Population Ecology — Print · Grade 12 Science

Chapter: Ecology, Populations & Biodiversity

Population Ecology

Learning goals

Readings for this unit

Before this unit

Rates, carrying capacity, and exponentials.

Use the detailed parent plan: two core 50–60-minute sessions per focused unit, with a third assigned for selected calculation/modeling topics. First study the core explanation and Parts 1–2 with their figures/checks; next study Parts 3–4, the whole-unit application, worked cases, varied practice and exit check. Attempt reasoning before opening guidance. Extend time when actual understanding requires it; investigations and chapter assessments have separate sessions.

Start with something to explain

Why can a population stop growing without every birth stopping?

Illustrative evidence case. Births and arrivals can balance deaths and departures near a conditional population level.

A population account needs species, place and timeA population account needs species, place and timeBirths /immigrationInputsPopulation NDefined boundaryDeaths /emigrationOutputsΔN=B+I−D−E over one stated intervalCounts and per-capita rates have different units.
Original population stock/flow account with no assumption that immigration is zero.

Notice and wonder

Record two observations using the stated quantities or relationships. Keep observations separate from possible causes. Write one question that a new measurement could help answer.

Why can a population stop growing without every birth stopping?

Your first model

Draw inputs/outputs and separate N from its growth rate.

Build the language from the idea

population
A group of individuals of the same species living in the same area, whose size changes with births, deaths, immigration, and emigration.
exponential growth
Growth at a constant per-capita rate when resources are unlimited, producing a J-shaped curve (dN/dt = rN).
logistic growth
Growth that slows as a population nears the limits of its environment, producing an S-shaped curve that levels off at carrying capacity.
carrying capacity (K)
The maximum population size an environment can sustain over the long term, given its resources and limiting factors.
limiting factor
A resource or condition that restricts population growth; density-dependent factors intensify with crowding, while density-independent factors act regardless of density.
survivorship curve
A graph of how many individuals of a cohort survive over their lifespan, classed as Type I, II, or III.

A population is a group of one species in one place, and its size is bookkeeping: it rises with births and immigration and falls with deaths and emigration. Ecologists summarize the balance with a per-capita growth rate, r. When r is positive the population grows, when it is negative it shrinks, and the beauty of the model is that the same small handful of numbers describes a colony of bacteria, a herd of deer, or the human species.

A population account needs species, place and timeA population account needs species, place and timeBirths /immigrationInputsPopulation NDefined boundaryDeaths /emigrationOutputsΔN=B+I−D−E over one stated intervalCounts and per-capita rates have different units.
Original population stock/flow account with no assumption that immigration is zero.

When resources are effectively unlimited, growth is exponential: each individual reproduces at the same rate, so the more individuals there are, the faster the total climbs, tracing a J-shaped curve that gets ever steeper. Written as a rate, dN/dt = rN. Bacteria in fresh nutrient broth, an invasive species arriving in a new land, and the recent explosion of the human population all show this runaway pattern. But no J-curve can last: multiply anything long enough and it collides with the finite limits of the real world.

Per-capita growth and total growth are different quantitiesPer-capita growth and total growth are different quantitiesPopulation model N0100200300400500012345Time (years)Continuous model: dN/dt=rN; r=0.30 yr⁻¹.
Calculated continuous exponential model, not an observed population trajectory.

The continuous logistic-growth model dN/dt=rN(1−N/K) reduces per-capita growth as N increases toward a fixed conditional carrying-capacity parameter K. It approaches K smoothly under its simple assumptions; overshoot, oscillations and collapse require changing conditions, delays or other model extensions. Real carrying capacity can change with resources and habitat. A measured population trajectory is not required to match one ideal S-curve, and K is not an eternal fixed biological maximum.

Carrying capacity is conditional and can changeCarrying capacity is conditional and can changeLogistic population model N02505007501000036912Time (years)K=1000 here is a fixed model parameter, not an eternal limit.
Calculated logistic curve with N₀=100,r=0.6 yr⁻¹,K=1000; not field observations.

What actually applies the brakes are limiting factors, and sorting them into two kinds is one of the most useful ideas in population ecology. *Density-dependent* factors bite harder as a population gets crowded — competition for food, predation, and the rapid spread of disease all intensify with density, so they naturally pull a population back toward K. *Density-independent* factors strike regardless of how many individuals are present: a hurricane, a hard freeze, a drought, or a wildfire can flatten a sparse population and a dense one alike. Real populations are shaped by both, which is why their numbers fluctuate rather than holding perfectly steady.

Species also differ in their whole life strategy, and survivorship curves make the differences visible by plotting how many of a cohort remain alive across the lifespan. *Type I* species (humans, elephants, other large mammals) invest heavily in a few offspring, so most survive to old age and mortality is late. *Type III* species (many fish, insects, oysters, plants) flood the environment with huge numbers of offspring and provide little care, so the vast majority die young while a lucky few survive. *Type II* species (many birds and small mammals) fall in between, facing a roughly constant risk of death at every age.

For the ideal fixed-parameter logistic model, maximum instantaneous total growth occurs at N=K/2. That mathematical result does not by itself establish a safe real harvest limit: variable recruitment, observation error, age structure, ecosystem effects and delayed management responses matter. Use the model as a conditional baseline, compare evidence and uncertainty, and avoid treating maximum modeled production as a guaranteed sustainable policy.

Model check: rN(1−N/K) is an instantaneous rate in the continuous model, not an exact finite-year population increase. dN/dt=.4×500×(1−.2)=160individuals/year at that moment; future N changes the rate.

Build your understanding

Use the detailed parent plan: two core 50–60-minute sessions per focused unit, with a third assigned for selected calculation/modeling topics. First study the core explanation and Parts 1–2 with their figures/checks; next study Parts 3–4, the whole-unit application, worked cases, varied practice and exit check. Attempt reasoning before opening guidance. Extend time when actual understanding requires it; investigations and chapter assessments have separate sessions.

Part 1 · Choose a population boundary and interval

A population is a defined set of organisms of the same species within a specified place and interval. Births and immigration add individuals; deaths and emigration remove them. A count difference alone does not reveal which flow changed. State whether a boundary is open to movement and whether records refer to adults, all ages or another defined group. Compare rates only after aligning the population and time definitions.

A population account needs species, place and timeA population account needs species, place and timeBirths /immigrationInputsPopulation NDefined boundaryDeaths /emigrationOutputsΔN=B+I−D−E over one stated intervalCounts and per-capita rates have different units.
Original population stock/flow account with no assumption that immigration is zero.

Read the visual model

Identify the labeled structures and units, then trace the arrows or compare values under the caption’s stated conditions. Separate the displayed evidence from a further inference. Write your reasoning before opening the guidance.

If births 20,immigration 5,deaths 8 and emigration 7 occur, what is ΔN?

Visual reasoning — after your attempt

ΔN=20+5−8−7=+10 individuals over the stated interval.

A population account needs species, area, and time interval. Change in number follows births plus immigration minus deaths and emigration. A larger count can reflect arrivals rather than reproduction, and density also depends on the area used as denominator.

Changing a survey boundary can change the count without an actual demographic event. Keep methods and mapped boundaries comparable.

Pause and explain

Why cannot two raw counts always be compared directly?

Check your reasoning after answering

They may use different boundaries, intervals, detection rates, or survey methods; these differences can mimic population change.

Part 2 · Distinguish per-capita growth from total change

In the continuous exponential-growth model, dN/dt=rN, where r is the net per-capita rate with inverse-time units. A fixed r gives a larger total growth rate when N is larger. The finite change after one year is N₀(e^r−1), not exactly rN₀ except as a small-interval approximation. State whether a problem uses a continuous differential model or a discrete per-step fraction before calculating.

Per-capita growth and total growth are different quantitiesPer-capita growth and total growth are different quantitiesPopulation model N0100200300400500012345Time (years)Continuous model: dN/dt=rN; r=0.30 yr⁻¹.
Calculated continuous exponential model, not an observed population trajectory.

Read the visual model

Identify the labeled structures and units, then trace the arrows or compare values under the caption’s stated conditions. Separate the displayed evidence from a further inference. Write your reasoning before opening the guidance.

At N=200 and r=0.30 yr⁻¹, what is the instantaneous modeled growth rate?

Visual reasoning — after your attempt

60 individuals per year at that instant; it is not the exact full-year increase if N changes continuously.

A total population change and a per-capita growth rate answer different questions. A simple exponential model assumes a constant per-capita rate and suitable conditions. Doubling time depends on that model; a short observed increase does not justify indefinite exponential projection.

A large population can add more individuals than a small population even at the same per-capita rate. State the denominator and time unit.

Pause and explain

Why is a larger numerical increase not automatically faster per-capita growth?

Check your reasoning after answering

The initial population size matters; compare change relative to population and time under compatible definitions.

Part 3 · Use carrying capacity as a changing model parameter

The logistic model uses dN/dt=rN(1−N/K), with K a carrying-capacity parameter under specified conditions. Growth slows as N approaches K in this fixed-parameter model. Real resources, habitat, climate, interactions and disturbance can change K, and delayed responses can produce overshoot or oscillations outside the simple curve. Maximum total logistic growth occurs at N=K/2 for fixed r,K; it is not the same as the highest per-capita growth rate.

Carrying capacity is conditional and can changeCarrying capacity is conditional and can changeLogistic population model N02505007501000036912Time (years)K=1000 here is a fixed model parameter, not an eternal limit.
Calculated logistic curve with N₀=100,r=0.6 yr⁻¹,K=1000; not field observations.

Read the visual model

Identify the labeled structures and units, then trace the arrows or compare values under the caption’s stated conditions. Separate the displayed evidence from a further inference. Write your reasoning before opening the guidance.

For r=0.4 yr⁻¹,K=1000 and N=500, find the instantaneous rate.

Visual reasoning — after your attempt

0.4×500×(1−0.5)=100 individuals/year.

An introductory logistic model limits growth through rN(1−N/K). Its K summarizes support under stated conditions and can change with resources, habitat, or interactions. The model is not a promise that every population approaches a perfectly stable number without delay or fluctuation.

At N=K, the ideal net growth term is zero. Real births, deaths, and movements can continue even when net change is zero.

Pause and explain

Does zero net growth mean no individuals are born or die?

Check your reasoning after answering

No. Opposing demographic flows can balance, so unchanged total number does not imply absent biological activity.

Part 4 · Interpret age structure and limits on inference

Age structure describes the distribution among age or life-stage groups. Many young individuals can support future growth if survival and reproductive conditions permit it, but fertility, mortality and migration also matter. A static age histogram cannot uniquely determine future size. Match age-group widths and definitions before comparing charts, and do not infer a causal policy or ecological conclusion from shape alone. Use explicit scenarios and uncertainty rather than a single inevitable prediction.

Age structure informs a forecast but does not determine it aloneAge structure informs a forecast but does not determine it aloneFraction of population (%)Pre-reproductive40Reproductive35Post-reproductive25Age structure suggests possibilities, not a unique forecast.
Illustrative equal-definition life-stage fractions, not a demographic projection for a named population.

Read the visual model

Identify the labeled structures and units, then trace the arrows or compare values under the caption’s stated conditions. Separate the displayed evidence from a further inference. Write your reasoning before opening the guidance.

What additional rates are needed to forecast from this snapshot?

Visual reasoning — after your attempt

Age-specific survival and reproduction, migration assumptions and the time interval, with uncertainty.

Age structure, survival, reproductive timing, and migration help explain future change. Density-dependent and density-independent effects can interact, and observed association does not alone identify the cause. Use repeated demographic and environmental records to test a proposed explanation.

A young age distribution may indicate future reproductive potential, but survival, fertility, and migration still affect what actually happens.

Pause and explain

What evidence distinguishes a demographic mechanism from a count artifact?

Check your reasoning after answering

Comparable surveys with detection assessment and separate birth, death, and movement records help test whether the measured change reflects the proposed mechanism.

Apply the whole unit · Combine a population budget and logistic estimate

Illustrative annual census starts at 120 individuals, with 20 births,12 deaths,5 arrivals, and 8 departures. A separate hypothetical closed-population model uses N=100, r=0.20/year, K=500.

Your task

Find the census end count and percentage net change. Calculate the separate logistic growth estimate and explain why it is not a prediction for the first census without matching assumptions.

What your response should show

  • Define the system, quantities, units, and relevant conditions before selecting a model.
  • Show intermediate calculations or a labeled evidence account, including signs or denominators.
  • Explain how the supplied evidence supports the conclusion rather than reporting only an answer.
  • Identify a meaningful uncertainty, model limit, or measurement needed to test the conclusion.
Response guidance — after your attempt
  1. Census change=20−12+5−8=+5; final count=125.

  2. Relative net change=5/120×100≈4.17% for that year.

  3. Separate logistic estimate=0.20×100×(1−100/500)=16 individuals/year.

The budget includes movement, while the supplied logistic model describes a different hypothetical population with its own parameters. The two results must not be combined as if they were observations and a validated model of the same site. Rates and carrying capacity require evidence before extrapolation.

Scientific references and source-model foundations

Parent / teacher teaching notes

Have students label observed demographic accounting separately from a model estimate. Correct any claim that a zero net change means zero births or deaths. Ask the learner to explain each symbol, axis, unit and arrow before calculating. Calculated examples, supplied illustrative records and actual historical observations are labeled separately. Selected public OpenSciEd middle-school source figures are foundation examples, not complete high-school editions or an endorsement; all advanced explanations are supplied locally.

KLogistic (S)Exponential (J)TimePopulation (N)Exponential growth races upward; logistic growth levels off at carrying capacity K
Calculated ideal exponential and fixed-K logistic comparisons. The curves are conditional models, not observations; real changing environments can depart from either.

The key idea

Exponential and logistic curves are conditional continuous models. Carrying capacity can change, and an instantaneous rate is not automatically a full-year population increase.

Exponential growth

dN/dt = rN

N is the population size and r is the per-capita growth rate; produces a J-shaped curve when resources are unlimited.

Logistic growth

dN/dt = rN((K - N)/K)

K is the carrying capacity; the (K - N)/K term shrinks toward 0 as N approaches K, slowing growth into an S-shaped curve.

Population growth rate

growth rate = (births - deaths) / N

the per-capita rate of change (also add immigration and subtract emigration when present); multiply by 100 to express it as a percent.

Rule of 70 (doubling time)

doubling time (years) ≈ 70 / (percent growth rate)

a quick estimate of how long a steadily growing population takes to double; e.g., a 2%/yr rate doubles in about 35 years.

Worked examples

Example 1

A rabbit population has N=200, r=0.5/year, and K=1000. Find the instantaneous logistic rate of change.
  1. Use dN/dt=rN(1−N/K).
  2. Substitute 0.5×200×(1−200/1000)=80.
  3. This is a rate at the stated population; it changes as population changes.
Answer: 80 individuals/year at that instant; not an exact integrated annual population increase.

Example 2 · Worked application

A population of 1000 has 80 births, 50 deaths, 30 immigrants and 40 emigrants in one year. Find growth and final size.
  1. ΔN=80−50+30−40=20.
  2. Final N=1020.
  3. Fractional change relative to initial size is 20/1000=0.02.
Answer: Growth 20; final size 1020; 2% annual change in this account.
Check the reasoning

Rates, net numbers and total population are different quantities.

Example 3

A town of 5,000 people records 150 births and 50 deaths in a year (ignore migration). Find the annual growth rate as a percent, then use the rule of 70 to estimate the doubling time.
  1. Net change = births - deaths = 150 - 50 = 100 people.
  2. Growth rate = 100/5,000 = 0.02 = 2% per year.
  3. Rule of 70: doubling time ≈ 70 ÷ (percent growth) = 70 ÷ 2 = 35 years.
Answer: A growth rate of about 2% per year, which doubles the population in roughly 35 years.

Example 4 · Find and fix the mistake

Context: A population of 1000 has 80 births, 50 deaths, 30 immigrants and 40 emigrants in one year. Find growth and final size. A student claims: “Exponential growth continues forever in every real environment.” Evaluate the claim and write a corrected explanation.
  1. Test the claim against the stated conditions: Rates, net numbers and total population are different quantities.
  2. Resources, density effects and changing conditions can limit or alter growth.
Answer: Resources, density effects and changing conditions can limit or alter growth.
Check the reasoning

Rates, net numbers and total population are different quantities.

Example 5 · Reason from the visual model

Carrying capacity is conditional and can changeCarrying capacity is conditional and can changeLogistic population model N02505007501000036912Time (years)K=1000 here is a fixed model parameter, not an eternal limit.
Calculated logistic curve with N₀=100,r=0.6 yr⁻¹,K=1000; not field observations.
For r=0.4 yr⁻¹,K=1000 and N=500, find the instantaneous rate.
  1. The logistic model uses dN/dt=rN(1−N/K), with K a carrying-capacity parameter under specified conditions. Growth slows as N approaches K in this fixed-parameter model. Real resources, habitat, climate, interactions and disturbance can change K, and delayed responses can produce overshoot or oscillations outside the simple curve. Maximum total logistic growth occurs at N=K/2 for fixed r,K; it is not the same as the highest per-capita growth rate.
  2. 0.4×500×(1−0.5)=100 individuals/year.
Answer: 0.4×500×(1−0.5)=100 individuals/year.
Check the reasoning

Calculated logistic curve with N₀=100,r=0.6 yr⁻¹,K=1000; not field observations.

Avoid these mistakes

Check your understanding

N=500,r=.4/year,K=2500. Find instantaneous growth rate.

Discuss the answer

dN/dt=.4×500×(1−.2)=160individuals/year at that moment; future N changes the rate.

Return to the phenomenon

Return to the initial case. Why can a population stop growing without every birth stopping? Revise your drawing or explanation using two named ideas and one stated limitation.

Compare explanations after your attempt

Net change can be zero while all flows continue; logistic K summarizes conditional constraints rather than a permanent universal maximum.

What should we investigate next?

Which comparison would test a remaining uncertainty? State what you would change, keep comparable and measure.

Investigate, calculate and revise

Keep a first model and an evidence-supported revision. Attempt each task before opening guidance; all required explanations and supplied-data routes are available locally.

Activity 1 · Return to the opening case

Assigned reading and preparation

Use the opening phenomenon, unit definitions and explained Parts 1–4.

Your task

Return to the initial case. Why can a population stop growing without every birth stopping? Revise your drawing or explanation using two named ideas and one stated limitation.

Success criteria

  • Use the stated observations and appropriate units.
  • Connect a labeled model with the physical/environmental mechanism.
  • State assumptions and an evidence limitation.
  • Explain a substantive revision or next test.
Hint

Keep object/material identity, material transfer and energy account distinct.

Response guidance — discuss after your attempt

Net change can be zero while all flows continue; logistic K summarizes conditional constraints rather than a permanent universal maximum.

Activity 2 · Transfer to a changed case

Assigned reading and preparation

Cover the worked answer and use the explained models, relationships and notebook.

Your task

For continuous logistic growth with r=0.5 yr⁻¹,K=800 and N=200, find dN/dt. Compare with N=400.

Success criteria

  • Use the stated measurements or conditions, with correct units.
  • Connect the result to the physical or environmental mechanism or evidence relationship.
  • Identify the assumption, model limit or further evidence requested.
Hint

Name known quantities and conditions, show intermediate steps and check conservation.

Response guidance — discuss after your attempt

At200:0.5×200×0.75=75 individuals/year. At400:0.5×400×0.5=100/year. Total growth rises even while per-capita growth falls.

Words to know

population
A group of individuals of the same species living in the same area, whose size changes with births, deaths, immigration, and emigration.
exponential growth
Growth at a constant per-capita rate when resources are unlimited, producing a J-shaped curve (dN/dt = rN).
logistic growth
Growth that slows as a population nears the limits of its environment, producing an S-shaped curve that levels off at carrying capacity.
carrying capacity (K)
The maximum population size an environment can sustain over the long term, given its resources and limiting factors.
limiting factor
A resource or condition that restricts population growth; density-dependent factors intensify with crowding, while density-independent factors act regardless of density.
survivorship curve
A graph of how many individuals of a cohort survive over their lifespan, classed as Type I, II, or III.

Live fast or live long: r- and K-selection

Ecologists describe two broad life strategies. r-selected species (many insects, weeds, bacteria) reproduce early and prolifically with little parental care; they thrive in unstable or empty habitats and show boom-and-bust, near-exponential growth — the Type III survivorship pattern. K-selected species (elephants, whales, humans, oak trees) produce few offspring, invest heavily in each, mature slowly, and live near carrying capacity with Type I survivorship. The labels are two ends of a continuum, but they neatly connect growth curves, survivorship, and reproductive strategy into one story.

The lynx and the hare: a century of coupled cycles

Some of the best long-term population data on Earth came from an unlikely source: the fur-trapping records of the Hudson's Bay Company, which logged snowshoe hare and Canada lynx pelts for nearly two centuries. The counts reveal a striking pattern — hare numbers rise and fall on a roughly 10-year cycle, and lynx numbers follow a step behind, a real-world example of coupled predator-prey cycles. More hares feed more lynx; more lynx then crash the hare population; fewer hares then starve the lynx, letting hares rebound. (The cycle is also driven partly by the hares' own food supply, showing that nature is rarely a clean two-species model.)

Does the human population have a carrying capacity?

For most of history human numbers crept along, then exploded into a textbook J-curve after the Industrial and Agricultural Revolutions, reaching 8 billion. Yet growth rates peaked in the 1960 s and have been falling since, as countries pass through the demographic transition from high birth-and-death rates to low ones. Demographers now project the curve bending toward an S-shape, leveling off later this century. Whether Earth's carrying capacity for humans is 9 billion or far more is fiercely debated — because, uniquely, humans can raise K with technology like fertilizer and irrigation, and lower it by degrading the very resources they depend on.

Overshoot and collapse on St. Matthew Island

Populations do not always glide gently to carrying capacity. In 1944, 29 reindeer were introduced to remote St. Matthew Island with abundant lichen and no predators. Freed of limits, the herd grew explosively to about 6,000 by 1963 — then, having stripped the slow-growing lichen bare, it crashed catastrophically to fewer than 50 animals in a single brutal winter. It is a stark real-world lesson that a population can overshoot its carrying capacity, degrade the resource base, and collapse far below where it started, rather than settling smoothly at K.

Why maximum sustainable yield sits near half of K

The logistic model has a practical payoff. Because the growth term rN((K - N)/K) is a downward parabola in N, a population adds the most new individuals per year when N is about K/2 — that is where the curve is steepest. Harvesting a fishery or forest down to roughly half its carrying capacity therefore lets it regrow fastest, defining the maximum sustainable yield. In practice, managers treat this as a ceiling, not a target: uncertainty in the data means aiming exactly at MSY has repeatedly tipped real fisheries, like the Atlantic cod, into collapse.

In the real world

Fisheries managers use logistic-growth models to set catch limits near a stock's maximum sustainable yield (around N = K/2, where the population grows fastest), harvesting enough to feed people while leaving the population able to rebuild.

Exit check

N=500,r=.4/year,K=2500. Find instantaneous growth rate.

Check your explanation after answering

dN/dt=.4×500×(1−.2)=160individuals/year at that moment; future N changes the rate.

Explain your reasoning without notes. If a key idea is missing, revisit the lesson and try again.

Problem 1

A population reproducing with unlimited resources, doubling again and again, produces which growth curve?
  1. An S-shaped logistic curve
  2. A flat horizontal line
  3. A bell-shaped curve
  4. A J-shaped exponential curve
Answer and explanation

A J-shaped exponential curve

Constant per-capita growth with no limits accelerates into a J-shaped exponential curve.

Problem 2

For N=200, r=0.5/year, and K=1000, find the instantaneous rate dN/dt=rN(1−N/K), in individuals/year.
Answer and explanation

80 rabbits/yr

(1,000 - 200)/1,000 = 0.8; 0.5 × 200 × 0.8 = 80. This is an instantaneous rate in the continuous model, not an exact finite-year increase.

Problem 3

A population of 4,000 has 240 births and 40 deaths in a year (ignore migration). What is the annual growth rate, as a percent?
Answer and explanation

5 %

Net change = 240 - 40 = 200; 200/4,000 = 0.05 = 5%.

Problem 4

Which of these is a density-DEPENDENT limiting factor?
  1. Disease spreading through a crowded population
  2. A volcanic eruption
  3. A hurricane that floods the habitat
  4. A sudden hard freeze
Answer and explanation

Disease spreading through a crowded population

Disease spreads faster as density rises, so it intensifies with crowding — a density-dependent factor. The others strike regardless of population size.

Problem 5

Explain why a population may temporarily overshoot its carrying capacity and then crash.
Answer and explanation

If a population grows rapidly, it can climb past K before limiting factors fully catch up. Once there are more individuals than the environment can support, resources run short and deaths spike, so the population crashes back down below K before stabilizing.

Problem 6

For dN/dt=rN with r=0.10/year and N=200, find instantaneous growth. Show the reasoning, not just the conclusion.
Hints

Rates, net numbers and total population are different quantities.

Answer and explanation

20 individuals/year in the exponential model.

Problem 7

In logistic growth, why does growth slow as N approaches K?
Hints

State what the supplied observations or conditions establish, and separate that from any assumption.

Answer and explanation

The model's factor 1−N/K reduces per-capita growth; real mechanisms and K can change with conditions.

Problem 8

Carrying capacity is conditional and can changeCarrying capacity is conditional and can changeLogistic population model N02505007501000036912Time (years)K=1000 here is a fixed model parameter, not an eternal limit.
Calculated logistic curve with N₀=100,r=0.6 yr⁻¹,K=1000; not field observations.
Interpret the supplied visual. For r=0.4 yr⁻¹,K=1000 and N=500, find the instantaneous rate.
Answer and explanation

0.4×500×(1−0.5)=100 individuals/year.

The logistic model uses dN/dt=rN(1−N/K), with K a carrying-capacity parameter under specified conditions. Growth slows as N approaches K in this fixed-parameter model. Real resources, habitat, climate, interactions and disturbance can change K, and delayed responses can produce overshoot or oscillations outside the simple curve. Maximum total logistic growth occurs at N=K/2 for fixed r,K; it is not the same as the highest per-capita growth rate.

0.4×500×(1−0.5)=100 individuals/year.

Response criteria

  • Interpret labels, structures, axes, units and directions correctly.
  • Explain the physical or environmental relationship or mechanism.
  • Respect stated assumptions and distinguish observation from inference.

Problem 9

For continuous logistic growth with r=0.5 yr⁻¹,K=800 and N=200, find dN/dt. Compare with N=400.
Answer and explanation

At200:0.5×200×0.75=75 individuals/year. At400:0.5×400×0.5=100/year. Total growth rises even while per-capita growth falls.

At200:0.5×200×0.75=75 individuals/year.

At400:0.5×400×0.5=100/year.

Total growth rises even while per-capita growth falls.

Response criteria

  • Use the stated measurements or conditions, with correct units.
  • Connect the result to the physical or environmental mechanism or evidence relationship.
  • Identify the assumption, model limit or further evidence requested.

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