a geometry.
NH₃ has three bonds and one lone pair around nitrogen, giving trigonal-pyramidal molecular geometry. CH₄ has four bonds with no lone pairs and tetrahedral geometry.
Optional guided lab · Change lone pairs and compare two kinds of geometry
Optional guided lab · Change lone pairs and compare two kinds of geometry
Optional external exploration — WeduLab. Complete the local explanation first. The task and practice record here are independently written for this course. Choose this in place of comparable practice or allow extra time; it does not add a required session to the year plan.
Predict the atom arrangement for AX4, AX3E and AX2E2. Here A is the central atom, X counts bonded atoms and E counts lone pairs on that center. An electron domain is one region of electron density; a single, double or triple bond counts as one domain in this VSEPR count. These three selected cases all have four domains.
Explore for about 15–20 minutes after the lone-pair explanation. In the VSEPR sandbox select AX4, AX3E and AX2E2 in that order. For each, sketch all four domains, circle only the atom positions and record the displayed angle as a sandbox result. Rotate the view so a three-dimensional shape is not mistaken for a flat drawing. Compare electron geometry with molecular geometry; use the supplied table if the controls are inaccessible.
This is a repulsion-based sandbox. Its live angle is a model output, not a calibrated measurement of a particular molecule. The ideal tetrahedral angle is about 109.5°; real gaseous water has an H–O–H angle about 104.5°. Do not relabel an arbitrary AX2E2 readout as measured water. Colored lobes are representations of electron density, not solid objects or electron orbits. Advanced hybridization, expanded-octet and chirality topics are optional extensions beyond this task.
No-lab route: the original supplied record below contains everything needed for the question. It is not measured evidence collected from WeduLab. Label any separate observations you collect as simulation output, with settings and date.
- Open WeduLab · MoleCraft VSEPR lab (external, English)
- OpenStax Chemistry 2e · molecular structure and polarity reference
| Original four-domain comparison | Bonded atoms / lone pairs | Electron-domain geometry | Molecular geometry |
|---|---|---|---|
| AX4 | 4 / 0 | Tetrahedral | Tetrahedral |
| AX3E | 3 / 1 | Tetrahedral | Trigonal pyramidal |
| AX2E2 | 2 / 2 | Tetrahedral | Bent |
Question 1
Why can all three rows have the same electron-domain geometry but different molecular shapes? A sandbox shows an AX2E2 angle near 108°. Can you report that as the measured bond angle of water? Explain, then use bond-dipole directions to compare the cancellation in ideal CO2 and H2O models.
Worked solution and marking guidance
Electron geometry counts all four regions, while molecular geometry describes the positions of bonded atoms and excludes lone-pair positions.
A sandbox calculates a simplified configuration. Its value does not establish a measured molecular angle; water is about 104.5° under the stated reference conditions.
In linear CO2 the equal C–O bond dipoles oppose and cancel. In bent H2O, the O–H bond dipoles do not cancel, so the molecule is polar.
Four domains do not always mean a tetrahedral molecular shape. The numerical sandbox angle must be labeled as model output. CO2 can have polar bonds but no net molecular dipole, whereas bent water has a net dipole.
- Distinguish domains, bonded atoms and lone pairs.
- Label a model output separately from a measured molecular property.
- Use shape and vector cancellation when explaining polarity.
Pause and explain
Why are NH₃ and CH₄ not assigned the same molecular geometry?
Check your reasoning after answering
Both have four domains, but ammonia has a lone pair instead of a fourth bonded atom. Molecular geometry counts atom positions, not all domains.
Part 3 · Combine bond dipoles as vectors
A dipole moment has direction as well as magnitude. Symmetry can make equal bond contributions cancel, as in an isolated ideal linear CO₂ molecule. In bent H₂O, the corresponding contributions do not cancel, producing a net molecular dipole. A bond can therefore be polar while its entire molecule has no permanent net dipole. The selected arrows point toward the negative ends as a classroom convention; a quantitative dipole calculation needs the actual charge distribution rather than these unscaled arrows alone.
Read the visual model
Identify the labeled structures and units, then trace the arrows or compare values under the caption’s stated conditions. Separate the displayed evidence from a further inference. Write your reasoning before opening the guidance.
Why do two polar C–O bonds not automatically make CO₂ a polar molecule?
Visual reasoning — after your attempt
In the symmetric linear molecule, equal opposing contributions cancel. Geometry is needed along with bond polarity.
A bond dipole points toward the more electronegative side in the common arrow convention. Molecular polarity depends on geometry and whether dipoles cancel. Symmetry must include the identity of surrounding groups; a symmetric-looking center with different substituents may not cancel.
Linear CO₂ has equal opposite bond dipoles. Tetrahedral CH₄ is symmetric, while CH₃Cl has a distinct substituent and a net dipole. Draw arrows instead of deciding from one bond alone.
Pause and explain
Why can replacing one H in CH₄ with Cl change molecular polarity?
Check your reasoning after answering
It breaks the equal-substituent symmetry and changes the dipole sum. Geometry alone without substituent identity does not settle cancellation.
Part 4 · Connect polarity to interactions without a single-factor rule
Molecular polarity affects interactions with neighboring molecules or ions, but bulk behavior also depends on molecular size, shape, polarizability, phase and conditions. Polarizability describes how readily electron density can be distorted. Two substances with different boiling points cannot be explained by counting polar bonds alone. In solutions, disruption of existing interactions and formation of new ones both matter. Use a matched comparison and identify the relevant mechanisms rather than treating polar as a universal synonym for high boiling or water-soluble.
Read the visual model
Identify the labeled structures and units, then trace the arrows or compare values under the caption’s stated conditions. Separate the displayed evidence from a further inference. Write your reasoning before opening the guidance.
Why might two molecules with the same formula have different boiling behavior?
Visual reasoning — after your attempt
Their shapes and intermolecular contact arrangements can differ, affecting dispersion and other interactions even when composition is the same.
Molecular polarity can affect attractions and solubility, but dispersion forces, size, shape, and hydrogen bonding also matter. Like dissolves like is a useful tendency, not a complete calculation of solubility. A nonpolar large molecule may have a higher boiling point than a small polar one.
Compare molecules using complete interaction evidence rather than only whether a dipole exists. State the solvent, temperature, and measured property when testing a polarity-based prediction.
Pause and explain
Does polar automatically mean higher boiling than every nonpolar substance?
Check your reasoning after answering
No. Molecular size, polarizability, shape, and other interactions matter. Polarity is one contributor, not a universal ranking rule.
Apply the whole unit · Predict three molecular shapes
Illustrative supplied Lewis patterns: CO₂ has two bonding domains and no lone pairs on C; H₂O has two bonds and two lone pairs on O; NH₃ has three bonds and one lone pair on N.
Your task
Name electron-domain and molecular geometries, draw dipole directions, and predict whole-molecule polarity. Explain why the prediction does not alone provide exact boiling points.
What your response should show
- Choose the appropriate chemical model or relationship and state its conditions.
- Show substitutions, units, particle or charge counts, and intermediate reasoning as relevant.
- Use supplied evidence to justify the conclusion; distinguish observation from inference.
- Identify a meaningful limitation, uncertainty, or next measurement.
Response guidance — after your attempt
CO₂: two domains, linear domain and molecular geometry.
H₂O: four domains, tetrahedral domain arrangement, bent molecular geometry.
NH₃: four domains, tetrahedral domain arrangement, trigonal-pyramidal molecular geometry.
CO₂ dipoles cancel; bent water and pyramidal ammonia have net dipoles in these models.
The supplied models predict nonpolar CO₂ and polar H₂O/NH₃. Lone pairs belong in the domain count even though molecular shape names describe atom positions. Exact boiling points need all intermolecular interactions and suitable reference data; shape and polarity do not constitute complete property measurements.
Scientific references and source-model foundations
Parent / teacher teaching notes
Have students make both a domain table and a molecular sketch. Do not require precise bond angles from VSEPR alone. Check dipole cancellation rather than memorized polar/nonpolar labels. Ask the learner to explain each particle symbol, axis, unit and arrow before calculating. Distinguish hypothetical models and calculated curves from measured records. Public OpenSciEd excerpts here are selected foundation prompts, not complete high-school teacher editions or an endorsement. All required advanced explanations and practice are provided locally.
The key idea
VSEPR theory says electron groups spread out to set a molecule's shape, and a molecule's overall polarity depends on both its bond polarities and whether that shape lets the dipoles cancel — which in turn sets the intermolecular forces that shape a substance's properties.
Electron Groups on the Central Atom (VSEPR)
electron groups = (atoms bonded to the central atom) + (lone pairs on the central atom)
each single, double, or triple bond counts as ONE group. The number of groups sets the shape: 2 = linear, 3 = trigonal planar, 4 = tetrahedral. Example: the O in H₂O has 2 bonded atoms + 2 lone pairs = 4 groups.
Worked examples
Example 1
- Identify the central atom and count its electron groups: carbon is bonded to 4 hydrogens and has no lone pairs, giving 4 electron groups.
- Four groups repel and spread as far apart as possible, pointing toward the corners of a tetrahedron.
- With an atom at each corner and none missing, the molecule is tetrahedral, with bond angles of about 109.5°.
Example 2 · Worked application
- Each bond has a dipole.
- In the symmetric linear geometry, equal opposing dipoles cancel.
- Molecular polarity is their vector sum, not just the presence of polar bonds.
Compare CO₂ with bent H₂O, where dipoles do not cancel.
Example 3
- Use VSEPR: the central carbon has 2 bonding groups (the two double bonds) and no lone pairs, so the molecule is linear (O=C=O at 180°).
- Each C=O bond is polar because oxygen pulls the shared electrons more strongly, creating two dipoles that point outward in exactly opposite directions.
- Because the molecule is symmetric and linear, the two equal dipoles cancel each other out, leaving no net dipole.
Example 4 · Find and fix the mistake
- Test the claim against the stated conditions: Compare CO₂ with bent H₂O, where dipoles do not cancel.
- Symmetry can cancel bond dipoles; geometry and charge distribution determine the net dipole.
Compare CO₂ with bent H₂O, where dipoles do not cancel.
Example 5 · Reason from the visual model
- A dipole moment has direction as well as magnitude. Symmetry can make equal bond contributions cancel, as in an isolated ideal linear CO₂ molecule. In bent H₂O, the corresponding contributions do not cancel, producing a net molecular dipole. A bond can therefore be polar while its entire molecule has no permanent net dipole. The selected arrows point toward the negative ends as a classroom convention; a quantitative dipole calculation needs the actual charge distribution rather than these unscaled arrows alone.
- In the symmetric linear molecule, equal opposing contributions cancel. Geometry is needed along with bond polarity.
Original qualitative vector comparison. Connectors show bond directions and are not complete Lewis structures; water angles are schematic here.
Avoid these mistakes
- Polar bonds do not automatically make a polar molecule.
Check your understanding
Compare CO₂ and water polarity.
Discuss the answer
CO₂ is linear with equal opposite bond dipoles that cancel; bent water has a nonzero molecular dipole.
Return to the phenomenon
Return to the initial case. Can a molecule have polar bonds but no permanent net dipole? Revise your drawing or explanation using two named ideas and one stated limitation.
Compare explanations after your attempt
Equal opposing contributions cancel in ideal linear CO₂; bent water retains a nonzero net contribution. Bond polarity and molecular polarity answer different questions.
What should we investigate next?
Which comparison would test a remaining uncertainty? State what you would change, keep comparable and measure.
Investigate, calculate and revise
Keep a first model and an evidence-supported revision. Attempt each task before opening guidance; all required explanations and supplied-data routes are available locally.
Activity 1 · Return to the opening case
Use the opening phenomenon, unit definitions and explained Parts 1–4.
Your task
Return to the initial case. Can a molecule have polar bonds but no permanent net dipole? Revise your drawing or explanation using two named ideas and one stated limitation.
Success criteria
- Use the stated observations and appropriate units.
- Connect a labeled model with the chemical mechanism.
- State assumptions and an evidence limitation.
- Explain a substantive revision or next test.
Hint
Keep species identity, material transfer and energy account distinct.
Response guidance — discuss after your attempt
Equal opposing contributions cancel in ideal linear CO₂; bent water retains a nonzero net contribution. Bond polarity and molecular polarity answer different questions.
Activity 2 · Transfer to a changed case
Cover the worked answer and use the explained models, relationships and notebook.
Your task
A molecule has four electron domains around its center, with two bonding pairs and two lone pairs. Predict electron-domain geometry and molecular shape; explain why bond angles need not be 109.5°.
Success criteria
- Use the stated measurements or conditions, with correct units.
- Connect the result to the chemical mechanism or evidence relationship.
- Identify the assumption, model limit or further evidence requested.
Hint
Name known quantities and conditions, show intermediate steps and check conservation.
Response guidance — discuss after your attempt
The electron-domain arrangement is approximately tetrahedral and the molecular shape is bent. Lone-pair interactions and the actual chemical species alter angles; 109.5° is an ideal tetrahedral reference rather than an exact universal bond angle.
Words to know
- VSEPR theory
- Valence Shell Electron Pair Repulsion — the idea that electron groups around a central atom spread out as far apart as possible, which sets the molecule's shape.
- molecular geometry
- The three-dimensional shape formed by the atoms in a molecule.
- electronegativity
- A measure of how strongly an atom pulls on the shared electrons in a bond.
- polar bond
- A covalent bond in which electrons are shared unequally, creating a slightly positive end and a slightly negative end.
- nonpolar bond
- A covalent bond in which electrons are shared equally, with no separation of charge.
- dipole
- A separation of partial positive and partial negative charge across a bond or a whole molecule.
- intermolecular force
- An attraction between separate molecules; these are much weaker than the bonds within a molecule.
- hydrogen bond
- A strong intermolecular attraction between a hydrogen bonded to N, O, or F and a lone pair on the N, O, or F of a neighboring molecule.
The two Ronalds who named the shapes
The tidy rule that electron groups spread out to set a molecule's shape has a name and an origin: VSEPR theory, developed in 1957 by Ronald Gillespie and Ronald Nyholm. Their insight was that you don't need heavy quantum calculations to predict a molecule's geometry — you just count the electron groups around the central atom and let their mutual repulsion do the rest. It remains one of chemistry's best examples of a simple idea with enormous predictive power.
How lone pairs squeeze the angles
Lone pairs don't just bend a molecule — they push harder than bonding pairs, because a lone pair is held by only one nucleus and so spreads out more. That extra shove shows up in the numbers: methane (no lone pairs) sits at a roomy 109.5°, ammonia (one lone pair) is squeezed to about 107°, and water (two lone pairs) is pinched all the way down to 104.5°. The order of pushiness runs lone-pair–lone-pair > lone-pair–bond > bond–bond.
The bent molecule that lets fish survive winter
Water's humble bent shape has outsized consequences. Because the molecule is bent and polar, its many hydrogen bonds lock solid water into an open, roomy lattice — so ice is less dense than liquid water and floats. A freezing pond therefore forms an insulating lid of ice on top while liquid water survives beneath it, letting fish live through the winter. Almost every other substance sinks when it freezes; water's shape makes it a life-preserving exception.
Why soap can wash away grease
'Like dissolves like' says polar mixes with polar and nonpolar with nonpolar — so how does water ever wash off greasy oil? The secret is soap, whose long molecules have a polar head that loves water and a nonpolar tail that clings to grease. The tails bury themselves in the oil while the heads face the water, breaking the grease into tiny droplets that rinse away. A single cleverly shaped molecule bridges two worlds that normally refuse to mix.
Shape, polarity, and the warming planet
A molecule can trap heat only if its shape lets its charges shift as it vibrates. Symmetric O₂ and N₂ — the bulk of the air — stay perfectly balanced when they wiggle, so they let Earth's infrared heat pass straight by. But bent water, and even linear carbon dioxide when it bends and flexes, develop a changing dipole that absorbs that infrared and radiates it back down. That difference in molecular shape is precisely why CO₂ and water vapor are greenhouse gases while the main gases of the air are not.
In the real world
A molecule's shape and polarity decide how it behaves. Water's bent, polar shape lets it dissolve salts and sugars and gives it the surface tension that lets insects walk on a pond, while nonpolar oils won't mix with it — 'like dissolves like.' Drug designers obsess over molecular shape because a medicine works only if it fits the exact target in your body.
Exit check
Compare CO₂ and water polarity.
Check your explanation after answering
CO₂ is linear with equal opposite bond dipoles that cancel; bent water has a nonzero molecular dipole.
Explain your reasoning without notes. If a key idea is missing, revisit the lesson and try again.
Chemical Names, Formulas & Polyatomic Ions
Learning goals
- I can write neutral ionic formulas with polyatomic ions.
- I can distinguish molecular prefixes, subscripts, and metal-charge numerals.
Readings for this unit
Before this unit
Ions, integer ratios, and counting formula subscripts.
Use the detailed parent plan: two core 50–60-minute sessions per focused unit, with a third assigned for selected calculation/modeling topics. First study the core explanation and Parts 1–2 with their figures/checks; next study Parts 3–4, the whole-unit application, worked cases, varied practice and exit check. Attempt reasoning before opening guidance. Extend time when actual understanding requires it; investigations and chapter assessments have separate sessions.
Start with something to explain
Why can changing a subscript change the substance rather than merely its amount?
Illustrative evidence case. CO and CO₂ have different formulas, while 2CO₂ changes how many CO₂ entities are counted.
Notice and wonder
Record two observations using the stated quantities or relationships. Keep observations separate from possible causes. Write one question that a new measurement could help answer.
Why can changing a subscript change the substance rather than merely its amount?
Your first model
Separate a coefficient in front from subscripts inside each formula.
Build the language from the idea
- polyatomic ion
- A bonded group of atoms with an overall charge.
- Roman numeral
- A notation specifying charge of a variable-charge metal cation.
- subscript
- A number giving atom counts within a formula.
A chemical formula states relative particle counts, not a recipe for mixing arbitrary amounts. An ionic compound must be electrically neutral overall. Combine charge magnitudes to find the smallest whole-number ratio, then check the total charge. Ca²⁺ and Cl⁻ give CaCl₂ because +2 + 2(−1) = 0.
A polyatomic ion is a bonded group with net charge that acts as a unit in many reactions. Common examples are ammonium NH₄⁺, hydroxide OH⁻, nitrate NO₃⁻, carbonate CO₃²⁻, sulfate SO₄²⁻, and phosphate PO₄³⁻. Parentheses preserve a group when more than one is needed: Ca(NO₃)₂ contains two nitrate ions.
Name a simple ionic compound with the cation first and anion second. A monatomic anion ends in -ide; oxygen gives oxide and chlorine chloride. Keep the established polyatomic-ion name. Metals with multiple common charges use Roman numerals to specify the cation charge: FeCl₃ is iron(III) chloride, not three iron atoms.
Binary molecular compounds usually use numerical prefixes: mono 1, di 2, tri 3, tetra 4, penta 5, hexa 6. CO is carbon monoxide and CO₂ carbon dioxide. Prefixes specify atom numbers, while Roman numerals specify ionic charge. Do not apply molecular prefixes indiscriminately to salts.
Formula subscripts count atoms inside one formula unit or molecule; a coefficient multiplies the entire formula. In 3Ca(NO₃)₂ there are 3 calcium atoms, 6 nitrogen atoms, and 18 oxygen atoms in the represented particle count. Changing a subscript changes substance identity; changing a coefficient changes amount.
Build a small ion-reference notebook and check neutrality instead of memorizing a criss-cross trick alone. Charge ratios must be reduced: Mg²⁺ and O²⁻ yield MgO, not Mg₂O₂. Naming is a way to communicate structure and composition; household product names do not necessarily identify pure substances.
Build your understanding
Use the detailed parent plan: two core 50–60-minute sessions per focused unit, with a third assigned for selected calculation/modeling topics. First study the core explanation and Parts 1–2 with their figures/checks; next study Parts 3–4, the whole-unit application, worked cases, varied practice and exit check. Attempt reasoning before opening guidance. Extend time when actual understanding requires it; investigations and chapter assessments have separate sessions.
Part 1 · Determine whether the naming system is ionic or molecular
Chemical naming systems differ because formulas describe different kinds of entities. In common ionic nomenclature, ion names and charges determine a neutral ratio; Greek prefixes are not normally used to name sodium oxide as disodium monoxide. For many binary molecular compounds, prefixes communicate atom counts, as in carbon dioxide. A Roman numeral in a variable-charge metal name identifies the metal’s oxidation-state/charge assignment in the ionic model, not the number of metal atoms. Identify the compound type before choosing the naming rules.
Read the visual model
Identify the labeled structures and units, then trace the arrows or compare values under the caption’s stated conditions. Separate the displayed evidence from a further inference. Write your reasoning before opening the guidance.
Why does carbon dioxide use a prefix while iron(III) chloride uses a Roman numeral?
Visual reasoning — after your attempt
The molecular prefix gives oxygen count in CO₂; the Roman numeral assigns iron +3 in the ionic charge account for FeCl₃.
Ionic naming commonly gives a cation followed by an anion, while many binary molecular names use numerical prefixes. Decide from the supplied identities and bonding context rather than blindly applying prefixes to every formula. Element symbols and subscripts carry composition; names should reproduce that information correctly.
NaCl is sodium chloride, not sodium monochloride in standard ionic naming. CO₂ is carbon dioxide in familiar binary molecular naming.
Pause and explain
Why are molecular prefixes inappropriate for ordinary sodium chloride naming?
Check your reasoning after answering
Ionic naming uses ion identities and charge-balanced ratios rather than the binary molecular prefix system.
Part 2 · Use neutrality to identify variable metal charge
For a neutral ionic formula, the sum of ionic charges must be zero. If chloride is −1, three chlorides require an iron assignment of +3 in FeCl₃; two require +2 in FeCl₂. The subscripts and the charge are different quantities. Write an equation rather than copying a subscript into a Roman numeral without checking the anion’s charge. This introductory method applies to the specified ion model; some mixed-valence solids and complex ions require a more detailed account.
Read the visual model
Identify the labeled structures and units, then trace the arrows or compare values under the caption’s stated conditions. Separate the displayed evidence from a further inference. Write your reasoning before opening the guidance.
Would an oxygen subscript of three by itself prove a metal has charge +3?
Visual reasoning — after your attempt
No. Use the number and charge of every ion in the full neutral formula, including the metal count.
Some metals form more than one common cation. A Roman numeral gives the charge/oxidation state specified in the ionic name, not the number of metal atoms. Infer the metal charge from a neutral formula using known anion charges.
In FeCl₃, three Cl⁻ ions total −3, so Fe is +3 and the name is iron(III) chloride. Iron(II) chloride would have a different formula.
Pause and explain
Does iron(III) mean three iron atoms?
Check your reasoning after answering
No. The numeral specifies the +3 ion/oxidation state in this naming context. The formula determines atom or ion count.
Part 3 · Keep a polyatomic ion intact
A polyatomic ion is a charged group of covalently connected atoms, such as nitrate NO₃⁻ or sulfate SO₄²⁻. Its internal formula is retained when charge balance determines how many groups are needed. Calcium nitrate therefore needs two nitrate ions, written Ca(NO₃)₂, giving one Ca, two N and six O atoms. Parentheses group the ion; they do not change its internal subscript to force neutrality. Learn common ion names and charges as linked information, and distinguish similarly named but chemically different ions.
Read the visual model
Identify the labeled structures and units, then trace the arrows or compare values under the caption’s stated conditions. Separate the displayed evidence from a further inference. Write your reasoning before opening the guidance.
How many oxygen atoms are represented by Ca(NO₃)₂, and why is CaNO₆ not an equivalent formula account?
Visual reasoning — after your attempt
Six oxygen atoms occur in two nitrate groups, along with two nitrogen atoms. CaNO₆ would lose a nitrogen and fail to represent the stated ions.
A polyatomic ion has a supplied formula and net charge. Use parentheses when more than one of that group is needed. Do not alter its internal subscripts to balance a compound; doing so changes the ion’s chemical identity. Show the complete charge sum.
Ca²⁺ with NO₃⁻ gives Ca(NO₃)₂. The formula contains one calcium, two nitrogen, and six oxygen atoms per formula unit.
Pause and explain
Why write Ca(NO₃)₂ rather than CaNO₆?
Check your reasoning after answering
Two intact nitrate ions are required. Parentheses preserve nitrate’s N: O ratio and show the full group repeated twice.
Part 4 · Check the name by reconstructing the formula
A reliable nomenclature check reconstructs a formula from the proposed name. Aluminum sulfate combines Al³⁺ and SO₄²⁻ in a 2:3 ratio, while dinitrogen tetroxide specifies molecular counts directly. Reducing a molecular formula such as N₂O₄ to NO₂ would change the named molecule, even though both share an empirical atom ratio. Ionic formula ratios are usually reduced to simplest whole numbers without altering polyatomic groups. Distinguish molecular formula from empirical ratio when checking the result.
Read the visual model
Identify the labeled structures and units, then trace the arrows or compare values under the caption’s stated conditions. Separate the displayed evidence from a further inference. Write your reasoning before opening the guidance.
Why is changing N₂O₄ into NO₂ not merely simplifying the same molecular formula?
Visual reasoning — after your attempt
It changes the molecule’s atom counts. The two formulas share an empirical ratio but denote different molecular entities.
After naming a formula, reconstruct it from the name and supplied ion charges. This round trip catches ambiguous charges and lost parentheses. Molecular names and ionic names encode composition differently, so the check should use the selected naming convention consistently.
From iron(III) oxide, Fe³⁺ and O²⁻ give Fe₂O₃. From dinitrogen tetroxide, prefixes give N₂O₄ without balancing fictional ion charges.
Pause and explain
What is a useful independent check on a chemical name?
Check your reasoning after answering
Rebuild the formula from the name and reference ion charges or prefixes, then compare it with the original composition.
Apply the whole unit · Name and count a nitrate compound
Illustrative reference ions: Fe³⁺ and NO₃⁻. A proposed neutral salt has formula Fe(NO₃)₃. Use standard ionic naming.
Your task
Name the compound, show its charge balance, count each element in one formula unit and in two formula units, and explain the different jobs of the Roman numeral, parentheses, and leading coefficient.
What your response should show
- Choose the appropriate chemical model or relationship and state its conditions.
- Show substitutions, units, particle or charge counts, and intermediate reasoning as relevant.
- Use supplied evidence to justify the conclusion; distinguish observation from inference.
- Identify a meaningful limitation, uncertainty, or next measurement.
Response guidance — after your attempt
Three nitrate ions give −3, balancing one Fe³⁺.
Name: iron(III) nitrate.
One formula unit contains Fe: 1,N: 3,O: 9.
A coefficient 2 multiplies all counts: Fe: 2,N: 6,O: 18.
The Roman numeral denotes iron’s +3 state; the subscript outside parentheses repeats the nitrate group three times; a leading coefficient repeats the entire formula unit. These are not interchangeable. The formula describes composition of a salt, not proof that individual intact neutral Fe(NO₃)₃ molecules exist in an extended solid.
Scientific references and source-model foundations
Parent / teacher teaching notes
Provide a small ion reference list. Require charge sums and formula reconstruction. Watch for changing polyatomic-ion subscripts instead of repeating intact groups. Ask the learner to explain each particle symbol, axis, unit and arrow before calculating. Distinguish hypothetical models and calculated curves from measured records. Public OpenSciEd excerpts here are selected foundation prompts, not complete high-school teacher editions or an endorsement. All required advanced explanations and practice are provided locally.
The key idea
Use charge neutrality for ionic formulas and distinguish ion charge from atom count.
Worked examples
Example 1
- Least common charge magnitude is 6.
- Use 2 aluminum ions and 3 sulfate ions.
- Check +6−6 = 0.
Example 2 · Worked application
- Three oxide ions contribute 3×(−2)=−6.
- Two irons must total +6, giving +3 each.
- Use a Roman numeral for the variable-charge metal.
The Roman numeral gives oxidation state, not number of iron atoms.
Example 3
- Three O²⁻ contribute −6.
- Two iron ions must each be +3.
Example 4 · Find and fix the mistake
- Test the claim against the stated conditions: The Roman numeral gives oxidation state, not number of iron atoms.
- III denotes iron's +3 oxidation state; charge balance gives Fe₂O₃.
The Roman numeral gives oxidation state, not number of iron atoms.
Example 5 · Reason from the visual model
- A polyatomic ion is a charged group of covalently connected atoms, such as nitrate NO₃⁻ or sulfate SO₄²⁻. Its internal formula is retained when charge balance determines how many groups are needed. Calcium nitrate therefore needs two nitrate ions, written Ca(NO₃)₂, giving one Ca, two N and six O atoms. Parentheses group the ion; they do not change its internal subscript to force neutrality. Learn common ion names and charges as linked information, and distinguish similarly named but chemically different ions.
- Six oxygen atoms occur in two nitrate groups, along with two nitrogen atoms. CaNO₆ would lose a nitrogen and fail to represent the stated ions.
Original stoichiometric formula construction; the reaction-style arrow indicates combining counts, not a complete solution reaction.
Avoid these mistakes
- Do not break a polyatomic group apart when balancing charge.
Check your understanding
Compare coefficients, subscripts, and Roman numerals.
Discuss the answer
Coefficients multiply whole particles; subscripts count atoms within a formula; Roman numerals specify a metal ion charge.
Return to the phenomenon
Return to the initial case. Why can changing a subscript change the substance rather than merely its amount? Revise your drawing or explanation using two named ideas and one stated limitation.
Compare explanations after your attempt
Subscripts specify composition of an entity; coefficients scale its amount. Naming and equation balancing must preserve that distinction.
What should we investigate next?
Which comparison would test a remaining uncertainty? State what you would change, keep comparable and measure.
Investigate, calculate and revise
Keep a first model and an evidence-supported revision. Attempt each task before opening guidance; all required explanations and supplied-data routes are available locally.
Activity 1 · Return to the opening case
Use the opening phenomenon, unit definitions and explained Parts 1–4.
Your task
Return to the initial case. Why can changing a subscript change the substance rather than merely its amount? Revise your drawing or explanation using two named ideas and one stated limitation.
Success criteria
- Use the stated observations and appropriate units.
- Connect a labeled model with the chemical mechanism.
- State assumptions and an evidence limitation.
- Explain a substantive revision or next test.
Hint
Keep species identity, material transfer and energy account distinct.
Response guidance — discuss after your attempt
Subscripts specify composition of an entity; coefficients scale its amount. Naming and equation balancing must preserve that distinction.
Activity 2 · Transfer to a changed case
Cover the worked answer and use the explained models, relationships and notebook.
Your task
Write the formula for iron(III) sulfate and count all atoms per formula unit. Then name N₂O₃ using molecular prefixes.
Success criteria
- Use the stated measurements or conditions, with correct units.
- Connect the result to the chemical mechanism or evidence relationship.
- Identify the assumption, model limit or further evidence requested.
Hint
Name known quantities and conditions, show intermediate steps and check conservation.
Response guidance — discuss after your attempt
Fe³⁺ and SO₄²⁻ require Fe₂(SO₄)₃: two Fe, three S and twelve O atoms. N₂O₃ is dinitrogen trioxide. The Roman numeral and prefixes serve different bookkeeping roles.
Words to know
- polyatomic ion
- A bonded group of atoms with an overall charge.
- Roman numeral
- A notation specifying charge of a variable-charge metal cation.
- subscript
- A number giving atom counts within a formula.
In the real world
Use the chapter investigation to connect this unit to measured evidence and a practical decision.
Exit check
Compare coefficients, subscripts, and Roman numerals.
Check your explanation after answering
Coefficients multiply whole particles; subscripts count atoms within a formula; Roman numerals specify a metal ion charge.
Explain your reasoning without notes. If a key idea is missing, revisit the lesson and try again.
Lewis Structures, Resonance & Bond Models
Learning goals
- I can count valence electrons and check a Lewis structure’s total charge.
- I can distinguish resonance, electron-domain geometry, and molecular shape.
Readings for this unit
Before this unit
Valence electrons, ionic charge, and covalent bonding.
Use the detailed parent plan: two core 50–60-minute sessions per focused unit, with a third assigned for selected calculation/modeling topics. First study the core explanation and Parts 1–2 with their figures/checks; next study Parts 3–4, the whole-unit application, worked cases, varied practice and exit check. Attempt reasoning before opening guidance. Extend time when actual understanding requires it; investigations and chapter assessments have separate sessions.
Start with something to explain
Do two resonance drawings show a molecule changing back and forth?
Illustrative evidence case. Two ozone contributors place the formal double bond on opposite sides without moving atoms.
Notice and wonder
Record two observations using the stated quantities or relationships. Keep observations separate from possible causes. Write one question that a new measurement could help answer.
Do two resonance drawings show a molecule changing back and forth?
Your first model
Keep atom positions fixed and track only electron assignments.
Build the language from the idea
- lone pair
- A valence electron pair not represented as a bond.
- formal charge
- An electron-counting assignment, distinct from partial charge.
- resonance
- Multiple electron drawings representing delocalized bonding in one structure.
A Lewis structure is a model of valence electrons: dots represent lone electrons and lines represent shared pairs. Count all valence electrons first; add electrons for negative charge and subtract for positive charge. Identify a central atom, usually a less electronegative non-hydrogen atom, and connect terminal atoms with single bonds.
Distribute remaining electrons to complete terminal octets, with hydrogen needing only two. Put leftovers on the central atom; if its octet is incomplete, consider a double or triple bond. Recount electrons. This procedure explains CO₂ with two double bonds and H₂O with two O–H bonds and two lone pairs on oxygen.
The octet rule is a useful pattern, not a universal law. Hydrogen follows a duet; boron compounds can have incomplete octets; odd-electron molecules exist; some third-period and heavier atom structures are conventionally drawn with expanded valence shells. A model should be applied within its scope.
Formal charge is bookkeeping: valence electrons minus nonbonding electrons minus half of bonding electrons. It is not the same as measured partial charge. For NH₄⁺, nitrogen has 5 − 0 − 4 = +1 and each hydrogen has 0 formal charge; the total is +1.
Resonance structures use the same atom arrangement but different electron placement. The actual bonding is described by a delocalized structure, not a molecule rapidly switching between drawings. In nitrate, three equivalent N–O arrangements contribute; the real bonds are equivalent in the idealized ion.
Use Lewis structure to count electron domains before predicting shape with VSEPR. A double bond counts as one direction of electron density. Separate electron-domain geometry from molecular shape, because lone pairs also occupy domains. Molecular polarity depends on the vector sum of bond dipoles and geometry.
Build your understanding
Use the detailed parent plan: two core 50–60-minute sessions per focused unit, with a third assigned for selected calculation/modeling topics. First study the core explanation and Parts 1–2 with their figures/checks; next study Parts 3–4, the whole-unit application, worked cases, varied practice and exit check. Attempt reasoning before opening guidance. Extend time when actual understanding requires it; investigations and chapter assessments have separate sessions.
Part 1 · Count valence electrons including charge
A Lewis structure tracks valence-electron pairs and atom connectivity. Add the valence electrons from all atoms, then add electrons for negative charge or subtract them for positive charge. In CO₂ the total is sixteen: eight in two double bonds and eight as oxygen lone pairs. A line represents two electrons, while a dot represents one. Counting the whole drawing prevents plausible-looking structures that secretly create or omit electrons; it is a model of valence bookkeeping, not a complete electron-density map.
Read the visual model
Identify the labeled structures and units, then trace the arrows or compare values under the caption’s stated conditions. Separate the displayed evidence from a further inference. Write your reasoning before opening the guidance.
How many lone-pair electrons are shown in the CO₂ structure after its bonding electrons are counted?
Visual reasoning — after your attempt
Eight lone-pair electrons remain after eight of the sixteen are assigned to the two double bonds.
Add valence electrons from each atom, add electrons for negative charge, and subtract for positive charge. Start a reasonable skeleton using supplied connectivity, then distribute electrons while tracking the total. A Lewis structure is an electron-bookkeeping model, not a complete image of quantum electron density.
CO₃²⁻ has 4+3×6+2=24 valence electrons. Ignoring the 2− charge leaves the wrong total and can produce an inconsistent diagram.
Pause and explain
Why does a negative charge increase the valence-electron total?
Check your reasoning after answering
The ion has gained electrons relative to the neutral atom total. Each unit of negative charge adds one electron to the bookkeeping.
Part 2 · Use octets with known exceptions
The octet rule is a useful pattern for many main-group Lewis structures, especially common second-period compounds. It has important exceptions: hydrogen uses a duet, some species are electron-deficient, some have an odd electron, and heavier-element Lewis accounts can assign more than eight electrons around a center. These patterns do not mean atoms consciously seek an octet. Advanced bonding models refine the interpretation of hypervalent species rather than simply proving that empty d orbitals act as storage boxes.
Read the visual model
Identify the labeled structures and units, then trace the arrows or compare values under the caption’s stated conditions. Separate the displayed evidence from a further inference. Write your reasoning before opening the guidance.
Why is an eleven-valence-electron molecule a warning against requiring paired octets everywhere?
Visual reasoning — after your attempt
An odd total cannot be distributed exclusively into paired electron groups; an odd-electron model or a different species assignment must be considered.
For many main-group examples, octets help guide electron placement after bonding and lone pairs are assigned. Hydrogen uses a two-electron arrangement. Electron-deficient species, odd-electron species, and some heavier-element representations require exceptions. Do not force a wrong electron total merely to draw every atom with eight.
NH₄⁺ has four N–H bonds and no nitrogen lone pair in its introductory structure. The charge and hydrogen duet rule are essential to checking the total.
Pause and explain
Should an octet rule override the supplied electron count?
Check your reasoning after answering
No. Keep the correct total and recognize known exceptions. An octet is a useful pattern for many cases, not an unconditional command.
Part 3 · Use formal charge as bookkeeping
Formal charge assigns bonding electrons equally between bonded atoms: valence count minus nonbonding electrons minus half the bonding electrons. In NH₄⁺, nitrogen has four single bonds and no lone pair, giving formal charge +1; each hydrogen has zero. The sum must equal the species’ net charge. Formal charge helps compare Lewis candidates but is not a direct measurement of actual partial charge, and it is distinct from oxidation-number bookkeeping, which assigns bonding electrons differently.
Read the visual model
Identify the labeled structures and units, then trace the arrows or compare values under the caption’s stated conditions. Separate the displayed evidence from a further inference. Write your reasoning before opening the guidance.
Why must the formal charges in a complete NH₄⁺ drawing sum to +1?
Visual reasoning — after your attempt
The electron inventory represents a species with one fewer electron than the neutral-atom sum; the assignments must reproduce that total charge.
Formal charge=valence count−nonbonding electrons−half bonding electrons. The formal charges sum to the total ion charge. This assignment is not identical to measured partial charge or oxidation number. It helps compare plausible Lewis representations when combined with connectivity and chemical evidence.
An oxygen with three lone pairs and one single bond has formal charge 6−6−1=−1. An oxygen with two lone pairs and a double bond has formal charge zero.
Pause and explain
Is formal charge the actual localized physical charge on an atom?
Check your reasoning after answering
Not exactly. It is an equal-sharing bookkeeping assignment; actual electron density and partial charges can be distributed differently.
Part 4 · Interpret resonance as one delocalized structure
Resonance contributors keep the same atom connectivity while changing allowed electron assignments. In the selected ozone account, the central oxygen has +1 formal charge and one terminal oxygen −1 in either contributor. The real molecule is not alternately one localized single/double pattern and then the other; it has a delocalized electronic structure. Equivalent contributors support equivalent bond behavior in the ideal symmetric case. Resonance arrows are not ordinary chemical-reaction arrows or movement of atomic nuclei between structures.
Read the visual model
Identify the labeled structures and units, then trace the arrows or compare values under the caption’s stated conditions. Separate the displayed evidence from a further inference. Write your reasoning before opening the guidance.
What stays fixed when moving between these ozone resonance contributors?
Visual reasoning — after your attempt
The three-oxygen connectivity and nuclear arrangement stay fixed; only the formal electron and bond assignments change.
Resonance contributors have the same atom connectivity but different electron placements. The actual structure is not rapidly flipping between separate drawings. Equivalent contributors can represent delocalization and equalized bonds; bond lengths provide evidence that a single localized drawing is incomplete.
Carbonate has three equivalent placements of one drawn C=O bond. The real ion has equivalent C–O bonds in the usual model, rather than one permanently double bond and two permanently single bonds.
Pause and explain
What stays fixed between resonance contributors?
Check your reasoning after answering
Atom connectivity stays fixed while electron placement changes. They represent contributions to one delocalized structure, not different isomers.
Apply the whole unit · Account for carbonate resonance
Illustrative ion CO₃²⁻ has carbon central and three oxygen neighbors. Use C=4 and O=6 valence electrons, and the formal-charge rule supplied in this lesson.
Your task
Count electrons, draw a valid contributor with one double bond, assign formal charges, draw the other equivalent contributors, and explain what equal measured C–O lengths would support.
What your response should show
- Choose the appropriate chemical model or relationship and state its conditions.
- Show substitutions, units, particle or charge counts, and intermediate reasoning as relevant.
- Use supplied evidence to justify the conclusion; distinguish observation from inference.
- Identify a meaningful limitation, uncertainty, or next measurement.
Response guidance — after your attempt
Count 24 valence electrons.
Use one C=O and two C–O bonds; assign lone pairs to satisfy oxygen octets.
Carbon and double-bonded oxygen have formal charge 0; each single-bonded oxygen has −1.
Move the drawn double bond to each oxygen while keeping connectivity unchanged.
The formal charges total −2 and all 24 electrons are accounted for. Equal C–O lengths support delocalization rather than three permanently unequal localized bonds. Contributors are bookkeeping representations of one ion; they are not atom rearrangements or a movie of the ion switching structures.
Scientific references and source-model foundations
Parent / teacher teaching notes
Check total electrons before judging a diagram. Separate formal charge, oxidation number, and partial charge. Use measured-bond evidence to explain why resonance is needed. Ask the learner to explain each particle symbol, axis, unit and arrow before calculating. Distinguish hypothetical models and calculated curves from measured records. Public OpenSciEd excerpts here are selected foundation prompts, not complete high-school teacher editions or an endorsement. All required advanced explanations and practice are provided locally.
The key idea
Count electrons and charge before predicting bonding, shape, and polarity.
Worked examples
Example 1
- O contributes 6 electrons and two H contribute 2: total 8.
- Two O–H bonds use 4 electrons.
- The remaining 4 give two oxygen lone pairs.
Example 2 · Worked application
- Carbon supplies 4 and two oxygens supply 12: total 16.
- Place carbon centrally and form two double bonds.
- Each oxygen has two lone pairs; count all 16 electrons and check octets.
Formal electron counting is a model; resonance is not rapid physical switching.
Example 3
- C contributes 4 and three O contribute 18.
- Add 2 for the negative charge.
Example 4 · Find and fix the mistake
- Test the claim against the stated conditions: Formal electron counting is a model; resonance is not rapid physical switching.
- Resonance drawings represent contributions to one delocalized electronic structure, not distinct structures flipping back and forth.
Formal electron counting is a model; resonance is not rapid physical switching.
Example 5 · Reason from the visual model
- Formal charge assigns bonding electrons equally between bonded atoms: valence count minus nonbonding electrons minus half the bonding electrons. In NH₄⁺, nitrogen has four single bonds and no lone pair, giving formal charge +1; each hydrogen has zero. The sum must equal the species’ net charge. Formal charge helps compare Lewis candidates but is not a direct measurement of actual partial charge, and it is distinct from oxidation-number bookkeeping, which assigns bonding electrons differently.
- The electron inventory represents a species with one fewer electron than the neutral-atom sum; the assignments must reproduce that total charge.
Original ammonium Lewis bookkeeping. The flat cross shows connectivity only, not the molecule’s tetrahedral geometry.
Avoid these mistakes
- Formal charge is bookkeeping; resonance drawings are not separate alternating molecules.
Check your understanding
How do you check a proposed Lewis structure?
Discuss the answer
Recount valence electrons, confirm total charge, check bond and lone pairs and applicable octet exceptions, then determine shape.
Return to the phenomenon
Return to the initial case. Do two resonance drawings show a molecule changing back and forth? Revise your drawing or explanation using two named ideas and one stated limitation.
Compare explanations after your attempt
They represent one delocalized structure, not a time sequence of two isolated structures. The model should explain equivalent bond behavior and conserve electron count.
What should we investigate next?
Which comparison would test a remaining uncertainty? State what you would change, keep comparable and measure.
Investigate, calculate and revise
Keep a first model and an evidence-supported revision. Attempt each task before opening guidance; all required explanations and supplied-data routes are available locally.
Activity 1 · Return to the opening case
Use the opening phenomenon, unit definitions and explained Parts 1–4.
Your task
Return to the initial case. Do two resonance drawings show a molecule changing back and forth? Revise your drawing or explanation using two named ideas and one stated limitation.
Success criteria
- Use the stated observations and appropriate units.
- Connect a labeled model with the chemical mechanism.
- State assumptions and an evidence limitation.
- Explain a substantive revision or next test.
Hint
Keep species identity, material transfer and energy account distinct.
Response guidance — discuss after your attempt
They represent one delocalized structure, not a time sequence of two isolated structures. The model should explain equivalent bond behavior and conserve electron count.
Activity 2 · Transfer to a changed case
Cover the worked answer and use the explained models, relationships and notebook.
Your task
For NH₄⁺, count valence electrons, assign nitrogen’s formal charge for four N–H single bonds and no lone pair, and distinguish that charge from molecular shape.
Success criteria
- Use the stated measurements or conditions, with correct units.
- Connect the result to the chemical mechanism or evidence relationship.
- Identify the assumption, model limit or further evidence requested.
Hint
Name known quantities and conditions, show intermediate steps and check conservation.
Response guidance — discuss after your attempt
Total valence electrons are 5+4(1)−1=8. Nitrogen formal charge is 5−0−4=+1 and each H is zero. The flat Lewis connectivity does not specify measured angles; the common molecular arrangement is tetrahedral.
Words to know
- lone pair
- A valence electron pair not represented as a bond.
- formal charge
- An electron-counting assignment, distinct from partial charge.
- resonance
- Multiple electron drawings representing delocalized bonding in one structure.
In the real world
Use the chapter investigation to connect this unit to measured evidence and a practical decision.
Exit check
How do you check a proposed Lewis structure?
Check your explanation after answering
Recount valence electrons, confirm total charge, check bond and lone pairs and applicable octet exceptions, then determine shape.
Explain your reasoning without notes. If a key idea is missing, revisit the lesson and try again.
Problem 1
Answer and explanation
K⁺, a 1+ cation.
Potassium has 1 valence electron. It loses that electron to reach a stable full outer shell, leaving one more proton than electron, so it becomes K⁺.
Problem 2
Answer and explanation
CaF₂
Ca²⁺ is +2 and each F⁻ is −1, so two fluoride ions are needed to balance one calcium ion: CaF₂.
Problem 3
Answer and explanation
Dissolving frees the ions to move and carry charge; in the solid they are locked in place.
Conduction needs free-moving charges. In solid NaCl the ions are fixed in the lattice. Dissolving in water separates the Na⁺ and Cl⁻ ions and lets them move, so the solution conducts electricity.
Problem 4
Answer and explanation
Al₂S₃
The total charge must be zero. The charges +3 and −2 have a least common multiple of 6: two Al³⁺ give +6 and three S²⁻ give −6. Criss-crossing the charges gives the subscripts Al₂S₃.
Problem 5
Answer and explanation
Covalent.
Both atoms are the same nonmetal with identical electronegativity, so neither can pull the electrons away. They share a pair of electrons instead of transferring them — a covalent bond.
Problem 6
Answer and explanation
A double bond; 4 electrons shared.
Two shared pairs make a double bond. Two pairs × 2 electrons per pair = 4 shared electrons.
Problem 7
Answer and explanation
Any two of: electrical/thermal conductivity, malleability, ductility, luster.
Delocalized electrons move freely, so they carry electric charge and heat (conductivity), let ion layers slide without breaking (malleability and ductility), and absorb and re-emit light (luster).
Problem 8
Answer and explanation
Magnesium contributes more electrons to the sea and forms higher-charged ions, so its metallic bonding is stronger.
Each magnesium atom donates 2 valence electrons (versus 1 for sodium) and becomes Mg²⁺ (versus Na⁺). The denser electron sea and higher ion charge create a stronger attraction — stronger metallic bonds — so magnesium is harder and higher-melting.
Problem 9
Answer and explanation
Ionic: high melting point, conducts only when molten or dissolved. Molecular: low melting point, does not conduct. Metal: usually high melting point, conducts even as a solid.
Ionic solids have strong lattice-wide electrostatic bonds (high melting) with ions free to move only when molten or dissolved (conducts then). Molecular solids are held together by weak intermolecular forces (low melting) with no free charges (insulator). Metals have strong metallic bonding (often high melting) plus a mobile electron sea (conducts even as a solid).
Problem 10
Answer and explanation
Bent, about 104.5°.
The four electron groups arrange tetrahedrally, but only two atoms are attached, so the visible shape is bent. The two lone pairs repel strongly and squeeze the H–O–H angle to about 104.5°.
Problem 11
Answer and explanation
'Like dissolves like' — nonpolar oil and polar water don't attract each other enough to mix.
Water molecules attract each other strongly through hydrogen bonds. Nonpolar oil molecules can't form those attractions, so the water molecules stay bonded to each other and squeeze the oil out. Polar dissolves polar, nonpolar dissolves nonpolar.
Problem 12
Answer and explanation
Trigonal planar; nonpolar.
Three bonding groups and no lone pairs spread out at 120° into a flat, symmetric trigonal-planar shape. The three equal bond dipoles point outward at 120° and cancel exactly, so the molecule is nonpolar despite its polar bonds.
Problem 13
Answer and explanation
Ca²⁺ needs two Cl⁻ ions for neutrality; a 1:1 formula would carry +1 net charge.
Response criteria
- State a scientifically accurate conclusion.
- Show the calculation or mechanism that supports it.
- Include units, conditions, or limits where relevant.
Problem 14
Answer and explanation
The least common charge magnitude is 6: two Al³⁺ and three O²⁻ give +6−6=0, so Al₂O₃. The formula states a stoichiometric ratio in an extended solid, not a claim of isolated five-ion molecules.
The least common charge magnitude is 6: two Al³⁺ and three O²⁻ give +6−6=0, so Al₂O₃. The formula states a stoichiometric ratio in an extended solid, not a claim of isolated five-ion molecules.
Response criteria
- Use the stated measurements or conditions, with correct units.
- Connect the result to the chemical mechanism or evidence relationship.
- Identify the assumption, model limit or further evidence requested.
Problem 15
Answer and explanation
Three shared pairs give six bonding electrons, not three.
Response criteria
- State a scientifically accurate conclusion.
- Show the calculation or mechanism that supports it.
- Include units, conditions, or limits where relevant.
Problem 16
Answer and explanation
CO₂ is linear with equal opposing bond contributions that cancel in the ideal symmetric molecule. H₂O is bent, so its bond dipoles do not cancel. Geometry and the full charge distribution matter.
CO₂ is linear with equal opposing bond contributions that cancel in the ideal symmetric molecule. H₂O is bent, so its bond dipoles do not cancel. Geometry and the full charge distribution matter.
Response criteria
- Use the stated measurements or conditions, with correct units.
- Connect the result to the chemical mechanism or evidence relationship.
- Identify the assumption, model limit or further evidence requested.
Problem 17
Answer and explanation
Copper has delocalized mobile electrons; salt’s ions are fixed in a lattice under ordinary conditions.
Response criteria
- State a scientifically accurate conclusion.
- Show the calculation or mechanism that supports it.
- Include units, conditions, or limits where relevant.
Problem 18
Answer and explanation
P satisfies both stated constraints. Q fails conduction and R fails strength. Cost, corrosion, fatigue, fabrication or service temperature could still change the decision.
P satisfies both stated constraints. Q fails conduction and R fails strength. Cost, corrosion, fatigue, fabrication or service temperature could still change the decision.
Response criteria
- Use the stated measurements or conditions, with correct units.
- Connect the result to the chemical mechanism or evidence relationship.
- Identify the assumption, model limit or further evidence requested.
Problem 19
Answer and explanation
CO₂ is linear with equal opposite bond dipoles that cancel; bent water has a nonzero molecular dipole.
Response criteria
- State a scientifically accurate conclusion.
- Show the calculation or mechanism that supports it.
- Include units, conditions, or limits where relevant.
Problem 20
Answer and explanation
The electron-domain arrangement is approximately tetrahedral and the molecular shape is bent. Lone-pair interactions and the actual chemical species alter angles; 109.5° is an ideal tetrahedral reference rather than an exact universal bond angle.
The electron-domain arrangement is approximately tetrahedral and the molecular shape is bent. Lone-pair interactions and the actual chemical species alter angles; 109.5° is an ideal tetrahedral reference rather than an exact universal bond angle.
Response criteria
- Use the stated measurements or conditions, with correct units.
- Connect the result to the chemical mechanism or evidence relationship.
- Identify the assumption, model limit or further evidence requested.
Problem 21
Answer and explanation
Dinitrogen tetroxide: two nitrogen and four oxygen atoms.
Response criteria
- State a scientifically accurate conclusion.
- Show the calculation or mechanism that supports it.
- Include units, conditions, or limits where relevant.
Problem 22
Answer and explanation
Ca²⁺ and CO₃²⁻ balance in the smallest 1:1 ratio.
Response criteria
- State a scientifically accurate conclusion.
- Show the calculation or mechanism that supports it.
- Include units, conditions, or limits where relevant.
Problem 23
Answer and explanation
Fe³⁺ and SO₄²⁻ require Fe₂(SO₄)₃: two Fe, three S and twelve O atoms. N₂O₃ is dinitrogen trioxide. The Roman numeral and prefixes serve different bookkeeping roles.
Fe³⁺ and SO₄²⁻ require Fe₂(SO₄)₃: two Fe, three S and twelve O atoms. N₂O₃ is dinitrogen trioxide. The Roman numeral and prefixes serve different bookkeeping roles.
Response criteria
- Use the stated measurements or conditions, with correct units.
- Connect the result to the chemical mechanism or evidence relationship.
- Identify the assumption, model limit or further evidence requested.
Problem 24
Answer and explanation
Four domains are arranged approximately tetrahedrally; considering only atom positions gives a bent molecule.
Response criteria
- State a scientifically accurate conclusion.
- Show the calculation or mechanism that supports it.
- Include units, conditions, or limits where relevant.
Problem 25
Answer and explanation
No. Resonance drawings represent one delocalized bonding structure with equivalent bonds in the idealized ion.
Response criteria
- State a scientifically accurate conclusion.
- Show the calculation or mechanism that supports it.
- Include units, conditions, or limits where relevant.
Problem 26
Answer and explanation
Total valence electrons are 5+4(1)−1=8. Nitrogen formal charge is 5−0−4=+1 and each H is zero. The flat Lewis connectivity does not specify measured angles; the common molecular arrangement is tetrahedral.
Total valence electrons are 5+4(1)−1=8. Nitrogen formal charge is 5−0−4=+1 and each H is zero. The flat Lewis connectivity does not specify measured angles; the common molecular arrangement is tetrahedral.
Response criteria
- Use the stated measurements or conditions, with correct units.
- Connect the result to the chemical mechanism or evidence relationship.
- Identify the assumption, model limit or further evidence requested.