Bonding, Formulas & Molecular Structure — Chapter quiz · Physical Science: Chemistry, Grade 11
Build names, formulas, Lewis structures, and structure-property explanations.
Problem 1
- molecule
- isotope
- anion
- cation
Answer and explanation
cation
Losing electrons leaves more protons than electrons, giving a positive cation.
Problem 2
Answer and explanation
2
Each Cl⁻ is −1, so two are needed to balance the +2 of Mg²⁺, giving MgCl₂.
Problem 3
- conducts electricity as a solid
- high melting point and brittle
- made of discrete molecules
- a very low melting point
Answer and explanation
high melting point and brittle
Strong lattice-wide attractions give ionic compounds high melting points and make them hard but brittle.
Problem 4
Answer and explanation
5
Balancing charges gives Al₂O₃, so 2 aluminum + 3 oxygen = 5 atoms.
Problem 5
- share electrons
- form ions
- release protons
- transfer electrons
Answer and explanation
share electrons
Covalent bonding is the sharing of electron pairs between atoms.
Problem 6
Answer and explanation
4
A double bond is 2 shared pairs, and 2 pairs × 2 electrons = 4 electrons.
Problem 7
- neutrons
- delocalized valence electrons
- anions
- protons
Answer and explanation
delocalized valence electrons
Metallic bonding features valence electrons that are delocalized and free to move throughout the metal.
Problem 8
- brittleness
- luster
- malleability
- high density
Answer and explanation
malleability
Malleability comes from ion layers sliding without breaking, because the mobile electron sea keeps them bonded.
Problem 9
Answer and explanation
In solid NaCl the ions are locked in a rigid lattice and can't move, so there are no free charges; melting frees the ions to move, so molten NaCl conducts. In copper, a metal, the valence electrons are delocalized in an electron sea and are free to move even in the solid, so solid copper conducts.
Problem 10
- stay locked at 90° angles
- disappear once a bond forms
- attract one another
- repel and spread as far apart as possible
Answer and explanation
repel and spread as far apart as possible
Electron groups repel and spread out as far as possible, which fixes the molecule's shape.
Problem 11
- tetrahedral
- trigonal planar
- linear
- bent
Answer and explanation
tetrahedral
Four electron groups point to the corners of a tetrahedron, giving a tetrahedral shape (~109.5°).
Problem 12
- it has lone pairs on the carbon atom
- it has no electronegativity difference in its bonds
- its linear, symmetric shape makes the bond dipoles cancel
- it is actually an ionic compound
Answer and explanation
its linear, symmetric shape makes the bond dipoles cancel
The molecule is linear and symmetric, so its two equal bond dipoles point in opposite directions and cancel.
Problem 13
Answer and explanation
Ca²⁺ needs two Cl⁻ ions for neutrality; a 1:1 formula would carry +1 net charge. Ionic solids are extended lattices, not isolated little NaCl molecules.
Response criteria
- State a scientifically accurate conclusion.
- Show the calculation or mechanism that supports it.
- Include units, conditions, or limits where relevant.
Problem 14
Answer and explanation
The least common charge magnitude is 6: two Al³⁺ and three O²⁻ give +6−6=0, so Al₂O₃. The formula states a stoichiometric ratio in an extended solid, not a claim of isolated five-ion molecules.
The least common charge magnitude is 6: two Al³⁺ and three O²⁻ give +6−6=0, so Al₂O₃. The formula states a stoichiometric ratio in an extended solid, not a claim of isolated five-ion molecules.
Response criteria
- Use the stated measurements or conditions, with correct units.
- Connect the result to the chemical mechanism or evidence relationship.
- Identify the assumption, model limit or further evidence requested.
Problem 15
Answer and explanation
Three shared pairs give six bonding electrons, not three. Sharing need not be equal; polar covalent bonds share electron density unevenly.
Response criteria
- State a scientifically accurate conclusion.
- Show the calculation or mechanism that supports it.
- Include units, conditions, or limits where relevant.
Problem 16
Answer and explanation
CO₂ is linear with equal opposing bond contributions that cancel in the ideal symmetric molecule. H₂O is bent, so its bond dipoles do not cancel. Geometry and the full charge distribution matter.
CO₂ is linear with equal opposing bond contributions that cancel in the ideal symmetric molecule. H₂O is bent, so its bond dipoles do not cancel. Geometry and the full charge distribution matter.
Response criteria
- Use the stated measurements or conditions, with correct units.
- Connect the result to the chemical mechanism or evidence relationship.
- Identify the assumption, model limit or further evidence requested.
Problem 17
Answer and explanation
Copper has delocalized mobile electrons; salt’s ions are fixed in a lattice under ordinary conditions. Not all metals have the same melting point or strength; electron-sea pictures are simplified.
Response criteria
- State a scientifically accurate conclusion.
- Show the calculation or mechanism that supports it.
- Include units, conditions, or limits where relevant.
Problem 18
Answer and explanation
P satisfies both stated constraints. Q fails conduction and R fails strength. Cost, corrosion, fatigue, fabrication or service temperature could still change the decision.
P satisfies both stated constraints. Q fails conduction and R fails strength. Cost, corrosion, fatigue, fabrication or service temperature could still change the decision.
Response criteria
- Use the stated measurements or conditions, with correct units.
- Connect the result to the chemical mechanism or evidence relationship.
- Identify the assumption, model limit or further evidence requested.
Problem 19
Answer and explanation
CO₂ is linear with equal opposite bond dipoles that cancel; bent water has a nonzero molecular dipole. Polar bonds do not automatically make a polar molecule.
Response criteria
- State a scientifically accurate conclusion.
- Show the calculation or mechanism that supports it.
- Include units, conditions, or limits where relevant.
Problem 20
Answer and explanation
The electron-domain arrangement is approximately tetrahedral and the molecular shape is bent. Lone-pair interactions and the actual chemical species alter angles; 109.5° is an ideal tetrahedral reference rather than an exact universal bond angle.
The electron-domain arrangement is approximately tetrahedral and the molecular shape is bent. Lone-pair interactions and the actual chemical species alter angles; 109.5° is an ideal tetrahedral reference rather than an exact universal bond angle.
Response criteria
- Use the stated measurements or conditions, with correct units.
- Connect the result to the chemical mechanism or evidence relationship.
- Identify the assumption, model limit or further evidence requested.
Problem 21
Answer and explanation
(NH₄)₂SO₄: two +1 ammonium ions balance one −2 sulfate ion.
Response criteria
- State a scientifically accurate conclusion.
- Show the calculation or mechanism that supports it.
- Include units, conditions, or limits where relevant.
Problem 22
Answer and explanation
Each iron cation has charge +3, giving FeCl₃ with chloride ions.
Response criteria
- State a scientifically accurate conclusion.
- Show the calculation or mechanism that supports it.
- Include units, conditions, or limits where relevant.
Problem 23
Answer and explanation
Fe³⁺ and SO₄²⁻ require Fe₂(SO₄)₃: two Fe, three S and twelve O atoms. N₂O₃ is dinitrogen trioxide. The Roman numeral and prefixes serve different bookkeeping roles.
Fe³⁺ and SO₄²⁻ require Fe₂(SO₄)₃: two Fe, three S and twelve O atoms. N₂O₃ is dinitrogen trioxide. The Roman numeral and prefixes serve different bookkeeping roles.
Response criteria
- Use the stated measurements or conditions, with correct units.
- Connect the result to the chemical mechanism or evidence relationship.
- Identify the assumption, model limit or further evidence requested.
Problem 24
Hints
Write the relationship first; substitute with consistent units.
Answer and explanation
24 electrons
5+3×6+1 = 24.
Problem 25
Answer and explanation
The total follows elemental valence counts and ion charge; a drawing with extra electrons represents a different charge or invalid model.
Response criteria
- State a scientifically accurate conclusion.
- Show the calculation or mechanism that supports it.
- Include units, conditions, or limits where relevant.
Problem 26
Answer and explanation
Total valence electrons are 5+4(1)−1=8. Nitrogen formal charge is 5−0−4=+1 and each H is zero. The flat Lewis connectivity does not specify measured angles; the common molecular arrangement is tetrahedral.
Total valence electrons are 5+4(1)−1=8. Nitrogen formal charge is 5−0−4=+1 and each H is zero. The flat Lewis connectivity does not specify measured angles; the common molecular arrangement is tetrahedral.
Response criteria
- Use the stated measurements or conditions, with correct units.
- Connect the result to the chemical mechanism or evidence relationship.
- Identify the assumption, model limit or further evidence requested.