Percent Composition, Empirical & Molecular Formulas — Practice · Grade 11 Science
Chapter: Reactions, Moles & CompositionWhat this practice covers
By the end of Percent Composition, Empirical & Molecular Formulas you should be able to:
- I can convert mass composition to a simplest mole ratio.
- I can use molar mass to distinguish empirical and molecular formulas.
8 questions, numeric and written answer, each with a worked explanation.
Vocabulary used: empirical formula, molecular formula, percent composition.
Problem 1
Hints
Write the relationship first; substitute with consistent units.
Answer and explanation
27.27 %
12/44 ×100 = 27.27%.
Problem 2
Answer and explanation
Subscripts count atoms; convert mass to moles because elements have different atomic masses.
Response criteria
- State a scientifically accurate conclusion.
- Show the calculation or mechanism that supports it.
- Include units, conditions, or limits where relevant.
Problem 3
Hints
List the given quantities, select a relationship, and check units before substituting.
Answer and explanation
4
60/15=4.
Problem 4
Hints
Write the relationship first; substitute with consistent units.
Answer and explanation
2
92/46 = 2.
Problem 5
Hints
Percentages describe mass, so convert to moles before atom ratios.
Answer and explanation
90/30=3; multiply subscripts to get C₃H₆O₃.
Problem 6
Hints
State what the supplied observations or conditions establish, and separate that from any assumption.
Answer and explanation
Moles C=2, H=4; ratio 1:2, giving CH₂.
Problem 7
Answer and explanation
It preserves the measured proportional relationship, yielding 2:3; rounding one term changes the ratio.
An empirical ratio near 1:1.5 can support a 2:3 atom ratio after multiplying all terms by two. Premature rounding to 1:2 changes the composition substantially. Look for simple fractional relationships and compare the reconstructed percent composition with the original data and uncertainty. A complicated multiplier chosen only to force an answer can overfit noisy measurements. If several formulas fit within error, report that ambiguity and request more evidence rather than treating the nearest decimal as an exact atomic count.
It preserves the measured proportional relationship, yielding 2:3; rounding one term changes the ratio.
Response criteria
- Interpret labels, structures, axes, units and directions correctly.
- Explain the chemistry relationship or mechanism.
- Respect stated assumptions and distinguish observation from inference.
Problem 8
Answer and explanation
Amounts are 1.25 mol Fe and 1.875 mol O, ratio 1:1.5, hence Fe₂O₃. Assume the analyzed sample is one oxide accounted for by those elements and the input precision supports that ratio.
Amounts are 1.25 mol Fe and 1.875 mol O, ratio 1:1.5, hence Fe₂O₃. Assume the analyzed sample is one oxide accounted for by those elements and the input precision supports that ratio.
Response criteria
- Use the stated measurements or conditions, with correct units.
- Connect the result to the chemical mechanism or evidence relationship.
- Identify the assumption, model limit or further evidence requested.